一毫米水柱等于多少帕
1mm水柱=9.8Pa。因为强ρSh*g/S=ρgh。且水的密度ρ=1g/cm^3，重力常数g=9.8N/kg，那么1mm水柱的压强为，P=1g/cm^3x9.8N/kgx1mm=1x10000kg/m^3x9.8N/kgx0.001m=9.8Pa。绛旓細璇ユ暟鍊兼按鏌卞崟浣绛変簬绾9.8064甯曟柉鍗★紙Pa锛夈傝繖涓浆鎹㈡槸鍩轰簬鐗╃悊鍘熺悊锛屽嵆鍦ㄦ爣鍑嗗ぇ姘斿帇涓嬶紝1姣背姘存煴鐨勯珮搴﹀搴旂殑鍘嬪姏灏辩瓑浜9.8064甯曟柉鍗°傝繖涓暟鍊兼槸缁忚繃绮剧‘璁＄畻寰楀嚭鐨勶紝骞朵笖鍦ㄥ疄闄呭簲鐢ㄤ腑琚箍娉涙帴鍙楀拰浣跨敤銆
绛旓細P=蟻gh=1000x10x1x10^-3=10Pa锛屽嵆1mm姘存煴绛変簬10Pa銆傛恫浣撳帇寮哄叕寮忔帹瀵艰繃绋嬶細瑕佹兂寰楀埌娑查潰涓嬫煇澶勭殑鍘嬪己锛屽彲浠ヨ鎯宠繖閲屾湁涓涓按骞虫斁缃殑鈥滃钩闈⑩濓紝杩欎釜骞抽潰浠ヤ笂鐨勬恫鏌卞骞抽潰鐨勫帇鍔涚瓑浜庢恫鏌辨墍鍙楃殑閲嶅姏銆傝繖涓钩闈笂鏂圭殑娑叉煴瀵瑰钩闈㈢殑鍘嬪姏锛欶=G=mg=蟻Vg=蟻Shg 骞抽潰鍙楀埌鐨勫帇寮猴細p=F/S=G/S=mg/S=蟻...
绛旓細涓1姣背姹炴煴杞崲涓姘存煴涓篖=10.34m/760=0.013605m 鍚屾椂姣背姹炴煴涓庢墭锛圱orr锛夌瓑浠凤紝骞朵笖鍧囦笉鏄浗闄呭崟浣嶅埗鍗曚綅鎴愬憳锛屽笗鏂崱鍒欎负鍘嬪己鐨勫浗闄呭崟浣嶃侾a鏄帇寮哄崟浣嶏紝1Pa灏辨槸1N/銕★紝1Pa=1N/m²銆1Pa鏄竴涓緢灏忕殑鍘嬪己锛岀洿鎺ョ敤甯鍋氬帇寮虹殑璁￠噺鍗曚綅涔熶細缁欏疄闄呯殑璁＄畻閫犳垚寰堝涓嶄究锛屾墍浠ョ粡甯镐細浣跨敤涓浜涜緝...
绛旓細鐢眕=蟻gh,g=9.8m/s^2=9.8N/kg,鍙煡,1kPa=1000Pa=1000kg/m^3*g*h,浠ｅ叆鏁版嵁寰梙=0.102m,鍥犳1鍗甯鐩稿綋浜102姣背姘存煴.鎵浠涓姣背姘存煴=1/102鍗冨笗;
绛旓細1姣背姘绛変簬9.8pa,涓绫虫按绛変簬9.8KPA,涓绫虫按绛変簬0.1bar=0.1KF/MM
绛旓細姣背姘存煴涓庡崈甯锛坘Pa锛変箣闂寸殑鎹㈢畻鍏崇郴鍙互閫氳繃鐩稿叧鐨勭墿鐞嗗叕寮忔潵寰楀嚭銆傚叿浣撴潵璇达紝1姣背姘存煴鐨勫帇鍔涚害绛変簬0.00981鍗冨笗銆備负浜嗘洿璇︾粏鍦拌В閲婅繖涓崲绠楀叧绯伙紝鎴戜滑棣栧厛瑕佷簡瑙ｅ帇鍔涘崟浣嶄箣闂寸殑杞崲鑳屾櫙銆傚湪鐗╃悊瀛︿腑锛屽帇鍔涙槸鍔涗綔鐢ㄥ湪鍗曚綅闈㈢Н涓婄殑鏁堟灉銆傛绫虫按鏌辨槸涓涓〃绀哄帇鍔涚殑鍗曚綅锛屽畠鎻忚堪鐨勬槸1姣背楂樼殑姘存煴鎵浜х敓鐨...
绛旓細9.8039鍗甯 鐢眕=蟻gh,g=9.8m/s^2=9.8N/kg,鍙煡,1kPa=1000Pa=1000kg/m^3*g*h,浠ｅ叆鏁版嵁寰梙=0.102m,鍥犳1鍗冨笗鐩稿綋浜102姣背姘存煴.鎵浠涓姣背姘存煴=1/102鍗冨笗 ,1绫姘存煴绛変簬1000/102=9.8039鍗冨笗=9803.9甯 鍦ㄥ浗闄呭埗鍗曚綅涓紝鍘嬪己鐨勫崟浣嶆槸N/m2锛岃浣滅墰椤挎瘡骞虫柟绫筹紝瀹冩湁涓涓笓闂ㄧ殑鍚嶇О...
绛旓細1鍗甯曠瓑浜7.5姣背姹炴煴銆傚崈甯曪紙kPa锛夊拰姣背姹炴煴锛坢mHg锛夋槸涓ょ涓嶅悓鐨勫帇鍔涘崟浣嶏紝瀹冧滑涔嬮棿鐨勬崲绠楀叕寮忔槸锛1kPa锛7.5mmHg锛1mmHg锛0.133kPa銆備篃灏辨槸璇达紝1鍗冨笗绛変簬7.5姣背姹炴煴锛1姣背姹鏌辩瓑浜0.133鍗冨笗銆傝繖涓崲绠楀叕寮忓彲浠ュ府鍔╂垜浠皢涓绉嶅帇鍔涘崟浣嶈浆鎹负鍙︿竴绉嶅崟浣嶏紝浠ヤ究浜庤繘琛屾瘮杈冨拰璁＄畻銆俴pa涓巑mhg...
绛旓細0.15绫虫按鏌辨槸1.47鍗甯銆傜敱p=蟻gh,g=9.8m/s^2=9.8N/kg,鍙煡锛1kPa=1000Pa=1000kg/m^3*g*h銆備唬鍏ユ暟鎹緱h=0.102m銆傚洜姝1鍗冨笗鐩稿綋浜102姣背姘存煴锛屾墍浠涓姣背姘存煴=1/102鍗冨笗 銆1绫姘存煴绛変簬1000/102=9.8039鍗冨笗=9803.9甯曘9.8039脳0.15=1.47鍗冨笗銆傜畝浠 1 Pa锛堝笗鏂崱锛=1 N/m2...
绛旓細1宸(bar)=100鍗冨笗(KPa)=10鐗涢】/骞虫柟鍘樼背=0.1MPa 宸达紙bar锛夋槸鍘嬪己鐨勫崟浣嶏紝鏃╁厛姘旇薄瀛︿腑甯哥敤姣反锛屽悗鏀圭敤绛夊肩殑鍥介檯鍗曚綅鐧惧笗銆1甯=1N/m2.鍦ㄥ伐绋嬩笂浠嶅湪娌跨敤鍏枻鍔涜繖涓崟浣嶏紝1鍏枻鍔绛変簬9.80665鐗涢】锛岀敱姝ゅ緱鍑猴細1鍏枻鍔/骞虫柟鍘樼背=0.967841澶ф皵鍘=98066.5甯曟柉鍗=1涓伐绋嬪ぇ姘斿帇 姣背姹炴煴涔熸槸涓绉...
