python中判断素数的代码 python判断素数的程序

\u5224\u65ad\u4e00\u4e2a\u6570\u662f\u5426\u4e3a\u7d20\u6570python

1\u3001\u5b9a\u4e49\u5224\u65ad\u7d20\u6570\u7684\u51fd\u6570isPrime

import math


def isPrime(num):
sqt = int(math.sqrt(num))
for i in range(2, sqt + 1):
if num % i == 0:
return False
return True

2\u3001\u8c03\u7528\u51fd\u6570\u5e76\u6253\u5370\u7ed3\u679c
a = int(input("\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570\u5b57\uff1a"))
if isPrime(a):
print(a)
else:
print("\u4e0d\u662f\u7d20\u6570")

3\u3001\u9a8c\u8bc1\u7ed3\u679c
\uff081\uff09\u8f93\u5165\u7684\u662f\u7d20\u6570
\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570\u5b57\uff1a3
3
\uff082\uff09\u8f93\u5165\u7684\u4e0d\u662f\u7d20\u6570
\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570\u5b57\uff1a12
\u4e0d\u662f\u7d20\u6570

\u4ee5\u4e0b\u662f\u6c42100\u4ee5\u5185\u7d20\u6570\u7684\u4ee3\u7801\uff1a
i = 2;
while(i < 100):
j = 2;
while (j <= (i/j)):
if not (i%j):break
j = j +1
if(j > i /j):print (i," \u662f\u7d20\u6570")
i = i+1

num = int(input("请输入一个数字: "))
if num > 1:
for i in range(2,num):
if (num % i) == 0:
print(num,"不是质数")
print(i,"乘于",num//i,"是",num)
break
else:
print(num,"是质数")
else:
print(num,"不是质数")

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