求大神详细分析运放+三极管输出10V电路的原理？ 急求“运放+三极管构成的恒流源的工作原理”

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此电路原理简要分析：运放组成电压比较器，正输入电压3.3V，负端电压也为3.3V(10V电压经R66电阻,晶体管Q4发射极电压10V,再经R59,R585,R47对10V分压得到电压3.3V.)此时如果因输入信号或其它原因造成运放输入信号变化,当正端输入信号略大于反向端信号时,运放输出近15V正电压,三极管Q4饱和导通,输出近10V电压.反之Q4截止时,输出+15V电压.

三极管Q4射级输出电压=3.3V*（R47+R55+R59)/R47=3.3V*（10000+20000+300）/10000=10V

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