问一道物理题
\u95ee\u4e00\u9053\u7269\u7406\u9898\u3002\u8bd5\u7ba1\u603b\u957f\u5ea6\u4e3a22cm\uff0c\u628a\u5b83\u770b\u6210\u4e00\u4e2a\u5706\u67f1\u4f53\uff0c\u5f53\u5728\u6c34\u4e2d\u6f02\u6d6e\u65f6\u670912cm\u9732\u51fa\u6c34\u9762\uff0c\u5219\u670910cm\u6d78\u5165\u6c34\u4e2d\uff0c\u5219V\u6392/V\u7269=10/22\u3002\u6b64\u65f6F\u6d6e=G=mg=0.02Kg*10N/kg=0.2N\u3002\u5219V\u6392=20cm^3(\u5728\u6c34\u4e2d \uff0c\u6392\u5f00100cm^3\u7684\u6c34\u6240\u53d7\u7684\u6d6e\u529b\u4e3a1N)\uff1b\u5219\u8bd5\u7ba1\u7684\u603b\u4f53\u79ef\u4e3a44cm^3
\u5f53\u8bd5\u7ba1\u4e0b\u90e8\u6302\u4e00\u77f3\u5757\u65f6\uff0c\u8bd5\u7ba1\u53ea\u67092cm\u9732\u51fa\uff0c\u5219\u670920cm\u6d78\u5165\uff0c\u6b64\u65f6\u8bd5\u7ba1\u6392\u5f00\u6c34\u7684\u4f53\u79ef\u4e3a40cm^3\uff0c\u8bd5\u7ba1\u6240\u53d7\u7684\u6d6e\u529b\u4e3a0.4N\uff0c\u9664\u4e86\u53d7\u5230\u8bd5\u7ba10.4N\u5411\u4e0a\u7684\u6d6e\u529b\uff0c\u8fd8\u8981\u53d7\u5230\u77f3\u5757\u7684\u6d6e\u529bF\u77f3\uff0c\u53ef\u4ee5\u628a\u77f3\u5757\u548c\u8bd5\u7ba1\u770b\u6210\u6f02\u6d6e\uff0c\u5219\u603b\u6d6e\u529b\u7b49\u4e8e\u603b\u91cd\u529b=G\u8bd5\u7ba1+G\u77f3\u5757=0.45N \u8bd5\u7ba1\u7684\u6d6e\u529b\u4e3a0.4N \uff0c\u5219\u77f3\u5757\u6240\u53d7\u7684\u6d6e\u529b\u4e3a0.45N-0.4N=0.05N \u7528\u963f\u57fa\u7c73\u5fb7\u516c\u5f0f\u8ba1\u7b97\u51fa\u77f3\u5934\u6392\u5f00\u6c34\u7684\u4f53\u79efV\u77f3\u6392=5cm^3\uff0c\u77f3\u5757\u7684\u8d28\u91cf\u4e3a25g\uff0c\u5219\u77f3\u5757\u7684\u5bc6\u5ea6=5*10^3kg/m^3
\u8bf4\u5f97\u6709\u70b9\u4e71\uff0c\u753b\u4e2a\u56fe\u6807\u51fa\u53d7\u529b\u7684\u793a\u610f\u56fe\u5c31\u65b9\u4fbf\u4e86\uff0c\u96be\u5f97\u8bdd\uff0c\u6162\u6162\u7406\u89e3\u4e0b\u5427
\u9009\u62e9B
\u5bf9\u7269\u4f53\u53d7\u529b\u5206\u6790\uff0c\u5b83\u53d7\u5230\u4e86\u91cd\u529bmg\uff08\u5411\u4e0b\uff09\uff0c\u62c9\u529bF\uff08\u5411\u4e0a\uff09\uff0c\u56e0\u4e3a\u7269\u4f53\u5411\u4e0a\u51cf\u901f\u8fd0\u52a8\u6240\u4ee5\u7528\u725b\u987f\u7b2c\u4e8c\u5b9a\u5f8b\uff1amg-F=ma\uff0c\u5176\u4e2da=1/6g\uff0c\u5f97\u5230F=5/6mg
G-F浮=Ma=1/2Mg
F浮=1/2Mg
上升时:
F浮-mg=ma
1/2Mg-mg=m(1/2g)
m=1/3M
M-m=M-1/3M=2/3M
m/M=（1/3）
F=ma 浮力是一直不变的记为F1
下降时：Mg-F1=Mg/2 得F1=Mg/2
上升时：设重量为x
F1-xg=xg/2
Mg/2=3xg/2
x=M/3
绛旓細(2)宸ヤ綔鐘舵佷笅锛岀伅娉′袱绔煭璺紝鍒欑數鐑欓搧涓ょ鐢靛帇220V锛屽姛鐜55W 棰勭儹鐘舵佷笅锛岀伅娉″姛鐜嘝鐏=I1^2R鐏=0.16^2*495=12.672W 鍒欓鐑姸鎬佹诲姛鐜囦负P棰勬=12.672+22.528=35.2 鐧惧垎姣斿氨鏄35.2/55=64
绛旓細1.姝ら鐨勬暣浣撹冭檻鎬濊矾搴旇鏄繍鍔ㄧ殑鍚堟垚涓庡垎瑙ｃ佸姏涓庤繍鍔ㄧ殑鍏崇郴锛屾纭垎瑙ｆ枩鎶涜繍鍔紝鐔熺粌搴旂敤杩愬姩瀛﹀叕寮忥紱2.閫夐」C娑夊強浜嗗姞閫熷害鐨勬蹇靛強鐗涢】杩愬姩瀹氬緥锛屽叿浣:鎶撲綇涓涓鐗╃悊閲忊斺旈熷害鍙樺寲閲忥紝瀹冩槸鎸囨湯閫熷害涓庡垵閫熷害鐨勭煝閲忓樊锛涘綋鐒跺湪杩欓噷杩欎釜宸殑瀹氶噺鍒嗘瀽鐩存帴鏄仛涓嶅嚭鏉ョ殑鐢氳嚦鏍规湰灏辨病鏈夋濊矾锛3.濡傛灉瀵瑰姞閫熷害...
绛旓細R1=U^2/P1 =220^2/100 =484惟 R2=220^2/25 =1936惟 涓茶仈鐢垫祦 I=220/(R1+R2)=0.091A 涓茶仈鍚庡姛鐜 P1=I^2*R1 =4W P2=I^2*R2 =16W
绛旓細Mg-T=Ma T-mg=ma 鍙眰寰桾=16.7 寮圭哀绉ょず閲2T=33.4 2.缁冲瓙鎷夊姏T=58.5/2=29.25 Mg-T=Ma1 5*10-29.25=5a a1=4.15 T-mg=ma2 29.25-10=a2=19.25 a-a'=4.15 a+a'=19.25 鍙緱a'=7.55
绛旓細浜烘墠鑳借窇鍒板畨鍏ㄥ尯锛屾牴鎹紩鐏嚎鐨勭噧鐑ч熷害鏄瘡绉05鍘樼背=0.005m/s 鍙圫=VT鍙畻鍑 S=0.2m=20cm 娉細瑙ｈ繖閬撻鐨勫叧閿湪鎶撲綇鏃堕棿鐩哥瓑鐨勫叧绯伙紝涔熷氨鏄浜哄埌瀹夊叏鍖烘墍闇鐨勬椂闂村拰寮曠伀绾跨儳瀹岀殑鏃堕棿鏄浉鍚岀殑锛屾妸鎻″ソ杩欎釜鍏崇郴灏辫兘寰堝ソ瑙ｅ喅杩欑被棰樸傝绠楁椂杩樿娉ㄦ剰鍗曚綅鐨勭粺涓銆備腑瀛鐗╃悊鏁欏笀 ...
绛旓細锛1锛夊疄闄呭瘑搴=600/52=11.54g/绔嬫柟鍘樼背銆傦紙2锛夎鎬昏川閲忎负x鍏嬶紝璐ㄩ噺鐩哥瓑锛屽垯閲戝拰閾滅殑璐ㄩ噺閮戒负x/2鍏嬶紝瀹冧滑鐨勪綋绉垎鍒槸x/锛2*19.3锛夈亁/锛2*8.9锛夛紝2鍊肩浉鍔犳讳綋绉氨鏄細2*锛19.3+8.9锛墄/锛4*19.3*8.9锛夛紝鍐嶇敤鎬昏川閲弜闄や互瀹冿紝寰12.18g/绔嬫柟鍘樼背銆傦紙3锛夎閲戠殑璐ㄩ噺涓篩锛屽垯閾...
绛旓細锛2锛夌怀瀛愭柇浜嗕互鍚庣墿浣撴墍鍙楀悎鍔=0.6-0.2=0.4N锛屽姞閫熷害=0.4/1.0=0.4m/s^2锛岀墿浣撻熷害涓洪浂鏃舵墍鑺辨椂闂=36.8/0.4=92s锛屾墍璧拌矾绋=36.8*92-1/2*0.4*92^2=1692.8m,缁冲瓙鏂箣鍓嶆墍璧拌矾绋=1/2*9.2*4^2=73.6m锛屾昏矾绋=1766.4m锛岃繑鍥炲簳绔墍鐢ㄦ椂闂=鏍瑰彿1766.4*2/0.4=93.98s,...
绛旓細鏈ㄥ潡鐨勪綋绉疺=125cm³娴稿叆姘翠腑鐨勪綋绉疺1=0.8XV=100cm³鍦嗘煴褰㈠鍣紝搴曢潰绉负S=100cm2 姘撮潰姣斿師鏉ュ崌楂樹簡h1=V1/S=100cm³/100cm2=1cm 锛屾按鐨勬繁搴︽槸h=h0+h1=10cm+1cm=11cm 姘村瀹瑰櫒搴曢儴鐨勫帇寮篜 =pgh=1000kg/m³X 10N /kgX 0.11m=1100pa ...
绛旓細鐢诧級锛歝锛堜箼锛*鈻砊锛堜箼锛=Q锛堢敳锛/m锛堢敳锛夛細Q锛堜箼锛/m锛堜箼锛=Q锛堢敳锛/Q锛堜箼锛:m锛堢敳锛/m锛堜箼锛=3:4 c锛堢敳锛*鈻砊锛堢敳锛夛細c锛堜箼锛*鈻砊锛堜箼锛= 锛(1)1*3锛1*4=3锛4鍙互 (2)2*1锛1*3=2锛3涓嶅彲 (3)1*3锛2*2=3锛4鍙互 (4)1*9锛4*4=9锛16涓嶅彲 鎵浠ラ塀 ...
绛旓細鎽╂摝鍔涘ぇ灏忎负f=渭N 娌挎按骞抽潰鍖閫熷墠杩涳紝閭ｄ箞锛屾媺鍔涚殑姘村钩鏂瑰悜鐨勫垎鍔涚瓑浜庢懇鎿﹀姏銆傚嵆Fcos伪=f 鍙堝湪绔栫洿鏂瑰悜涓婏紝N=mg-Fsin伪 鐢辫繖浜涘紡瀛愬緱鍒版媺鍔涚殑澶у皬F = mg渭/(cos胃 + 渭sin胃).瑕佹眰鎷夊姏鍋氱殑鍔燂紝绔栫洿鏂瑰悜涓婏紝鏃犱綅绉伙紝鍋氬姛涓0 姘村钩鏂瑰悜锛屽姏涓篎cos伪鍔熷氨涓篎cos伪*s=mg渭s/(1 + 渭tan胃...
