python输入一行字符串,调用wordsearch(),返回指定字符串中长度为5的单词？ 用Python设计一个函数，该函数接受一个字符串，其功能是返...
C\u8bed\u8a00\u627e\u51fa\u6700\u957f\u7684\u5b57\u7b26\u4e32\u3002\u8f93\u51655\u4e2a\u5b57\u7b26\u4e32\uff0c\u8f93\u5165\u5176\u4e2d\u6700\u957f\u7684\u5b57\u7b26\u4e32\u3002#include
#include
int main()
{
int i = 0;
char s[80] = {""}, max[80] = {""};
printf("\u8f93\u5165\u4e94\u4e2a\u5b57\u7b26\u4e32:\n");
scanf("%s",s);
strcpy(max,s);
for(i=1; i<5; i++)
{
scanf("%s",s);
if( strcmp(max,s)<0 )
strcpy(max,s);
}
printf("\u6700\u5927\u7684\u5b57\u7b26\u4e32\u662f:%s \n",max);
return 0;
}
\u6269\u5c55\u8d44\u6599\uff1aprintf\u51fd\u6570\u4f7f\u7528\u6ce8\u610f\u4e8b\u9879
1\u3001\u57df\u5bbd
%d\uff1a\u6309\u6574\u578b\u6570\u636e\u7684\u5b9e\u9645\u957f\u5ea6\u8f93\u51fa\u3002
\u5982\u679c\u60f3\u8f93\u51fa\u6307\u5b9a\u5bbd\u5ea6\u53ef\u4ee5\u6307\u5b9a\u57df\u5bbd\uff0c%md-->m\u57df\u5bbd,\u6253\u5370\u51fa\u6765\u4ee5\u540e\uff0c\u5728\u63a7\u5236\u53f0\u4e0a\uff0c\u663e\u793am\u4f4d\uff1b
\u5982\u679c\u8981\u6253\u5370\u7684\u6570\u7684\u4f4d\u6570\u5982\u679c\u8d85\u8fc7\u6211\u4eec\u8bbe\u5b9am\u5219\u539f\u6837\u8f93\u51fa\uff1b
\u5982\u679c\u8981\u6253\u5370\u7684\u6570\u7684\u4f4d\u6570\u5982\u679c\u5c0f\u4e8e\u8bbe\u5b9a\u7684\u4f4d\u6570\uff0c\u5219\u8865\u7a7a\u767d\uff0c\u5177\u4f53\u5982\u4e0b:
\u5982\u679cm\u4e3a\u6b63\u6570\uff0c\u5219\u5de6\u5bf9\u9f50(\u5de6\u4fa7\u8865\u7a7a\u767d)\uff1b
\u5982\u679cm\u4e3a\u8d1f\u6570\uff0c\u5219\u53f3\u5bf9\u9f50(\u53f3\u4fa7\u8865\u7a7a\u767d)\u3002
2\u3001\u8f6c\u4e49\u5b57\u7b26
\u5982\u679c\u60f3\u8f93\u51fa\u5b57\u7b26"%"\uff0c\u5219\u5e94\u8be5\u5728\u201c\u683c\u5f0f\u63a7\u5236\u201d\u5b57\u7b26\u4e32\u4e2d\u7528\u8fde\u7eed\u4e24\u4e2a%\u8868\u793a\u3002
\u5982\uff1aprintf("%f%%",1.0/3)\uff1b\u8f93\u51fa\u7ed3\u679c\uff1a0.333333%\u3002
def lastwordlen(txt): import re return len(re.findall(r'[A-Za-z\']+',txt)[-1])
题主你好,
代码及测试截图如下:
希望可以帮到题主, 欢迎追问
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