SQL语句的问题,关于SELECT 一个关于SQL中select语句的问题

\u5173\u4e8eSQL\u8bed\u53e5\u7684\u95ee\u9898\uff0cselect\u8bed\u53e5\u3002

\u8fd9\u6837\u5c31\u7ed9\u4e2a\u8868\u5f88\u96be\uff0c\u4f60\u77e5\u9053\u90a3\u4e2a\u8868\u8ddf\u90a3\u4e2a\u8868\u5173\u8054\uff0c\u7136\u540e\u7528\u5173\u8054\u67e5\u8be2\u5c31OK\u4e86

Select min(\u4e00\u4e2a\u5b57\u6bb5) from \u8868
min(\u4e00\u4e2a\u5b57\u6bb5) \u53d6\u6700\u5c0f\u503c

\u5982\u679c\u4f60\u60f3\u53d6\u6700\u5927\u503c\u5c31\u7528 max(\u4e00\u4e2a\u5b57\u6bb5),\u8fd8\u53ef\u4ee5\u53d6\u548c\u503c sum(\u4e00\u4e2a\u5b57\u6bb5)
\u5982\u679c\u4f60\u7528\u7684\u662fsql server\u6570\u636e\u5e93\uff0c\u4e0b\u9762\u8fd9\u4e2a\u65b9\u6cd5\u4e5f\u53ef\u4ee5\uff1a
Select TOP 1 \u4e00\u4e2a\u5b57\u6bb5 from \u8868 order by \u4e00\u4e2a\u5b57\u6bb5 asc

to kutengshu:
Select TOP 1 \u4e00\u4e2a\u5b57\u6bb5 from \u8868 where (\u4f60\u7684\u6761\u4ef6) order by \u4e00\u4e2a\u5b57\u6bb5 asc

假设你的表名为test,其中搜索的字段为text,表内容如下:

text
——————
about
out
where
this
come
isit
comeisit
isitko
kois

示例代码如下:

declare @a varchar(20),@b varchar(20),@c varchar(20) /*三个搜索条件*/

set @a = 'is'
set @b = 'it'
set @c = 'ko'

select *,IDENTITY(int,1,1) as id into #Temp from
(
select *,1 as lv from test where text like '%'+@a+'%' and text like '%'+@b+'%' and text like '%'+@c+'%'
union select *,2 as lv from test where (text like '%'+@a+'%' and text like '%'+@b+'%') or (text like '%'+@a+'%' and text like '%'+@c+'%') or (text like '%'+@b+'%' and text like '%'+@c+'%')
union select *,3 as lv from test where text like '%'+@a+'%' or text like '%'+@b+'%'or text like '%'+@c+'%'
) as tmp order by lv

select text from #Temp t1 where
id=(select min(id) from #Temp t2 where t1.text = t2.text) order by id

drop table #Temp

列出结果如下:

text
----------
isitko
comeisit
isit
kois
this

这样就满足了你的需求:满足更多条件的排序更靠上。

用包含就行了select * from 表 where xxx='%x%' and xxx='%y%'.....

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