后台应该如何取到前端传来的json对象 如何获取前端传过来的json对象?
\u540e\u53f0\u600e\u6837\u83b7\u53d6\u524d\u53f0ajax\u4f20\u6765\u7684json\u6570\u636eJava\u63a5\u6536\u53c2\u6570
String ds = request.getParameter("ds");
JSONArray json=JSONArray.fromObject(ds);
JSONObject jsonOne;
Map map=null;
for(int i=0;i<json.size();i++){
updataMap = new HashMap();
jsonOne = json.getJSONObject(i);
map.put("name", (String) jsonOne.get("name"));
map.put("age", (String) jsonOne.get("age"));
}
\u6b64\u65f6map\u4e2d\u5c31\u4fdd\u5b58\u4e86\u9875\u9762\u4f20\u8fc7\u6765\u7684\u6570\u7ec4\u4e2d\u6240\u6709json\u4e2d\u7684\u952e\u503c\u5bf9\u4e86
\u83b7\u53d6\u524d\u7aef\u4f20\u8fc7\u6765\u7684json\u5bf9\u8c61
\u4ee3\u7801\u5982\u4e0b
public JSONObject getRequestContent(HttpServletRequest req) {
JSONObject data = null;
try {
InputStream is = req.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(is, "utf-8"));
String line = null;
StringBuffer content = new StringBuffer();
while ((line = br.readLine()) != null) {
System.out.println(line);
content.append(line);
System.out.println(content);
}
String reqStr = content.toString().trim();
if (StringUtils.isEmpty(reqStr)) {
return new JSONObject();
}
if (reqStr.contains("=")) {
reqStr = reqStr.replaceAll("=", ":");
}
if (!reqStr.startsWith("{")) {
reqStr = "{" + reqStr;
}
if (!reqStr.endsWith("}")) {
reqStr = reqStr + "}";
}
data = JSONObject.fromObject(reqStr);
} catch (Exception e) {
e.printStackTrace();
return new JSONObject();
}
return data;
}
可先转成字符串dataForm = dataForm.toString();
后端接收:String dataForm = request.getParameter("dataForm");
假如有Test这个类,里面有hello ,hello2
那么就可以将json格式的数据转换成数组格式
List<Test> qualificationList = JSONArray.parseArray(HtmlUtils.htmlUnescape(dataForm), Test.class);
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