高一化学计算题！麻烦了，很急的 高一化学计算题，很急的啊啊啊~~~
\u9ad8\u4e00\u5316\u5b66\u9898\uff0c\u5e94\u8be5\u4e0d\u7b97\u592a\u96be\uff0c\u6025\u7b49\u7740\u7528\uff0c\u6211\u7684\u4efd\u4e5f\u5c31\u8fd9\u4e48\u591a\u4e86\uff0c\u9ebb\u70e6\u4e86\u9178\u76d0R(NO3)2\u53d7\u70ed\u5206\u89e3\u4e3aRO\u3001NO2\u548cO2\u7684\u65b9\u7a0b\u5f0f\u4e3a
2R(NO3)2===2RO + 4NO2 + O2
\u8bbe\u70e7\u74f6\u7684\u4f53\u79ef\u4e3aV\uff0c\u5219 NO2\u548cO2\u7684\u4f53\u79ef\u5206\u522b\u4e3a
4/5V\u548c1/5V
\u7531\u65b9\u7a0b4NO2+O2+2H2O=4HNO3\u5f97NO2\u548cO2\u6070\u597d\u5b8c\u5168\u53cd\u5e94\u751f\u6210HNO3\uff0c\u5373\u4e3a\u6eb6\u8d28
n(HNO3)=n(NO2)=0.8V/22.4
\u5c06\u70e7\u74f6\u5012\u7f6e\u4e8e\u6c34\u4e2d\u540e\uff0c\u6c34\u5145\u6ee1\u6574\u4e2a\u70e7\u74f6\uff0c\u5373\u6eb6\u6db2\u7684\u4f53\u79ef\u4e3aV
\u5219\u70e7\u74f6\u4e2d\u6eb6\u8d28\u7684\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u4e3a
0.8V/22.4\u00f7V = 0.8/22.4 = 1/28
\u9009B
\u7b2c\u4e00\u95ee\u4f60\u5e94\u8be5\u77e5\u9053\u5427\uff0c
\u7b2c\u4e8c\u95ee\u5c31\u662f\uff1a\u5148\u5224\u65ad\u6709\u591a\u5c11\u7684\u6d53\u76d0\u9178\u88ab\u6c27\u5316\uff0c\u6c27\u5316\u5c31\u662f\u5316\u5408\u4ef7\u4e0a\u5347\uff0c\u5982\u751f\u6210\u7269\u4e2d\u67095\u4e2aCl2\uff0c\u90a3\u4e48\u5c31\u670910\u4e2aCl\u88ab\u6c27\u5316\u4e86\uff0c\u63a5\u4e0b\u6765\u6b65\u9aa4\u5c31\u72b9\u5982\u7b2c\u4e00\u95ee\u4e86\u3002
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（2）（73+492*1）/1.13=500mL 盐酸的物质的量浓度=2/500=0.004mol/mL=4mol/L
（3）4*0.02=0.08mol 则稀释后体积为0.08/1=0.08L=80mL
望采纳 方法对 计算过程也对 就是计算器有没按错 不知道。。
HCl的物质的量=44.8/22.4=2mol
HCl的质量=2*36.5=73克
溶液的质量=492*1+73=565克
溶液的体积=565/1.13=500ml=0.5L
(1)质量分数=73/565=12.9%
(2)物质的量浓度=2/0.5=4mol/L
(3)稀释后溶液的体积=20*4/1=80ml.
1)n(HCl)=44.8L/22.4L/mol =2mol
m(HCl)=2mol*36.5g/mol =73g
HCl的质量分数： 73g/（73g+492g）=19.8%
2)c=1000*密度*质量分数/M =1000*1.13*19.8/36.5 =4.0mol/L
3)V稀= C浓V浓/C稀== 4mol/L*0.02L /1mol/L =0.08L =80ml
（1）44.8/22.4=2mol 2molX36.5g/mol=73g 73/73+492=12.92%
(2)1000X12.92%X1.13/36.5=4.0mol/L
(3)C1V1==C2V2==>4.0X20.0=1.00XV2==>V2=80.0mL
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