四年级数学题鸡兔同笼 小学四年级数学的鸡兔同笼应用题怎么作
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16\uff0e\u6674\u5929\u5171\u67096\u5929\u3002
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解答：
兔：94÷2-35 =12
鸡：35-12=23
求采纳哦！
鸡有两只脚，兔有四肢脚，因此可设鸡为x，兔为y；鸡跟兔共x+y只（题中已给），鸡脚跟兔脚共x+2y只（题中已给）；两个未知数，两个方程式可解出。
用假设法：
假设全部是鸡，那么一共有脚：30×2=60只
比实际有的脚的数量少了：84-60=24只
这是因为把兔当成鸡，每只少算了：4-2=2只脚
所以，有兔：24÷2=12只
有鸡：30-12=18只
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绛旓細楦″厰鍚岀,楦＄殑鍙暟鏄厰鐨4鍊,鍏辨湁180鍙剼銆傞浮銆佸厰鍚勬湁澶氬皯鍙 鍏180梅锛4+2脳4锛=180梅12 =15鍙 楦15脳4=60鍙
绛旓細楦″厰鍚岀 鏁欏鍐呭锛氫汉鏁欑増鍥涘勾绾ф暟瀛涓嬪唽鏁板骞胯銆婇浮鍏斿悓绗笺嬮浮鍏斿悓绗奸棶棰樻槸鎴戝浗鍙や唬钁楀悕瓒ｉ涔嬩竴銆傞氳繃瀛︿範瑙ｉ浮鍏斿悓绗奸棶棰橈紝鍙互鎻愰珮鎴戜滑鐨勫垎鏋愰棶棰樸佽В鍐抽棶棰樼殑鑳藉姏銆備緥棰橈細澶х害涓鍗冧簲鐧惧勾鍓嶏紝鎴戝浗鍙や唬鏁板鍚嶈憲銆婂瓩瀛愮畻缁忋嬩腑璁拌浇浜嗕竴閬撴暟瀛﹁叮棰橈紝杩欏氨鏄憲鍚嶇殑鈥滈浮鍏斿悓绗尖濋棶棰樸備功涓槸杩欐牱鍙欒堪鐨勶細...
绛旓細鍥犳锛岃剼鐨勬诲彧鏁47涓庢诲ご鏁35鐨勫樊锛屽氨鏄厰瀛愮殑鍙暟锛屽嵆47-35=12(鍙).鏄剧劧锛岄浮鐨勫彧鏁板氨鏄35-12=23(鍙)浜嗐傚亣璁炬硶 鍏堝亣璁惧畠浠叏鏄浮锛屾牴鎹瘡鍙浮鏈2鍙剼鍙互绠楀嚭鍦ㄥ亣璁句笅鍏辨湁鍑犲彧鑴氾紝鎶婅繖鏍峰緱鍒扮殑鑴氭暟涓庨涓粰鍑虹殑鑴氭暟鐩告瘮杈冿紝鐪嬪皯浜嗗灏.姣忓皯2鍙剼灏辫鏄庢湁涓鍙厰琚湅鎴愪簡楦★紱灏嗗皯...
绛旓細璁鍏鏈墄鍛橈紝鍒欓浮鏈(x+15)鍙 4x+2(x+15)=186 4x+2x+30=186 6x=156 x=26 x+15=26+15=41(鍙級绛旓細楦℃湁41鍙紝鍏旀湁25鍙
绛旓細灏忓鍥涘勾绾鐨勯锛屾病鏈夊鏂圭▼锛屾墍浠ュ彧鑳介潬鍒嗘瀽娉曟潵瑙ｅ喅姝ら锛岄敾鐐煎瀛愪滑鐨勫垎鏋愯兘鍔涖傝В浣撳涓嬶細1銆佸亣濡傞浮鍜屽厰閮芥寜鐓2鍙剼绠楋紝搴旇鍏辨湁30鍙猉2涓/鍙=60涓剼 2銆侀偅涔堝鍑虹殑86-60=26涓剼鑲畾鏄墍鏈夌殑鍏斿瓙澶氬嚭鐨勮剼 3銆佷篃灏辨槸璇达紝姣忎釜鍏斿瓙鑳藉2涓剼锛屽洜姝ゅ厰瀛愮殑鏁伴噺涓猴細26/2=13鍙 閭ｄ箞楦＄殑鏁伴噺...
绛旓細瑙ｏ細璁鹃浮鏈墄鍙紝鍒鍏鏈夛紙18-x)鍙紝鏍规嵁棰樻剰寰楋細2x+4(18-x)=42 瑙ｈ繖涓柟绋嬪緱锛歺=15 18-x=3 绛旓細楦℃湁15鍙紝鍏旀湁3鍙
绛旓細瑙ｏ細浠“鍒”浣滀负閽辩殑鍗曚綅.鎴戜滑璁炬兂锛屼竴绉“楦”鏈11鍙剼锛屼竴绉“鍏斿瓙”鏈19鍙剼锛屽畠浠叡鏈16涓ご锛280鍙剼.鐜板湪宸茬粡鎶婁拱閾呯瑪闂锛岃浆鍖栨垚“楦″厰鍚岀”闂浜.鍒╃敤涓婇潰绠楀厰鏁板叕寮忥紝灏辨湁 钃濈瑪鏁=(19×16-280)÷(19-11)=24÷8...
