急需解决四道七年级因式分解数学题,哪位可以帮帮忙!!!有十五分悬赏!!!
\u6025\u9700\u89e3\u51b3\u4e09\u9053\u4e03\u5e74\u7ea7\u56e0\u5f0f\u5206\u89e3\u6570\u5b66\u9898,\u54ea\u4f4d\u53ef\u4ee5\u5e2e\u5e2e\u5fd9!!!1\uff1a\u5341\u5b57\u76f8\u4e58\u6cd5
a^2+14ab+45b^2 = (a+5b)*(a+9b)
a^2-9ab+20b^2 = (a-5b)*(a-4b)
2:\u5341\u5b57\u76f8\u4e58\u6cd5+\u5e73\u65b9\u5dee\u516c\u5f0f
a^4-5a^2+4 =(a^2-1)*(a^2-4\uff09=\uff08a+1)*\uff08a-1)*(a+2)*(a-2)
3:\u63d0\u516c\u56e0\u5f0f\u6cd5+\u5341\u5b57\u76f8\u4e58\u6cd5
2a+4+3ab+6b = 2(a+2)+3b(a+2) = (a+2)*(2+3b)
\u5efa\u8bae\u4f60\u52a0\u5f3a\u5341\u5b57\u76f8\u4e58\u6cd5\u7684\u8bad\u7ec3 \u8fd9\u4e2a\u65b9\u6cd5\u5f88\u5e38\u7528
\u2479\u5341\u5b57\u76f8\u4e58\u6cd5
\u8fd9\u79cd\u65b9\u6cd5\u6709\u4e24\u79cd\u60c5\u51b5\u3002
\u2460x^2+(p+q)x+pq\u578b\u7684\u5f0f\u5b50\u7684\u56e0\u5f0f\u5206\u89e3
\u8fd9\u7c7b\u4e8c\u6b21\u4e09\u9879\u5f0f\u7684\u7279\u70b9\u662f\uff1a\u4e8c\u6b21\u9879\u7684\u7cfb\u6570\u662f1\uff1b\u5e38\u6570\u9879\u662f\u4e24\u4e2a\u6570\u7684\u79ef\uff1b\u4e00\u6b21\u9879\u7cfb\u6570\u662f\u5e38\u6570\u9879\u7684\u4e24\u4e2a\u56e0\u6570\u7684\u548c\u3002\u56e0\u6b64\uff0c\u53ef\u4ee5\u76f4\u63a5\u5c06\u67d0\u4e9b\u4e8c\u6b21\u9879\u7684\u7cfb\u6570\u662f1\u7684\u4e8c\u6b21\u4e09\u9879\u5f0f\u56e0\u5f0f\u5206\u89e3\uff1ax^2+(p+q)x+pq=(x+p)(x+q) \uff0e
\u2461kx^2+mx+n\u578b\u7684\u5f0f\u5b50\u7684\u56e0\u5f0f\u5206\u89e3
\u5982\u679c\u5982\u679c\u6709k=ac\uff0cn=bd\uff0c\u4e14\u6709ad+bc=m\u65f6\uff0c\u90a3\u4e48kx^2+mx+n=(ax+b)(cx+d)\uff0e
\u56fe\u793a\u5982\u4e0b\uff1a
\u00b7a b
\u00b7 \u00d7
\u00b7c d
\u4f8b\u5982\uff1a\u56e0\u4e3a
\u00b71 -3
\u00b7 \u00d7
\u00b77 2
\u4e142-21=-19\uff0c
\u6240\u4ee57x^2-19x-6=(7x+2)(x-3)\uff0e
(1-x^2)(1-y^2)+4xy
=1-x^2-y^2+x^2y^2+4xy
=(x^2y^2+2xy+1)-(x^2-2xy+y^2)
=(xy+1)^2-(x-y)^2
=(xy+x-y+1)(xy-x+y+1)
x^2-x-2y-4y^2
=(x^2-4y^2)-x-2y
=(x+2y)(x-2y)-(x+2y)
=(x+2y)(x-2y-1)
4x^2-4xy+y^2-44x+22y+40
=(2x-y)^2-22(2x-y)+121-81
=(2x-y-11)^2-9^2
=(2x-y-11+9)(2x-y-11-9)
=(2x-y-2)(2x-y-20)
x^3y^2-5x^2y^2-24xy^2
=xy^2(x^2-5x-24)
=xy^2(x-8)(x+3)
1.m的平方减n的平方＝（m＋n）×（m—n）＝9
分情况讨论：
1）m＋n＝3 m－n＝3 m＝3，n＝0（舍去）
2）m＋n＝－9 m－n＝－1 m＝－5 n＝－4
2.提取公因式xy的四次方得到xy的四次方乘以（x＋y
)=1的四次方×4＝4
3.提取公因式x(2-a)即得x(2-a)(1-x)
4.（七分之二y＋三分之一x）×（七分之二y－三分之一x）
1、 m=-5,n=-4
2、 4
3、 x(x-1)(a-2)
4、（2y/7+x/3）*(2y/7-x/3)
m=5,n=4
4
x(x-1)(a-2)
m=5,n=4
绛旓細(1-x^2)(1-y^2)+4xy =1-x^2-y^2+x^2y^2+4xy =(x^2y^2+2xy+1)-(x^2-2xy+y^2)=(xy+1)^2-(x-y)^2 =(xy+x-y+1)(xy-x+y+1)x^2-x-2y-4y^2 =(x^2-4y^2)-x-2y =(x+2y)(x-2y)-(x+2y)=(x+2y)(x-2y-1)4x^2-4xy+y^2-44x+22y+40 =(2x-y...
绛旓細(x^4+x^2-4)(x^4+x^2+3)+10 璁緓^4+x^2=y (y-4)(y+3)+10 =y^2+3y-4y-12+10 =y^2-y-2 =(y+1)(y-2)=(x^4+x^2+1)(x^4+x^2-2)=(x^4+x^2+1)(x^2-1)(x^2+2)=(x^4+x^2+1)(x+1)(x-1)(x^2+2)濡傝繕涓嶆槑鐧斤紝璇风户缁拷闂傚鏋滀綘璁ゅ彲鎴戠殑...
绛旓細瑙ｏ細
绛旓細1. (a - 8)^2 2. (2m + 1)^2 3.(3a - 4b)^2 4. -(m + 1/2)^2 5.(x^n - 1)^2
绛旓細5銆4鍒嗕箣1(x-5y)(x+5y)6銆(x+y-z)(x+y+z)7銆-(a-b)²8銆11 9銆(xy-1)²10銆3x³y-6x²y²+3xy³=3xy(x²-2xy+y²)=3xy(x-y)²11銆亁鐨勪簲娆℃柟y鐨勫洓娆℃柟+x鐨勫洓娆℃柟y鐨勪簲娆℃柟=x³y³(x+y)=(xy)³...
绛旓細棰1锛144锛坅+2b锛塣2-169(2a-b)^2 =[12(a+2b)+13(2a-b)][12(a+2b)-13(2a-b)]=(38a+11b)(-14a+37b)=-(38a+11b)(14a-37b)棰2锛氾紙x^2-2x锛塣2+2(x^2-2x)+1 =(x²-2x+1)²=(x-1)^4
绛旓細锛7a-8b)^2-4x^2 =(7a-8b+2x)(7a-8b-2x)X^2(x-4)+y^2(4-x)=(x^2-y^2)(x-4)=(x+y)(x-y)(x-4)a^4-81 =(a^2+9)(a^2-9)=(a^2+9)(a+3)(a-3)11(a-b)+11/1(b-a)^3 =11(a-b)[1-121/1(b-a)^2]=11(a-b)[1+11/1(b-a)][1-11/1(b-...
绛旓細4銆 鍗佸瓧鐩镐箻娉 瀵逛簬mx +px+q褰㈠紡鐨勫椤瑰紡锛屽鏋渁脳b=m,c脳d=q涓攁c+bd=p锛屽垯澶氶」寮忓彲鍥犲紡鍒嗚В涓(ax+d)(bx+c)渚4銆鍒嗚В鍥犲紡7x -19x-6 鍒嗘瀽锛 1 -3 7 2 2-21=-19 瑙ｏ細7x -19x-6=锛7x+2锛(x-3)5銆侀厤鏂规硶 瀵逛簬閭ｄ簺涓嶈兘鍒╃敤鍏紡娉曠殑澶氶」寮忥紝鏈夌殑鍙互鍒╃敤灏嗗叾閰嶆垚涓涓畬鍏...
绛旓細瑙ｏ細鍘熷紡=(2a+b-5)^2 锛堣繖閲屾槸灏2a+b鐪嬫垚鏄竴涓暣浣(鈯檕鈯)鍝︼級2. xy^2-8xy+16x 瑙ｏ細鍘熷紡=x(y^2-8y+16)=x(y-4)^2 3. 2x^2+2x+浜屽垎涔嬩竴 瑙ｏ細鍘熷紡=2锛坸^2+x+1/4)=2(x+1/2)^2 4. (x^2+9)^2-36x^2 瑙ｏ細鍘熷紡=(x^2+9-6x)(x^2+9+6x) ...
绛旓細3 6x^2+xy-y^2+2x+6y-8 绛旀锛(3x-y+4)(2x+y-2)4 4x^4+1 绛旀锛(2x^2+1+2x)(2x^2+1-2x)5 y^4-27y^2+1 绛旀锛(y^2+5x-1)(y^2-5y-1)6 y^3+5y+6 绛旀锛(y+1)(y^2-y+6)7 (x+1)(x+2)(x+3)(x+6)+x^2 绛旀锛(x^...
