java，请问如何截取一个字符串的后三位 java如何截取一个字符串的后三位?
java\u4e2d\u600e\u6837\u622a\u53d6\u4e00\u4e2a\u5b57\u7b26\u4e32\u4e2d\u6307\u5b9a\u7684\u5b57\u7b26\u4e32String reg1 = ".*\u6027\u522b\uff1a([^\\|]*)\\|?.*";
String reg2 = ".*\u6c11\u65cf\uff1a([^\\|]*)\\|?.*";
String reg3 = ".*\u751f\u65e5\uff1a([^\\|]*)\\|?.*";
String str = "\u6027\u522b\uff1a\u5973\u58eb|\u6c11\u65cf\uff1a\u6c49\u65cf|\u751f\u65e5\uff1a1990-9-22";
String sex = str.replaceAll(reg1, "$1");
String mz = str.replaceAll(reg2, "$1");
String brith = str.replaceAll(reg3, "$1");
System.out.println (sex);
System.out.println (mz);
System.out.println (brith);
str.substring\u4e00\u4e2a\u8d77\u59cb\u4f4d\u7f6e\u4e00\u4e2a\u7ed3\u675f\u4f4d\u7f6e\u3002
Stringvalue="abcdefg";
intlength=value.length();
if(length>=3){
Stringstr=value.substring(length-3,length);
System.out.println(str);
}else{
System.out.println(value);
}\u8f93\u51fa\u7ed3\u679c\u4e3aefg
\u5f53\u7136\u622a\u53d6\u524d\u8981\u5224\u65ad\u662f\u5426\u4e3anull\uff0c\u4e0d\u4e3anull\u624d\u53ef\u4ee5\u622a\u53d6
String str="abcdefgh";
String newStr=String.SubString(str.length()-3);
System.out.println(newStr); // \u5c06\u8f93\u51fa\u5b57\u7b26\u4e32\u6700\u540e\u4e09\u4f4d\u5b57\u7b26fgh
str.substring一个起始位置一个结束位置。
String value = "abcdefg";
int length = value.length();
if(length >= 3){
String str = value.substring(length-3, length);
System.out.println(str);
}else{
System.out.println(value);
}
输出结果为：
efg
当然截取前要判断是否为null，不为null才可以截取
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