java中怎么把一个字符串中数字和字符分别提取出，例如字符串12+3，要提取成12,3，+，并且打印出来。 编写一个java方法，使得字符串1,2,3,4...11,1...
\u5982\u4f55\u7528java\u8bfb\u53d6\u4e00\u4e32\u5b57\u7b26\u4e32\u4e2d\u62ec\u53f7\u5185\u7684\u6570\u636e\uff1f\u5982String=\u201c2012\u5e74\u201c\u5317\u4eac\u201d\u4f60\u597d\uff0812,34\uff09\u548c\uff083,2\uff09\u7528\u5b57\u7b26\u4e32\u7684split\u65b9\u6cd5\u5206\u5272\u5b57\u7b26\u4e32\u6210\u6570\u7ec4\u3002\u6bd4\u5982string.split("("); \u5bf9\u6570\u7ec4\u4ece1\u8d77\u518d\u7528subString(0,\u6570\u7ec4[i].indexOf(")"); \u65b9\u6cd5\u6570\u636e\u5c31\u51fa\u6765\u4e86\u3002
\u8fd9\u4e2a\u65b9\u6cd5\u6709\u5f88\u591a\uff0c\u5199\u4e24\u79cd\u4f60\u770b\u770b\u3002
\u65b9\u6cd5\u4e00\uff1a
public class Num {
public static void main(String[] args){
String str1="1,2,3";
String ret="'"+str1.replace(",", "','")+"'";
System.out.println(ret);
}
}
\u65b9\u6cd5\u4e8c\uff1a
public class Num {
public static void main(String[] args){
String str1="1,2,3";
String[] str2=str1.split(",");
String ret="";
for(String i : str2){
ret+="'"+i+"',";
}
System.out.println(ret);//\u6700\u540e\u6709\uff0c
System.out.println(ret.substring(0, ret.length()-1));//\u6700\u540e\u6ca1\u6709\uff0c
}
}
参考http://www.blogjava.net/Javaphua/archive/2007/06/05/122131.html
1.java自带函数
for (int i = str.length();--i>=0;){
if (!Character.isDigit(str.charAt(i))){
这里将非数字提取
}else{
这里将数字提取
}
}
2用正则表达式，不过这个是判断整个字符串的。你把字符串分割了再循环调用
public static boolean isNumeric(String str){
Pattern pattern = Pattern.compile("[0-9]*");
return pattern.matcher(str).matches();
}
3用ascii码，这个最简单了，小雨0或者大于9的asscii码就肯定不是数字
public static boolean isNumeric(String str){
for(int i=str.length();--i>=0;){
int chr=str.charAt(i);
if(chr<48 || chr>57)
return false;
}
return true;
}
public class Test {
public static void main(String[] args) {
Pattern p=Pattern.compile(\\d+);
Matcher matcher=p.matcher("12+3");
while(matcher.find()) {
System.out.println(matcher.group());
}
}
}
根据它们的ascii码区分,用正则表达式会简单点：
String input="12+3";
String regExp="\\D";//非数字的正则表达式
String [] nums=input.split(regExp);//取得数字
System.out.println(Arrays.asList(nums));
//取得非数字
Pattern p = Pattern.compile(regExp);
Matcher m = p.matcher(input);
while(m.find()){
System.out.println(m.group());
}
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