职高数学，大神们，不要过程
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绛旓細瑙ｏ細(1)褰搙锛瀉鏃, f(x)=3x²-2ax+a²=3(x-a/3)²+2a²/3 褰搙鈮鏃, f(x)=x²+2ax-a²=(x+a)²-2a²鑻鈮0, 鏈灏忓间负f(-a)=-2a²鑻锛0, 鏈灏忓间负f(a/3)=2a²/3 缁间笂寰梖(x)鏈灏忓肩殑鍑芥暟g(a)g(a)...
绛旓細29.鍏呭垎蹇呰 30.e 31. 0 1 2 2/3 32. 7 n 33. 9 2n-1 34.1/110 35.A=30搴 A=60搴 36.S=1/2absinC 37. 4 38.39.宸 蟺/12
绛旓細璇锋牴鎹垜璇寸殑鐢诲浘锛岃竟鐢昏竟鐪嬶細鍥犱负 CD=2鍊嶆牴鍙2锛岃BPD涓90搴︼紱鍙煡P鐐瑰湪姝ｆ柟褰BCD鐨勫鎺ュ渾涓婏紙璺熷浘1,2涓殑姝ｆ柟褰㈠拰澶栨帴鍦嗕竴鏍凤級銆傚張鍥犱负PD=2锛屽仛杈呭姪绾匡紝杩炴帴BD锛孭D锛孊P銆傚彲浠ュ彂鐜帮紝P鐐瑰湪鍦嗗姬AD鎴栬呭渾寮D涓婏紝鏈変袱绉嶆儏鍐点備护鍦嗗姬AD涓奝鐐瑰拰鍦嗗姬CD涓婄殑P'鐐广備綔鍥惧悗鍙煡閬撲笁瑙掑舰BPD...
绛旓細(sina)^2=(1-cos2a)/2=3/8 C sinx=-3/5,tanx=-3/4.tan2x=(tanx+tanx)/[1-(tanx)^2]=-24/7 2a=(a+b)+(a-b) tan(a+b)=3 tan(a-b)=5 tan2a=tan[(a+b)+(a-b)]=tan(a+b)+tan(a-b)/[1-tan(a+b)脳tan(a锛峛)]=锛4/7 绉婚」鍦ㄥ悓闄in灏辩煡閬搕a...
绛旓細1.杩炴帴OC鍜孫F锛屽彲浠ヨ瘉鏄嶢C鍜孋F鎵瀵圭殑鍦嗗績瑙掑害鏁扮浉绛夛紝鎵浠ュ湪鍥唴锛屼袱鏉″鸡鐩哥瓑
绛旓細鍥炵瓟锛4銆佽瀹戒负x,鍒欓暱涓(x鍗1),鐢遍鎰忓彲鐭,x(x鍗1)=132 瑙ｅ緱x鍗冲彲
绛旓細姹鏁板澶х,瑕佽缁杩囩▼,涓嶈鐩存帴鍑虹瓟妗 鎴戞潵绛 3涓洖绛 #鐑# 浣犺杩囧摢浜涘洜涓鸿佹澘浣滄瀵艰嚧鍊掗棴鐨勫叕鍙?鍖垮悕鐢ㄦ埛 2014-09-16 灞曞紑鍏ㄩ儴 鏈洖绛旂敱鎻愰棶鑰呮帹鑽 宸茶禐杩 宸茶俯杩< 浣犲杩欎釜鍥炵瓟鐨勮瘎浠锋槸? 璇勮 鏀惰捣 鍖垮悕鐢ㄦ埛 2014-09-16 灞曞紑鍏ㄩ儴 宸茶禐杩 宸茶俯杩< 浣犲杩欎釜鍥炵瓟鐨勮瘎浠锋槸? 璇勮 鏀惰捣 ...
绛旓細鍥炵瓟锛27000➗1000=27,澶т簬25浜 璁炬湁X浜,鏍规嵁棰樻剰鏈, X•[1000-20(X-25)]=27000 X=30浜
绛旓細鍥炵瓟锛歠(x)=2sin(2x+胃)鍗乵 m=1 4蟺/3鍗佄=3蟺/2 胃=蟺/6
绛旓細1)鍦ㄥ摢閲岃繖妫掔悆锛2)鍦ㄥ摢閲屾垜鐨勮绠楁満锛3)鍦ㄥ摢閲屾偍鐨勪功锛4)鍦ㄥ摢閲屼粬鐨勯挜鍖欙紵5)瀹冨湪娌欏彂涔嬩笅锛6)瀹冨湪鑳屽寘閲屻7)瀹冨湪妗屽瓙涓娿8)浠栦滑鍦ㄦ瀛愪笂銆9)浠栦滑鍦ㄦ⒊濡嗗彴涓娿10)鏄紝瀹冩槸銆/涓嶏紝瀹冧笉鏄
