c语言：任意输入一整数，编程输出其反序数 c语言：任意输入一整数，编程输出其反序数
C\u8bed\u8a00 \u4efb\u610f\u8bfb\u5165\u4e00\u4e2a\u6574\u6570\uff0c\u8f93\u51fa\u5176\u53cd\u5e8f\u6570\u3002\u4f8b\u5982\u8bfb\u5165 123 \uff0c\u53cd\u5e8f\u8f93\u51fa\u4e3a321
\u6bcf\u6b21\u966410\u53d6\u4f59\u6570\uff0c\u7136\u540e\u5c06\u7ed3\u679c\u62fc\u63a5\u5728\u4e00\u8d77\u3002
\u8bbe\u6c42\u5f97\u7684\u6700\u7ec8\u7ed3\u679c\u4e3as = 0 \u53e6a = 123
1)s = s *10 + a %10 = 3
a = a / 10 = 12
2) s = s*10 + a%10 = 3*10 + 2 = 32;
a = a / 10 = 1;
3) s = s*10 + a%10 = 32*10+1 = 321
a = a / 10 = 0;
\u53cd\u8f6c\u7ed3\u679c\u4e3a321
\u7a0b\u5e8f\u4e2dc\u8868\u793a\u7b26\u53f7\u4f4d\uff0c\u5982\u679c\u4e3a\u8d1f \u7528 c = - 1 \u6b63 c = 1
\u6700\u540e\uff0c\u7ed3\u679c\u4e58\u4ee5\u7b26\u53f7c \u5373\u53ef\u3002
#includemain(){int n,s=0;scanf("%d",&n);while(n){s*=10;s+=n%10;n/=10;}printf("%d",s);}\u60a8\u597d\uff0c\u5f88\u9ad8\u5174\u4e3a\u60a8\u89e3\u7b54\uff0c\u6d41\u661f\u4e0d\u6b7b\u4e3a\u60a8\u7b54\u7591\u89e3\u60d1
\u5982\u679c\u672c\u9898\u8fd8\u6709\u4e0d\u61c2\u7684\u5730\u65b9\u8bf7\u8ffd\u95ee\uff0c\u671b\u91c7\u7eb3\u6211\u7684\u56de\u7b54\u3002
\u795d\u697c\u4e3b\u5b66\u4e60\u8fdb\u6b65\u3002
\u4e0a\u9762\u7684\u4ee3\u7801\u53ef\u4ee5\u76f4\u63a5\u590d\u5236\u5230\u7f16\u8bd1\u5668\u91cc\uff0c\u5e26\u6362\u884c\u3002
#include<stdio.h>
void reverse(int n)
{printf("%d",n%10);
if(n>9)reverse(n/10);
}
int main()
{int n;
scanf("%d",&n);
reverse(n);
return 0;
}
用除法各位取整
再
使用一维数组
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绛旓細= EOF ) { if( a>0 && a<10 ){ printf("%d\n", a*10); }else if( a <= 20 ){ printf("%d\n", a); }else{ printf("%.3lf\n", double(a) / 10.0); } } return 0;}
