数学题初一下册整式的乘除,计算题一道 60道整式的乘除计算题 带答案
\u4e03\u4e0b\u6570\u5b66\u8ba1\u7b97\u9898\u6574\u5f0f\u7684\u4e58\u9664(1)7\uff08m³+\u33a1-m-1\uff09-2\uff08m³+m\uff09
绛旓細1銆 2锛坹+2锛2銆乤=1,b=-2 3銆 5
绛旓細鍥炵瓟锛1.1/9x²-9/16y²-( 1/9x²-1/2xy+9/16y² )=1/2xy
绛旓細1.(-ab-2)(-ab+2)=(-ab)^2-2^2 =a^2b^2-4 2.(a^2-0.1)(a^2+0.1);=a^4-0.01 3.(a+1/3b)^2;=a^2+2a/3b+1/9b 4.(2x+5)^2-(2x-5)^2 =(2x+5+2x-5)(2x+5-(2x-5))=4x *10 =40x
绛旓細1銆=2*x鐨2n-2娆″箓-x鐨2n-2娆″箓-x鐨2n-2娆″箓=02銆=[锛1/8锛夌殑4娆℃柟x4鐨5娆℃柟]=[锛4/8锛夌殑4娆℃柟x4]=1/4
绛旓細鍥炵瓟锛-8鍒嗕箣1鍙互鐪嬪仛-2鍒嗕箣1鐨3娆℃柟,閭d箞-8鍒嗕箣1鐨2013娆℃柟=-2鍒嗕箣1鐨6039娆℃柟,鐢变簬鏄熀鏁版鏂,鎵浠ヨ礋鍙蜂繚鐣,鎵浠ユ渶缁堢瓟妗=-1
绛旓細鈥鏁村紡鐨勪箻闄鈥濇槸鍒濅竴鐨勫ソ涓嶅ソ锛(a-b)2=a2-2ab+b2;(a+b)2=a2+2ab+b2;a2-b2=(a-b)(a+b);a3-b3=(a-b)锛坅2+ab+b2锛;a3+b3=(a+b)(a2-ab+b2);(a+b)3=a3+3a2b+3ab2+b3;an*am=a(n+m);an/am=a(n-m);(an)m=anm;a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-...
绛旓細鍒濅竴鏁板涓嬪鏈熸暣寮忕殑杩愮畻鐭ヨ瘑鐐 鏁村紡鐨勮繍绠楁槸鍒濅竴涓嬪鏈熷涔犵殑绗竴绔犲唴瀹癸紝涓昏璁茶В浜嗘暣寮忕殑姒傚康銆佸悓搴曟暟骞傜殑涔樻硶銆佸悓搴曟暟骞傜殑闄ゆ硶銆鏁村紡鐨勪箻闄娉曘佸钩鏂瑰樊鍏紡銆佸畬鍏ㄥ钩鏂瑰叕寮忕瓑銆備互涓嬫槸鎴戞暣鐞嗙殑鍏充簬鍒濅竴鏁板涓嬪鏈熸暣寮忕殑杩愮畻鐭ヨ瘑鐐癸紝甯屾湜澶у璁ょ湡闃呰!涓銆佹暣寮 鍗曢」寮忓拰澶氶」寮忕粺绉版暣寮忋俛)鐢辨暟涓庡瓧姣嶇殑绉...
绛旓細鍥涙湀浠界◢寰环鏍硷細a(1-20%锛=4a/5 鍥涙湀浠界殑閿閲2b 鍥涙湀浠界殑钀ヤ笟棰濓細8ab/5 (4a/5脳2b锛変笁鏈堜唤鐨勮惀涓氶锛歛b 鍥涙湀浠芥瘮涓夋湀浠藉鍔犱簡锛屽鍔犱簡锛8ab/5-ab锛壝穉b=60
绛旓細鍥炵瓟锛氱浜岄亾: 浠=0,鏈-9=-3A-B 浠=2,鏈-105=7A-B 鑱旂珛杩欎袱涓柟绋,寰桝=-48/5,B=189/5
绛旓細鍥炵瓟锛=-p2路p4路(-p15) =p21