Python题目求解答 Python题目 求解答
Python\u4e60\u9898\u6c42\u89e3\u7b54\u91cd\u590d\u8bfb\u53d6\u6570\u636e\u5199\u4e2awhile\u5faa\u73af\u5c31\u884c\u4e86
\u4ee3\u7801\u4e3a\uff1a
arr = []num = 0sum = 0while 1: val = input('\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570') try: if val == 'done': for i in arr: sum = sum + float(i) print('\u603b\u548c\u4e3a\uff1a' + str(sum)) print('\u8f93\u5165\u4e2a\u6570\u4e3a\uff1a' + str(num)) print('\u5e73\u5747\u6570\u4e3a\uff1a' + str(sum/num)) exit() else: float(val) arr.append(float(val)) num = num + 1 except(ValueError): print('\u8fd9\u4e0d\u662f\u4e00\u4e2a\u6570\u5b57') print(ValueError) pass
import matplotlib.pyplot as pltx = range(1, 11)y = [2 * i ** 2 + 3 for i in x]plt.plot(x, y)plt.show()
第4题
def sumofexpress(a,n):
sum=0
for i in range(1,n+1):
sum+=int(str(a)*i)
return sum
if __name__=='__main__':
print(sumofexpress(2,5))
源代码(注意源代码的缩进)
第3题
def sumofdigit(n):
sum=0
while n>0:
sum+=n%10
n=n//10
return sum
if __name__=='__main__':
for x in range(100,1000):
x1=sumofdigit(x)
x3=sumofdigit(x*3)
x4=sumofdigit(x*4)
x5=sumofdigit(x*5)
x6=sumofdigit(x*6)
x7=sumofdigit(x*7)
if x1==x3 and x1==x4 and x1==x5 and x1==x6 and x1==x7:
print("x="+str(x)+":x*3="+str(x*3)+",x*4="+str(x*4)+",x*5="+str(x*5)+",x*6="+str(x*6)+",x*7="+str(x*7))
源代码(注意源代码的缩进)
最后一题
def isLeap(n):
if n%4==0 and n%100!=0 or n%400==0:
return True
else:
return False
if __name__=='__main__':
count=0
for n in range(1900,2021):
if isLeap(n)==True:
print(n,end=' ')
count+=1
if count%5==0:
print()
源代码(注意源代码的缩进)
#题目1
def na(n,a):
r=0
for i in range(1,n+1):
r=int(str(a)*i)+r
return r
na(5,2)
#题目2
def snum(x):
x=str(x)
l=len(x)
a=[int(x[i]) for i in range(0,l)]
return sum(a)
m=0
for j in range(100,1000):
a=str(j)+'*'+str(3)
b=str(j)+'*'+str(4)
c=str(j)+'*'+str(5)
d=str(j)+'*'+str(6)
e=str(j)+'*'+str(7)
n=[snum(eval(a)),snum(eval(b)),snum(eval(c)),snum(eval(d)),snum(eval(e))]
if len(set(n))==1:
print('x=' + str(j) + ':' +
a + '=' + str(eval(a)) + ',' +
b + '=' + str(eval(b)) + ',' +
c + '=' + str(eval(c)) + ',' +
d + '=' + str(eval(d)) + ',' +
e + '=' + str(eval(e)))
m +=1
print('共有'+str(m)+'符合条件的三位数')
我困了，题目3 你自己研究吧。。
# 1
def fun(a,n):
sum=0
for i in range(1,n+1):
sum+=int(str(a)*i)
return sum
# 2
def bitsum(n): #返回某个正整数各位数字之和
sum=0
tem=n
while(tem):
sum+=tem%10
tem=int(tem/10)
return sum
for i in range(100,1000):
s=set()
for j in range(5,8):
s.add(bitsum(i*j))
if(len(s)==1):
print("x=%d:x*3=%d,x*4=%d,x*5=%d,x*6=%d,x*7=%d"%(i,i*3,i*4,i*5,i*6,i*7))
# 3
def isLeap(n):
if((n%4==0 and n%100!=0) or n%400==0):
return True
return False
count=0
for n in range(1900,2021):
if(isLeap(n)):
print(n,end=' ')
count+=1
if(count%5==0):
print()
绛旓細5): if i!=j and j!=k and k!=i: print(i,j,k) total+=1print("鎬荤粍鍚堟暟锛", total)鎴栬咃紝浣犲彲浠ヤ娇鐢Python鐨itertools妯″潡绠鍖栭棶棰橈細import itertoolssum2 = 0a = [1,2,3,4]for i in
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