大学数学，线性代数如图，求详细手写图片答案。 线性代数 可以手写答案发图片
\u5927\u5b66\u6570\u5b66\uff0c\u7ebf\u6027\u4ee3\u6570\u5982\u56fe\uff0c\u6c42\u8be6\u7ec6\u624b\u5199\u56fe\u7247\u7b54\u6848\u2026\u2026\u7b54\u6848\u662f-12\u2026\u2026\u6211\u7684\u8fc7\u7a0b\u54ea\u91cc\u6709\u9519\u2026\u2026\uff1f\u52a0\u5230\u67d0\u4e00\u884c\uff0c\u8fdb\u884c\u521d\u7b49\u53d8\u6362\uff0c\u4f60\u7b2c\u4e00\u6b65\u5c31\u52a0\u9519\u4e86
\u7cfb\u6570\u77e9\u9635\u884c\u5217\u5f0f |A| =
|\u03bb 1 1|
|1 \u03bb 1|
|1 1 \u03bb|
|A| =
|\u03bb+2 1 1|
|\u03bb+2 \u03bb 1|
|\u03bb+2 1 \u03bb|
|A| =
|\u03bb+2 1 1|
|0 \u03bb-1 1|
|0 1 \u03bb-1|
|A| = (\u03bb+2)(\u03bb-1)^2
\u5f53 \u03bb \u2260 -2 \u4e14 \u03bb \u2260 1 \u65f6\uff0c|A| \u2260 0\uff0c\u65b9\u7a0b\u7ec4\u6709\u552f\u4e00\u89e3\u3002
\u5f53 \u03bb = -2 \u65f6, (A,b) =
[-2 1 1 1]
[ 1 -2 1 -2]
[ 1 1 -2 4]
\u884c\u521d\u7b49\u53d8\u6362\u4e3a
[ 1 1 -2 4]
[ 0 3 -3 9]
[ 0 -3 3 -6]
\u884c\u521d\u7b49\u53d8\u6362\u4e3a
[ 1 1 -2 4]
[ 0 1 -1 3]
[ 0 0 0 1]
r(A,b)=3, r(A)=2, \u65b9\u7a0b\u7ec4\u65e0\u89e3\u3002
\u5f53 \u03bb = 1 \u65f6, (A,b) =
[ 1 1 1 1]
[ 1 1 1 1]
[ 1 1 1 1]
\u884c\u521d\u7b49\u53d8\u6362\u4e3a
[ 1 1 1 1]
[ 0 0 0 0]
[ 0 0 0 0]
r(A,b) = r(A) = 1 < 3, \u65b9\u7a0b\u7ec4\u6709\u65e0\u7a77\u591a\u89e3
\u6b64\u65f6\uff0c\u7279\u89e3\u662f (1 0 0)^T,
\u5bfc\u51fa\u7ec4 x1+x2+x3 = 0
\u7684\u57fa\u7840\u89e3\u7cfb\u662f (1 -1 0)^T, (1 0, -1)^T
\u901a\u89e3\u662f x = (1 0 0)^T+k(1 -1 0)^T+c(1 0, -1)^T\uff0c
\u5176\u4e2d k\uff0cc \u4e3a\u4efb\u610f\u5e38\u6570\u3002
然后2,3,4行依次减去第一行，那么2,3,4行除了对角线元素为λ，其余都是0
行列式的值为(λ+4)λ^3=0
该方程的根为λ1=λ2=λ3=0，λ4=-4
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