用python编写一段程序，输入若干单词，按照单词长短进行排序，并统计所有单词中每个字母(a-z)出现的次数 Python编程 从键盘上输入若干个用空格分开的单词,按字典...
\u4e00\u4e2a\u7b80\u5355\u7684python\u7a0b\u5e8f\uff0c\u5229\u7528DSU\u6a21\u5f0f\u628awords\u91cc\u9762\u7684\u5355\u8bcd\u6309\u7167\u957f\u5ea6\u6392\u5e8f\u3002\u4e0b\u9762\u7684\u7a0b\u5e8f\u4e2d\u6ce8\u91ca\u7684\u90a3\u53e5\u8bdd\u5230\u5e95\u6709\u4ec0\u4e48\u53d8\u91cf\u8986\u76d6\u7684\u95ee\u9898
words = ['abcd', 'ab', 'defghi']lst = []for word in words: #\u8fd9\u91cc\u5bf9word\u53d8\u91cf\u8fdb\u884c\u4e86\u5e45\u503c,\u5386\u904d\u540eword\u7b49\u4e8e\u6700\u540e\u4e00\u4e2a\u503c,\u5c31\u662f'defghi' lst.append((len(word), word))lst.sort(reverse = True)sort_words = []for e in lst: #\u8fd9\u5c40\u7684\u610f\u601d\u662f\u5c06\u6392\u5e8f\u540e\u7684\u53d8\u91cf\u8fdb\u884c\u89e3\u5305 #word\u53d8\u91cf\u5c06\u8986\u76d6\u4e0a\u9762\u7684word\u53d8\u91cf,\u6ca1\u6709\u8fd9\u4e00\u53e5,word\u7684\u503c\u5c31\u4e0d\u4f1a\u6539\u53d8 length, word = e //\u4f5c\u7528\u5230\u5e95\u662f\u4ec0\u4e48\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f sort_words.append(word)print sort_words
a = str(raw_input(u"\u8bf7\u8f93\u5165\u7528\u7a7a\u683c\u5206\u5f00\u7684\u5355\u8bcd\uff1a"))b = a.split()b.sort()for i in b: print i
1、解法：对输入的单词进行分割得到列表，遍历列表中的单词，二级遍历单词中的字符，判断字符是否存在字符字典中，存在则计数+1，不存在则初始化字典为1
2、知识点：字典、列表、for循环、if判断、input获得输入、print打印
3、代码如下：
# -*- coding: UTF-8 -*-
#简历一个字典，key=26个英文字母，value为出现次数
wordDict = {}
#获得输入单词字符串
str = input("请输入一串单词")
#用空格分割单词，存到列表
strArr = str.split(sep=' ')
#遍历列表中的单词
for word in strArr:
#遍历单词中的字母
for ch in word:
#判断字典中是否存在键key
if ch in wordDict:
wordDict[ch] = wordDict.get(ch)+1#计数+1
else:
wordDict[ch] = 1#计数初始化为1
#打印输出
for key,value in wordDict.items():
print("%s=%d"%(key, value))
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