y=2的x次方的绝对值sin2x
f(x)=(2cosx,1)(cosx,(√3)sin2x)=2(cosx)^2+(√3)sin2x
=1+cos2x+(√3)sin2x
=1+2(sin2x+π/6)
=1+2[sin2(x+π/12)]
故 m=π/12,n=1
绛旓細f(x)=|2sinx| f(-x)=|2sin(-x)| =|-2sinx| =|sin2x| =f(x)鎵浠ユ槸鍋跺嚱鏁
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