python中如何删除指定位置前的字符 比如 21-2 删除-前面的所有字符? python删除某一行字符前面的内容

python\u5982\u4f55\u5220\u9664\u5b57\u7b26\u4e32\u4e2d\u6307\u5b9a\u4f4d\u7f6e\u7684\u5b57\u7b26\uff1f

#!/bin/env pythonimport shutil, sys, osdarray = [ "Entering directory", "In function ", "Leaving directory", "__NR_SYSCALL_BASE", "arm-hisiv100-linux-ar ", "arm-hisiv100-linux-gcc ", "but argument is of type", "dereferencing type-punned pointer will break strict-aliasing rules", "differ in signedness", "does break strict-aliasing rules", "embedded '\\0' in format", "excess elements in array initializer", "implicit declaration of", "make -C ", " rm -f", "this is the location of the previous definition", "warning: multi-line comment"]def isInArray (array, line): for item in array: if item in line: return True return Falseif __name__ == '__main__': argv = sys.argv argc = len(argv) if argc " %(os.path.basename(argv[0])) exit() fname = argv[1] fresult = fname + ".result" with open(fname, 'r') as f: with open(fresult, 'w') as g: for line in f.readlines(): if not isInArray(darray, line): g.write(line)\u5173\u4e8ePython\u76f8\u5173\u5185\u5bb9\u611f\u5174\u8da3\u7684\u8bfb\u8005\u53ef\u67e5\u770b\u672c\u7ad9\u4e13\u9898\uff1a\u300aPython\u6587\u4ef6\u4e0e\u76ee\u5f55\u64cd\u4f5c\u6280\u5de7\u6c47\u603b\u300b\u3001\u300aPython\u6587\u672c\u6587\u4ef6\u64cd\u4f5c\u6280\u5de7\u6c47\u603b\u300b\u3001\u300aPython URL\u64cd\u4f5c\u6280\u5de7\u603b\u7ed3\u300b\u3001\u300aPython\u56fe\u7247\u64cd\u4f5c\u6280\u5de7\u603b\u7ed3\u300b\u3001\u300aPython\u6570\u636e\u7ed3\u6784\u4e0e\u7b97\u6cd5\u6559\u7a0b\u300b\u3001\u300aPython Socket\u7f16\u7a0b\u6280\u5de7\u603b\u7ed3\u300b\u3001\u300aPython\u51fd\u6570\u4f7f\u7528\u6280\u5de7\u603b\u7ed3\u300b\u3001\u300aPython\u5b57\u7b26\u4e32\u64cd\u4f5c\u6280\u5de7\u6c47\u603b\u300b\u53ca\u300aPython\u5165\u95e8\u4e0e\u8fdb\u9636\u7ecf\u5178\u6559\u7a0b\u300b

import re
a='''Aug 24 2018 10:29:59 SRM_ENTITY 4 CARDINVALIDRESUI4E:OID 1.3.6.1.4.1.2011.5.25.219.2.3.6 The card recovered from total failure.
Aug 24 2018 10:30:00 IFNET 1 IF_LINKDOWN:OID 1.3.6.1.6.3.1.1.5.3 Interface 7 turned into DOWN state.
Aug 24 2018 10:30:00 IFNET 4 IF_CARD_CFI4OVER:OID 1.3.6.1.4.1.2011.5.25.41.3.27 The configuration of the interface card is restored.
Aug 24 2018 10:30:47 HWCM 4 CFGCHANGE:OID 1.3.6.1.4.1.2011.6.10.2.1 Configure changed.
Aug 24 2018 10:30:47 LINE 5 VTYUSERLOGOUT:OID 1.3.6.1.4.1.2011.5.25.207.2.4 A user logout.
Aug 24 2018 10:36:31 INFO 4 IC_LOGFILE_AGING:OID 1.3.6.1.4.1.2011.5.25.212.2.2 One log file is deleted due to aging.
Aug 24 2018 10:38:52 CGN 4 CGN2USER_PORT_NUI4_TRAP:Sloc=7,Vcpu=0:OID 1.3.6.1.4.1.2011.5.25.240.2.4 The number of pores assigned to Cl
Aug 24 2018 10:56:52 LINE 5 VTYUSERLOGIn7:OID 1.3.6.1.4.1.2011.5.25.207.2.2 A user login.
Aug 24 2018 10:56:58 LINE 5 VTYUSERLOGOUT:OID 1.3.6.1.4.1.2011.5.25.207.2.4 A user logout.
Aug 24 2018 11:07:30 SNMP 4 AUTHFAIL:OID 1.3.6.1.6.3.1.1.5.5 authenticationFailure.'''
arr=a.split('\n')
[' '.join(x.split(' ')[:3]+["OID"]+x.split(' ')[7:8]) for x in arr]

关于您的问题,我想到三种思路
s = "21-2"

# 方法一(通用)
# 找到‘-’的索引值,然后加一取出减号后面的值
index = s.find('-')+1
print(s[index:])

# 方法二(手工计算便宜)
# 数偏移量
print(s[3:])

# 方法三(取巧,利用-分隔)
# 已‘-’为分隔符,取后面的内容
print(s.split('-')[1])

可以用字符切片的方式
字符串21-2中,获取-的下标
然后用切片获取后面的内容

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