跪求用Matlab解带指数的三元方程组 求matlab解三元方程组,最好能把命令行列出来

\u6c42\u9ad8\u624b\u7528matlab\u89e3\u4e00\u4e2a\u4e09\u5143\u7684\u65b9\u7a0b\u7ec4

\u65b9\u7a0b\u65e0\u89e3\u3002\u53ef\u4ee5\u5f88\u7b80\u5355\u5730\u753b\u51fa\u4e24\u4e2a\u65b9\u7a0b\u7684\u66f2\u7ebf\u6765\uff1a
ezplot('-0.050+0.015+0.070-2.*(d.*0.0215).^0.5-2.*(p.*0.0504).^0.5',[-0.02 0.02])
hold on
ezplot('-0.015+d+p',[-0.02 0.02])

\u7531\u56fe\u53ef\u89c1\uff0c\u4e24\u6761\u7ebf\u65e0\u4ea4\u70b9\uff0c\u4e5f\u5c31\u610f\u5473\u7740\u65b9\u7a0b\u7ec4\u65e0\u89e3\u3002

\u6216\u8005\u6362\u53e6\u4e00\u79cd\u65b9\u5f0f\u6765\u5206\u6790\uff1a\u628a\u65b9\u7a0b1\u4ee3\u5165\u65b9\u7a0b2\uff1a
syms d p
eq1=-0.015+d+p;
eq2=-0.050+0.015+0.070-2.*(d.*0.0215).^0.5-2.*(p.*0.0504).^0.5;
d=solve(eq1,d)
eq=subs(eq2,d,d)\u5f97\u5230\u65b9\u7a0b\uff1a
>> eq=subs(eq2,d,d)
eq =
7/200 - 2*(129/400000 - (43*p)/2000)^(1/2) - 2*((63*p)/1250)^(1/2)\u65b9\u7a0b\u4e2d\u4e24\u4e2a\u5305\u542bp\u7684\u9879\u90fd\u8981\u8fdb\u884c\u5f00\u5e73\u65b9\uff0c\u5e94\u8be5\u5927\u4e8e0\uff0c\u5373\uff1a
(63*p)/1250
>=
0
129/400000
-
(43*p)/2000
>=
0
\u8054\u7acb\u89e3\u5f97
0<=p<=0.015\uff0c\u753b\u51fa\u8be5\u65b9\u7a0b\u7684\u66f2\u7ebf\u5982\u4e0b\uff1a

\u4e0d\u53ef\u80fd\u4e0e0\u8f74\u76f8\u4ea4\uff0c\u4e5f\u5373\u65b9\u7a0b\u65e0\u89e3\u3002

\u6c42matlab\u89e3\u6b64\u4e09\u5143\u65b9\u7a0b\u7ec4\uff0c\u53ef\u4ee5\u8003\u8651\u7528fsove\uff08\uff09\u51fd\u6570\u6765\u6c42\u89e3\u3002
1\u3001\u9996\u5148\u81ea\u5b9a\u4e49\u51fd\u6570fun(x)
fun=@(x)[11*cos(x(2))+x(1)-350,cos(x(3).*x(1))+sin(x(2)),1/tan(x(2))+x(3)*11.*sin(x(3).*x(1))]; %x=x(1),y=x(2),z=x(3)
2\u3001\u7136\u540e\u7528fsove\uff08\uff09\u51fd\u6570\u6c42\u89e3
x0=[300 2 -0.01], [x,h]=fsolve(fun,x0)
3\u3001\u6c42\u89e3\u7ed3\u679c
x\u2248350.01\uff1by\u22481.5713\uff1bz\u22480.044877
4\u3001\u6c42\u89e3\u754c\u9762

用solve()函数,求解就ok了.

 v1=53.56;v2=24.46;v3=10.16;T1=323.13;T2=343.13;T3=373.13;

 syms A B m0

s=solve(log10(v1+A)-B+m0*log10(T1),log10(v2+A)-B+m0*log10(T2),log10(v3+A)-B+m0*log10(T3));

s.A,s.A,B.m0

运行结果如下



先新建一个函数
function F = fun1( x )
v1=53.56;
v2=24.46;
v3=10.16;
T1=323.13;
T2=343.13;
T3=373.13;
F=[log10(v1+x(1))-x(2)+x(3)*log10(T1);
log10(v2+x(1))-x(2)+x(3)*log10(T2);
log10(v3+x(1))-x(2)+x(3)*log10(T3)];
end
再重新建个脚本

clc
x0=[1 -10 1];
options=optimoptions('fsolve','Display','iter','TolFun',1e-50,'TolX',1e-50);
[x,fval,~,output,~] = fsolve(@fun1,x0,options);
A=x(1)
B=x(2)
m0=x(3)

x0是初值,初值不同解可能不同(局部收敛)

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