编程，输入一个3*4整数矩阵并求出各行元素之和及各列元素之和 在C语言中,编写程序,求下列矩阵各行元素之和及各列元素之和
\u7528C\u8bed\u8a00\u7f16\u7a0b\uff0c\u8f93\u5165\u4e00\u4e2a3*4\u6574\u6570\u77e9\u9635\u5e76\u4e14\u6c42\u5404\u884c\u5143\u7d20\u4e4b\u548c\u548c\u5404\u5217\u5143\u7d20\u4e4b\u548c1.
#include
int main()
{
int a[3][4]={0};
int i,j,max,max_i,max_j;
printf("Please input a 3X4 matrix:\n");
for(i=0;i<3;i++)
for(j=0;j<4;j++)
scanf("%d",&a[i][j]);
max=a[0][0];
max_i=max_j=0;
for(i=0;i<3;i++)
for(j=0;j<4;j++)
if(a[i][j]>max)
{
max=a[i][j];
max_i=i;
max_j=j;
}
printf("The max is %d,row %,col %d\n",max,max_i,max_j);
}
2.
#include
int main()
{
char a[100]={0};
int i,count=0;
printf("Please input a string:");
gets(a);
for(i=0;a[i]!='\0';i++)
if(a[i]==' ')
count++;
printf("The string contents %d space\n",count);
}
\u8003\u8651\u5230\u8fd9\u9053\u9898\u7684\u6027\u8d28\uff0c\u7528\u4e00\u7ef4\u6570\u7ec4\u8fd0\u7b97\u901f\u5ea6\u66f4\u5feb\uff08\u539f\u7406\u5c31\u4e0d\u8bf4\u4e86\uff0c\u8981\u60f3\u95ee\u518d\u7559\u8a00\uff09
int arry1[5]={1,3,5,7,9};
int arry2[5]={2,4,6,8,10};
int arry3[5]={3,5,8,7,6};
int sum_row[3]={0*3};/*\u4e00\u884c\u5143\u7d20\u4e4b\u548c*/
int sum_column[5]={0*8};/*\u4e00\u5217\u5143\u7d20\u4e4b\u548c*/
for(int i=0;i<5;i++)
{
sum_row[0]+=arry1[i];
sum_row[1]+=arry2[i];
sum_row[2]+=arry3[i];
sum_column[i]=arry1[i]+arry2[i]+arry2[i];
printf("\u7b2c%d\u5217\u548c\u4e3a%d",i,sum_column[i]);
}
for(int i=0;i<3;i++)
{
printf("\u7b2c%d\u884c\u548c\u4e3a%d",i,sum_row[i]);
}
#include<stdio.h>
int main()
{
int i,j,a[4][5]={1,2,3,4,0,5,6,7,8,0,9,10,11,12};
for(i=0;i<3;i++)
for(j=0;j<4;j++)
{
a[i][4]+=a[i][j];
a[3][j]+=a[i][j];
}
for(i=0;i<4;i++)
{
for(j=0;j<5;j++)
{
if(i==3&&j==4)break;
if(j<4)printf("%4d",a[i][j]);
else printf("%6d",a[i][j]);
}
printf("
");
if(i==2)printf("
");
}
}
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