高考数学必背公式整理
在应试教育中，只有多记公式，掌握解题技巧，熟悉各种题型，把自己变成一个做题机器，才能在考试中取得最好的成绩。
两角和公式
sin(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-sinBcosA
cos(A+B)=cosAcosB-sinAsinB
cos(A-B)=cosAcosB+sinAsinB
tan(A+B)=(tanA+tanB)/(1-tanAtanB)
tan(A-B)=(tanA-tanB)/(1+tanAtanB)
ctg(A+B)=(ctgActgB-1)/(ctgB+ctgA)
ctg(A-B)=(ctgActgB+1)/(ctgB-ctgA)
倍角公式
tan2A=2tanA/(1-tan2A) ctg2A=(ctg2A-1)/2ctga
cos2a=cos2a-sin2a=2cos2a-1=1-2sin2a
半角公式
sin(A/2)=√((1-cosA)/2) sin(A/2)=-√((1-cosA)/2)
cos(A/2)=√((1+cosA)/2) cos(A/2)=-√((1+cosA)/2)
tan(A/2)=√((1-cosA)/((1+cosA))
tan(A/2)=-√((1-cosA)/((1+cosA))
ctg(A/2)=√((1+cosA)/((1-cosA)) ctg(A/2)=-√((1+cosA)/((1-cosA))
绛旓細楂樿甯哥敤鏁板鍏紡 涓銆佷袱瑙掑拰鍏紡 1銆乻in锛坅+b锛=sinacosb+cosasinbsin锛坅-b锛=sinacosb-sinbcosa銆2銆乧os锛坅+b锛=cosacosb-sinasinbcos锛坅-b锛=cosacosb+sinasinb銆3銆乼an锛坅+b锛=锛坱ana+tanb锛/锛1-tanatanb锛塼an锛坅-b锛=锛坱ana-tanb锛/锛1+tanatanb锛夈4銆乧tg锛坅+b锛=锛坈tgactgb...
绛旓細楂樿蹇呭鏁板鍩烘湰鍏紡濡備笅锛氫竴銆佹暟瀛︿袱瑙掑拰鍏紡 1銆乻in(A+B)=sinAcosB+cosAsinBsin(A-B)=sinAcosB-sinBcosA 2銆乧os(A+B)=cosAcosB-sinAsinBcos(A-B)=cosAcosB+sinAsinB 3銆乼an(A+B)=(tanA+tanB)(1-tanAtanB)tan(A-B)=(tanA-tanB)/(1+tanAtanB)4銆乧tg(A+B)=(ctgActgB-1)/(ctg...
绛旓細cos(a)-cos(b)=-2sin(a+b2)sin(a-b2)4.浜屽嶈鍏紡 sin(2a)=2sin(a)cos(b)cos(2a)=cos2(a)-sin2(a)=2cos2(a)-1=1-2sin2(a)5.鍗婅鍏紡 sin2(a2)=1-cos(a)2 cos2(a2)=1+cos(a)2 tan(a2)=1-cos(a)sin(a)=sina1+cos(a)6.涓囪兘鍏紡 sin(a)=2tan(a2)1+tan...
绛旓細楂樿蹇呭鏁板鍏紡锛1銆佷笁瑙掑嚱鏁帮細sin(a+b)=sin(a)cos(b)+cos(a)sin(b)銆乧os(a+b)=cos(a)cos(b)-sin(a)sin(b)銆乼an(a+b)=(tan(a)+tan(b))/(1-tan(a)tan(b))銆乻in^2(a)+cos^2(a)=1銆1+tan^2(a)=sec^2(a)銆1+cot^2(a)=csc^2(a)2銆佸钩闈㈠嚑浣曪細鍕捐偂瀹氱悊锛歛^...
绛旓細鏁板鍏紡楂樿濡備笅锛1銆佷笁瑙掑嚱鏁板叕寮忥細 sin²胃 + cos²胃 = 1 tan胃 = sin胃/cos胃銆2銆佽搴﹀埗鍜屽姬搴﹀埗涔嬮棿鐨勮浆鎹細 瑙掑害鍒 = 寮у害鍒 脳 180/蟺 寮у害鍒 = 瑙掑害鍒 脳 蟺/180銆3銆佸渾涓庡渾鍛ㄧ殑鍏崇郴锛 鍦嗙殑闈㈢Н锛歋=蟺r² 鍦嗙殑鍛ㄩ暱锛欳=2蟺r 寮ч暱鍏紡锛歀 = 胃/2蟺 脳...
绛旓細1.涓夎鍑芥暟鍏紡锛氫袱瑙掑拰鍏紡 sin(A+B) = sinAcosB+cosAsinB sin(A-B) = sinAcosB-cosAsinB ?cos(A+B) = cosAcosB-sinAsinB cos(A-B) = cosAcosB+sinAsinB tan(A+B) = (tanA+tanB)/(1-tanAtanB)tan(A-B) = (tanA-tanB)/(1+tanAtanB)cot(A+B) = (cotAcotB-1)/(cotB+cotA...
绛旓細楂樹腑鐨勬暟瀛︽湁寰堝闇瑕佹垜浠啛璁扮殑鍏紡锛岃繖浜涙暟瀛︿腑鐨勫叕寮忓彲浠ュ府鍔╂垜浠湪楂樿冩暟瀛鐨勭瓟棰樹腑鏇村姞绠鍗曞鏄擄紝涓嬮潰鎴戜负澶у鏁寸悊浜嗕竴浜涢噸鐐鏁板鍏紡銆傞珮涓暟瀛﹀叕寮忓ぇ鍏 1銆佸嚱鏁扮殑鍗曡皟鎬 (1)璁緓1銆亁2[a,b],x1x2閭ｄ箞 f(x1)f(x2)0f(x)鍦╗a,b]涓婃槸澧炲嚱鏁;f(x1)f(x2)0f(x)鍦╗a,b]涓婃槸鍑忓嚱鏁....
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绛旓細楂樿冩暟瀛姒傜巼鍏紡濡備笅锛1銆佷簨浠剁殑姒傜巼鍏紡 P锛圓锛=n锛圓锛/n锛圫锛夛紝鍏朵腑n锛圓锛夎〃绀轰簨浠禔鍙戠敓鐨勫彲鑳芥э紝n锛圫锛夎〃绀烘牱鏈┖闂寸殑鎬绘暟銆2銆佹潯浠舵鐜囧叕寮 P锛圓|B锛=P锛圓鈭〣锛/P锛圔锛夛紝鍏朵腑P锛圓鈭〣锛夎〃绀轰簨浠禔鍜屼簨浠禕鍚屾椂鍙戠敓鐨勬鐜囷紝P锛圔锛夎〃绀轰簨浠禕鍙戠敓鐨勬鐜囥3銆佸叏姒傜巼鍏紡 P锛圓锛=危P锛...
绛旓細鏁板楂樿蹇呰鍏紡鏄冪敓鍦楂樿冩暟瀛绉戠洰涓繀椤荤啛鎮夊苟鑳藉杩愮敤鐨勪竴浜涘熀鏈叕寮忋備互涓嬫槸涓浜涘父瑙佺殑鏁板楂樿冨繀鑰冨叕寮忥細涓夎鍑芥暟锛氭寮﹀畾鐞嗭細a/sinA = b/sinB = c/sinC 浣欏鸡瀹氱悊锛歝² = a² + b² - 2abcosC 姝ｅ垏鐨勫畾涔夛細tan胃 = sin胃/cos胃 骞抽潰鍑犱綍锛氱洿绾跨殑鏂滅巼锛歬 = (y₂...
