用C语言写一个函数,给出年月日,计算该日是该年的第几天 用#include<iostream,h>开头的 C语言程序设计:给出年、月、日,计算该日是该年的第几天。

\u7528c\u8bed\u8a00\u7f16\u5199\uff1a\u7ed9\u51fa\u5e74\u3001\u6708\u3001\u65e5\uff0c\u8ba1\u7b97\u8be5\u65e5\u662f\u8be5\u5e74\u7684\u7b2c\u51e0\u5929\u3002

#include
int main()
{
int n,y,r,t,i;
int a[12];
a[1]=31; a[2]=28; a[3]=31;
a[4]=30; a[5]=31; a[6]=30;
a[7]=31; a[8]=31; a[9]=30;
a[10]=31;a[11]=30;a[12]=31;
while (scanf("%d %d %d",&n,&y,&r)!=EOF)
{
t=0;
if((n%4==0 && n%100!=0)||(n%400==0)) a[2]=29; else a[2]=28;
for (i=1;i<y;i++)
t+=a[i];
t+=r;
printf("%d\n",t);
}
}

#include "stdio.h"

int main () {
int year;
int month;
int day;

scanf("%d %d %d", &year, &month, &day);
if(year 12) || (day 31))return -1;

int daynum[12] = {
31, 28, 31,30 ,31, 30, 31, 31, 30, 31, 30, 31
};

if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
daynum[1] = 29;
}

int dayth = 0;
for (int i = 0; i < month - 1; ++i) {
dayth += daynum[i];
}
dayth += day;
printf("the day is:%d\n", dayth);
return 0;
}

代码如下:

#include <iostream>
using namespace std;
int leap_year(int n)
{
    if(n%400==0||(n%4==0 && n%100!=0))
        return 1;
    else
        return 0;
}
int main()
{
    int year,month,day;
    int dayCount=0,i;
    int mon[]={31,28,31,30,31,30,31,31,30,31,30,31};
    cout<<"请输入当前的年,月,日: ";
cin>>year>>month>>day;
    for(i=0;i<month-1;i++)
        dayCount+=mon[i];
    if(month>2)
        dayCount+=day+leap_year(year);
    else
        dayCount+=day;
    cout<<"该日是该年的第几天: "<<dayCount<<endl;
    return 0;
}


#include<iostream>
using namespace std;
int main()
{
int year,month,day;
int i,j;
int mon[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
cout<<"请输入‘年 月 日’:";
cin>>year>>month>>day;
if(year%4==0&&(year%400==0||year%100!=0))//闰年
mon[2]=29;
if(month<1||day<1||month>12||mon[month]<day)
cout<<"日期格式非法!"<<endl;
else{
for(i=1,j=0;i<month;i++)
j += mon[i];
cout<<"这是当年的第 "<<j+day<<" 天!"<<endl;
}

return 0;
}

注意输入年月日中间要用空格。



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