因式分解x^2+3x+2
\u56e0\u5f0f\u5206\u89e3\uff1ax^3+3x^2+3x-26\u89e3\uff1ax^3+x^3+3x^2+3x-26
=\uff08x^3-4x^2+4x\uff09+\uff087x^2-x-26 \uff09
=x\uff08x-2\uff09^2+(7x+13)(x-2)
=(x-2)(x^2-2x+7x+13)
=(x-2)(x^2+5x+13)
x^2+3x
=x(x+3)
十字相乘法啊！
答案为(x+1)(x+2)
原式=（x+1）*（x+2）
满意请给分
不满意请忽略
原式=(x+1)(x+2)
(x+2)脳(x+1)
绛旓細鍘熷紡=x²+2x+x+2 =x(x+2)+(x+2)=(x+2)(x+1)
绛旓細x^2-3x+2=0 (x-1)(x-2)=0 x=1鎴杧=2 x^2+x-2=0 (x-1)(x+2)=0 x-1=0,x+2=0 x=1鎴杧=-2
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绛旓細x+1 x+2
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绛旓細x²+3x+2 =x²+x+2x+2 =x(x+1)+2(x+1锛=(x+1)(x+2)
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