初二整式的除法以及因式分解难题

\u521d\u4e8c\u56e0\u5f0f\u5206\u89e3\u96be\u9898

1/x(x+1)+1/(x+1)(x+2\uff09+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
(x+2+x)/x+(x+1)+(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
2(x+1)/x(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
2/x(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
[2(x+3)+x]/x(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
3(x+2)/x(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
3/x(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
[3(x+4)+x]/x(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
4(x+3)/x(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
4/x(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
[4(x+5)+x]/x(x+4)(x+5)=5/(x²+11x-708)
5(x+4)/x(x+4)(x+5)=5/(x²+11x-708)
5/x(x+5)=5/(x²+11x-708)
x(x+5)=x²+11x-708
x²+5x=x²+11x-708
6x=708
x=118

\u56e0\u5f0f\u5206\u89e3\u7ec3\u4e60\u9898

140\uff0em2(p-q)-p+q
141\uff0e(2m+3n)(2m-n)-4n(2m-n)\uff0e
142\uff0e(x+2y)2-x2-2xy\uff0e
143\uff0ea(ab+bc+ac)-abc\uff0e
144\uff0eab-a-b+1\uff0e
145\uff0exyz-xy-xz+x-yz+y+z-1\uff0e
146\uff0ex4-2y4-2x3y+xy3\uff0e

148\uff0eabc(a2+b2+c2)-a3bc+2ab2c2\uff0e
149\uff0e(a-b-c)(a+b-c)-(b-c-a)(b+c-a)\uff0e
150\uff0ea2(b-c)+b2(c-a)+c2(a-b)\uff0e

a(a+b)(a-b)-a(a+b)2\uff0e
152\uff0e(x2-2x)2+2x(x-2)+1\uff0e
153\uff0e2acd-c2a-ad2\uff0e
154\uff0e(x-y)2+12(y-x)z+36z2\uff0e

156\uff0ex2-4ax+8ab-4b2\uff0e
157\uff0ea2b2+c2d2-2abcd+2ab-2cd+1\uff0e
158\uff0e(ax+by)2+(ay-bx)2+2(ax+by)(ay-bx)\uff0e

160\uff0e(1-a2)(1-b2)-(a2-1)2(b2-1)2\uff0e
161\uff0e3x4-48y4\uff0e
162\uff0e(x+1)2-9(x-1)2\uff0e
163\uff0e(x2+pq)2-(p+q)2x2\uff0e
164\uff0e(1+2xy)2-(x2+y2)2\uff0e
165\uff0e4a2b2-(a2+b2)2\uff0e
166\uff0e4a2b2-(a2+b2-c2)2\uff0e
167\uff0e(c2-a2-b2)2-4a2b2\uff0e
168\uff0e(x2-b2+y2-a2)2-4(ab-xy)2\uff0e
169\uff0e64a4(x+1)2-49b4(x+1)4\uff0e
170\uff0eab2-ac2+4ac-4a\uff0e
171\uff0e4a2-c2+6ab+3bc\uff0e
172\uff0ex3n+y3n\uff0e

174\uff0e(x+y)3+125\uff0e

176\uff0e(m-n)6-(m+n)6\uff0e
177\uff0e(x+1)6-(x-1)6\uff0e
178\uff0ea12-b12\uff0e
179\uff0e(z-x)3-(y+z)3\uff0e
180\uff0e(3m-2n)3+(3m+2n)3\uff0e
181\uff0ex6(x2-y2)+y6(y2-x2)\uff0e
182\uff0e8(x+y)3+1\uff0e
183\uff0e(a-1)3-(b+1)3\uff0e
184\uff0e(a+b+c)3-a3-b3-c3\uff0e
185\uff0ex2+4xy+3y2\uff0e
186\uff0ex2y2-18xy+65\uff0e
187\uff0ex2+18x-144\uff0e
188\uff0ex2+30x+144\uff0e
189\uff0ex4+2x2-8\uff0e
190\uff0e3x4+6x2-9\uff0e
191\uff0e-m4+18m2-17\uff0e
192\uff0e3x4-7x2y2-20y4\uff0e
193\uff0ex5-2x3-8x\uff0e
194\uff0ea3-5a2b-300ab2\uff0e
195\uff0ex8+19x5-216x2\uff0e
196\uff0e6a4n+k-a2n+k-35ak\uff0e

199\uff0e30x2+8xy-182y2\uff0e
200\uff0em4+14m2-15\uff0e
140\uff0e\uff08p-q\uff09\uff08m-1\uff09\uff08m+1\uff09\uff0e
141\uff0e\uff082m-n\uff092\uff0e
142\uff0e2y\uff08x+2y\uff09\uff0e
143\uff0ea2\uff08b+c\uff09\uff0e
144\uff0e\uff08b-1\uff09\uff08a-1\uff09\uff0e
145\uff0e\uff08x-1\uff09\uff08y-1\uff09\uff08z-1\uff09\uff0e
\u63d0\u793a\uff1a\u65b9\u6cd5\u4e00 \u539f\u5f0f=x\uff08yz-y-z+1\uff09-\uff08yz-y-z+1\uff09
=\uff08yz-y-z+1\uff09\uff08x-1\uff09
=[y\uff08z-1\uff09-\uff08z-1\uff09]\uff08x-1\uff09
=\uff08x-1\uff09\uff08y-1\uff09\uff08z-1\uff09\uff0e
\u65b9\u6cd5\u4e8c \u539f\u5f0f=xy\uff08z-1\uff09-x\uff08z-1\uff09-y\uff08z-1\uff09+\uff08z-1\uff09
=\uff08xy-x-y+1\uff09\uff08z-1\uff09
=[x\uff08y-1\uff09-\uff08y-1\uff09]\uff08z-1\uff09
=\uff08x-1\uff09\uff08y-1\uff09\uff08z-1\uff09\uff0e
146\uff0e\uff08x-2y\uff09\uff08x+y\uff09\uff08x2-xy+y2\uff09\uff0e
\u63d0\u793a\uff1a\u65b9\u6cd5\u4e00 \u539f\u5f0f=x\uff08x3+y3\uff09-2y\uff08x3+y3\uff09
=\uff08x3+y3\uff09\uff08x-2y\uff09
=\uff08x-2y\uff09\uff08x+y\uff09\uff08x2-xy+y2\uff09\uff0e
\u65b9\u6cd5\u4e8c \u539f\u5f0f=x3\uff08x-2y\uff09+y3\uff08x-2y\uff09
=\uff08x-2y\uff09\uff08x3+y3\uff09
=\uff08x-2y\uff09\uff08x+y\uff09\uff08x2-xy+y2\uff09\uff0e


148\uff0eabc\uff08b+c\uff092\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=abc\uff08a2+b2+c2-a2+2bc\uff09\uff0e
149\uff0e2\uff08b-c\uff09\uff08a-b-c\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=\uff08a-b-c\uff09\uff08a+b-c\uff09+\uff08a-b-c\uff09\uff08b-c-a\uff09
=\uff08a-b-c\uff09[\uff08a+b-c\uff09+\uff08b-c-a\uff09]
=2\uff08b-c\uff09\uff08a-b-c\uff09\uff0e
150\uff0e\uff08a-b\uff09\uff08b-c\uff09\uff08a-c\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=a2b-a2c+b2c-ab2+c2\uff08a-b\uff09
=\uff08a2b-ab2\uff09-\uff08a2c-b2c\uff09+c2\uff08a-b\uff09
=ab\uff08a-b\uff09-c\uff08a2-b2\uff09+c2\uff08a-b\uff09
=\uff08a-b\uff09[ab-c\uff08a+b\uff09+c2]
=\uff08a-b\uff09[a\uff08b-c\uff09-c\uff08b-c\uff09]
=\uff08a-b\uff09\uff08b-c\uff09\uff08a-c\uff09\uff0e

\u63d0\u793a\uff1a\u539f\u5f0f=a\uff08a+b\uff09[a-b-\uff08a+b\uff09]=a\uff08a+b\uff09\uff08-2b\uff09
=-2ab\uff08a+b\uff09\uff1b

152\uff0e\uff08x-1\uff094\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=[x\uff08x-2\uff09]2+2•x\uff08x-2\uff09+12
=[x\uff08x-2\uff09+1]2=\uff08x2-2x+1\uff092
=\uff08x-1\uff094\uff0e
153\uff0e-a\uff08c-d\uff092\uff0e
154\uff0e\uff08x-y-6z\uff092\uff0e

156\uff0e\uff08x-2b\uff09\uff08x-4a+2b\uff09\uff0e
157\uff0e\uff08ab-cd+1\uff092\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=\uff08a2b2-2abcd+c2d2\uff09+2\uff08ab-cd\uff09+1
=\uff08ab-cd\uff092+2\uff08ab-cd\uff09+1
=\uff08ab-cd+1\uff092\uff0e
158\uff0e\uff08ax+by+ay-bx\uff092\uff0e


160\uff0e\uff081+a\uff09\uff081-a\uff09\uff081+b\uff09\uff081-b\uff09\uff08a2+b2-a2b2\uff09\uff0e
161\uff0e3\uff08x2+4y2\uff09\uff08x+2y\uff09\uff08x-2y\uff09\uff0e
162\uff0e4\uff082x-1\uff09\uff082-x\uff09\uff0e
163\uff0e\uff08x2+px+qx+pq\uff09\uff08x2-px-qx+pq\uff09\uff0e
164\uff0e\uff081+x-y\uff09\uff081-x+y\uff09\uff08x2+y2+2xy+1\uff09\uff0e
165\uff0e-\uff08a+b\uff092\uff08a-b\uff092\uff0e
166\uff0e\uff08a+b+c\uff09\uff08a+b-c\uff09\uff08c+a-b\uff09\uff08c-a+b\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=\uff082ab+a2+b2-c2\uff09\uff082ab-a2-b2+c2\uff09
=[\uff08a+b\uff092-c2][c2-\uff08a-b\uff092]
=\uff08a+b+c\uff09\uff08a+b-c\uff09\uff08c+a-b\uff09\uff08c-a+b\uff09\uff0e
167\uff0e\uff08c+a-b\uff09\uff08c-a+b\uff09\uff08c+a+b\uff09\uff08c-a-b\uff09\uff0e
168\uff0e\uff08x+y+a+b\uff09\uff08x+y-a-b\uff09\uff08x-y+a-b\uff09\uff08x-y-a+b\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=\uff08x2-b2+y2-a2+2ab-2xy\uff09\uff08x2-b2+y2-a2-2ab+2xy\uff09
=[\uff08x2-2xy+y2\uff09-\uff08a2-2ab+b2\uff09][\uff08x2+2xy+y2\uff09
-\uff08a2+2ab+b2\uff09]
=[\uff08x-y\uff092-\uff08a-b\uff092][\uff08x+y\uff092-\uff08a+b\uff092]
=\uff08x-y+a-b\uff09\uff08x-y-a+b\uff09\uff08x+y+a+b\uff09\uff08x+y-a-b\uff09\uff0e
169\uff0e\uff08x+1\uff092\uff088a2+7b2x+7b2\uff09\uff088a2-7b2x-7b2\uff09\uff0e
170\uff0ea\uff08b-c+2\uff09\uff08b+c-2\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=a\uff08b2-c2+4c-4\uff09
=a\uff08b2-c2+2b-2b+2c+2c-4\uff09
=a[\uff08b-c\uff09\uff08b+c\uff09-2\uff08b-c\uff09+2\uff08b+c\uff09-4]
=a[\uff08b-c\uff09+2][\uff08b+c\uff09-2]\uff0e
171\uff0e\uff082a+c\uff09\uff082a-c+3b\uff09\uff0e
172\uff0e\uff08xn+yn\uff09\uff08x2n-xnyn+y2n\uff09\uff0e

174\uff0e\uff08x+y+5\uff09\uff08x2+2xy+y2-5x-5y+25\uff09\uff0e

176\uff0e-4mn\uff083n2+m2\uff09\uff083m2+n2\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=[\uff08m-n\uff093]2-[\uff08m+n\uff093]2
=[\uff08m-n\uff093+\uff08m+n\uff093][\uff08m-n\uff093-\uff08m+n\uff093]
=2m[\uff08m-n\uff092-\uff08m-n\uff09\uff08m+n\uff09\uff08m+n\uff092]
\u00d7{-2n[\uff08m-n\uff092+\uff08m-n\uff09\uff08m+n\uff09+\uff08m+n\uff092]}
=-4mn\uff08m2+3n2\uff09\uff083m2+n2\uff09\uff0e
177\uff0e4x\uff08x2+3\uff09\uff083x2+1\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=[\uff08x+1\uff093]2-[\uff08x-1\uff093]2
=[\uff08x+1\uff093+\uff08x-1\uff093][\uff08x+1\uff093-\uff08x-1\uff093]
=2x[\uff08x+1\uff092-\uff08x+1\uff09\uff08x-1\uff09+\uff08x-1\uff092]
\u00d72[\uff08x+1\uff092+\uff08x+1\uff09\uff08x-1\uff09+\uff08x-1\uff092]
=4x\uff08x2+3\uff09\uff083x2+1\uff09\uff0e
178\uff0e\uff08a-b\uff09\uff08a+b\uff09\uff08a2+b2\uff09\uff08a2+ab+b2\uff09\uff08a2-ab+b2\uff09\uff08a4-a2b2+b4\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=\uff08a6\uff092-\uff08b6\uff092=\uff08a6+b6\uff09\uff08a6-b6\uff09
=[\uff08a2\uff093+\uff08b2\uff093][\uff08a3\uff092-\uff08b3\uff092]
=\uff08a2+b2\uff09\uff08a4-a2b2+b4\uff09\uff08a3+b3\uff09\uff08a3-b3\uff09\uff0e
179\uff0e-\uff08x+y\uff09\uff08x2+y2+3z2-xy+3yz-3xz\uff09\uff0e
180\uff0e18m\uff083m2+4n2\uff09\uff0e
181\uff0e\uff08x+y\uff092\uff08x-y\uff092\uff08x2-xy+y2\uff09\uff08x2+xy+y2\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=\uff08x2-y2\uff09\uff08x6-y6\uff09
=\uff08x+y\uff09\uff08x-y\uff09\uff08x3+y3\uff09\uff08x3-y3\uff09\uff0e
182\uff0e\uff082x+2y+1\uff09\uff084x2+8xy+4y2-2x-2y+1\uff09\uff0e
183\uff0e\uff08a-b-2\uff09\uff08a2+ab+b2-a+b+1\uff09\uff0e
184\uff0e3\uff08b+c\uff09\uff08a+b\uff09\uff08c+a\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=[\uff08a+b+c\uff093-a3]-\uff08b3+c3\uff09\uff0e
185\uff0e\uff08x+3y\uff09\uff08x+y\uff09\uff0e
186\uff0e\uff08xy-13\uff09\uff08xy-5\uff09\uff0e
187\uff0e\uff08x-6\uff09\uff08x+24\uff09\uff0e
188\uff0e\uff08x+6\uff09\uff08x+24\uff09\uff0e
189\uff0e\uff08x2-2\uff09\uff08x2+4\uff09\uff0e
190\uff0e3\uff08x2+3\uff09\uff08x+1\uff09\uff08x-1\uff09\uff0e
191\uff0e\uff08m2-17\uff09\uff081+m\uff09\uff081-m\uff09\uff0e
192\uff0e\uff083x2+5y2\uff09\uff08x+2y\uff09\uff08x-2y\uff09\uff0e
193\uff0ex\uff08x+2\uff09\uff08x-2\uff09\uff08x2+2\uff09\uff0e
194\uff0ea\uff08a-20b\uff09\uff08a+15b\uff09\uff0e
195\uff0ex2\uff08x+3\uff09\uff08x2-3x+9\uff09\uff08x-2\uff09\uff08x2+2x+4\uff09\uff0e
\u63d0\u793a\uff1a\u539f\u5f0f=x2\uff08x6+19x3-216\uff09
=x2\uff08x3+27\uff09\uff08x3-8\uff09
=x3\uff08x+3\uff09\uff08x2-3x+9\uff09\uff08x-2\uff09\uff08x2+2x+4\uff09\uff0e
196\uff0eak\uff082a2n-5\uff09\uff083a2n+7\uff09\uff0e

199\uff0e2\uff083x-7y\uff09\uff085x+13y\uff09\uff0e
200\uff0e\uff08m2+15\uff09\uff08m+1\uff09\uff08m-1\uff09\uff0e

x²-3x+1=0
两边除以x可得
x-3+1/x=0
x+1/x=3
两边平方得
x²+1/x²=9-2=7

2.
因为任何数的绝对值非负,平方非负
所以ab-2=0,b-1=0
所以
b=1,a=2
所以
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+......+1/(a+2008)(b+2008)
=
1/1*2+1/2*3+......+1/2009*2010
=1-1/2+1/2-1/3+...+1/2009-1/2010
=1-1/2010
=2009/2010

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