用c语言编写程序,判断两个自然数是否为“自然对数”,所谓自然对数,指两个自然数的和或差都是平方数例 编写一个程序判断两个数是否是自然对数并用主函数调用它

\u7f16\u5199\u51fd\u6570\uff0c\u5224\u65ad\u4e24\u4e2a\u81ea\u7136\u6570\u662f\u5426\u4e3a\u81ea\u7136\u5bf9\u6570\uff0c\u4e3b\u51fd\u6570\u4e2d\u8f93\u51fa100\u4ee5\u5185\u7684\u6240\u6709\u81ea\u7136\u5bf9\u6570

#includeintfun(intn)/*\u51fd\u6570\u7528\u6765\u5224\u65ad\u4e00\u4e2a\u6570\u662f\u5426\u662f\u5b8c\u5168\u6570.\u662f\u5c31\u8fd4\u56de1.\u4e0d\u662f\u8fd4\u56de0*/{inti,sum=0;for(i=1;i

\u697c\u4e3b\u4f60\u597d\uff0c\u8fd9\u662f\u6e90\u7a0b\u5e8f\uff0c\u662f\u7528\u8f97\u8f6c\u76f8\u9664\u6cd5\u5199\u7684 #include int max(int p_a,int p_b) { if(p_b==0) return p_a; else return max(p_b,p_a%p_b); } void main() { int a,b; printf("Input two numbers:\n"); scanf("%d %d",&a,&b); if(b

#include<stdio.h>
main()
{
int i,j,A,B,s=0;
for(i=001;i<=14;i+=1)
for(j=i+2;j<=14;j+=2)
{ A=(j*j+i*i)/2;
if(A>100)continue;
B=j*j-A;
s+=i*i;
printf("%d,%d\t",A,B);/*输出自然数对*/
}
printf("sum=%d\n",s);/*输出自然数对之和509*/
getch();
}

5RMB可以代劳

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