高中物理
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\uff081\uff09f=F=P\u989d/V\u6700\u5927=80000/20=4000N \u6240\u4ee5\uff0c\u963b\u529b\u4e3a4000\u725b\u3002
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F\u2032=f+ma=4000+2000\u00d72=8000N
\u2234P\u2032=FV\u2032=8000\u00d76=48000W \u22343s\u672b\u7684\u529f\u7387\u4e3a48000W\u3002
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V\u3003=P\u989d/F\u2032=80000/8000=10m/s\uff0ct=V\u3003/a=10/2=5s
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\u7ecf\u53d7\u529b\u5206\u6790\u5f97\uff1a\u2211W=W\u7275\u5f15\u529b
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\u53e6\u5916\uff1a\u5b66\u7269\u7406\u4e00\u5b9a\u8981\u4ed4\u7ec6\u60f3\uff0c\u8ba4\u771f\u5206\u6790\uff0c\u8001\u5e08\u66fe\u544a\u8beb\u6211\uff1a\u4e0d\u8981\u88ab\u7269\u7406\u5413\u5230\uff0c\u56e0\u4e3a\u5b83\u5e76\u4e0d\u53ef\u6015\uff01
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设时间为t
体积S*Vt
电荷数N=(SVt)n
总电荷量Q=Nq=(SVt)nq
电流：
I=Q/t
=(SVt)nq/t
=nqSV
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绛旓細楂樹腑鐗╃悊鍏紡鏈夛細楂樹腑鐗╃悊鍏紡涓銆佸寑鍙橀熺洿绾胯繍鍔 1銆佸钩鍧囬熷害V骞=s/t锛堝畾涔夊紡锛2銆佹湁鐢ㄦ帹璁篤t2-Vo2=2as 2銆佷腑闂存椂鍒婚熷害Vt/2=V骞=(Vt+Vo)/2 4銆佹湯閫熷害Vt=Vo+at 3銆佷腑闂翠綅缃熷害Vs/2=[(Vo2+Vt2)/2]1/2 6銆佷綅绉籹=V骞硉=Vot+at2/2=Vt/2t 4銆佸姞閫熷害a=(Vt-Vo)/t{浠o涓烘...
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