C语言编程题，求解答 C语言编程题，求解答！（要求写出详细注释）
c\u8bed\u8a00\u7f16\u7a0b\u9898 \u6c42\u89e3\u7b54\u600e\u4e48\u505a\u554a\u6709\u4e00\u4e2a\u975e\u5e38\u4f4e\u6548\u7684\u65b9\u6cd5\uff0c\u4e0d\u8fc7\u80fd\u7b97\u51fa\u6765\uff1a
#include #include int main() {int a, b, c, d, e, f;for (a = 2; a <= 6; a++) {for (b = 1; b <= 6; b++) {for (c = 1; c <= 6; c++) {for (d = 1; d <= 6; d++) {for (e = 1; e <= 6; e++) {for (f = 1; f <= 6; f++) {if ((abs(a - b) == 1) && (d - c == 1) && (b - e == 2) && (c - f == 4) && (a != b) && (a != c) && (a != d) && (a != e) && (a != f) && (b != c) && (b != d) && (b != e) && (b != f) && (c != d) && (c != e) && (c != f) && (d != e) && (d != f) && (e != f)) {printf("A: %d\nB: %d\nC: %d\nD: %d\nE: %d\nF: %d\n", a, b, c, d, e, f);}}}}}}}return 0;}
\u7ed3\u679c\u4e3a\uff1a
\u4e0d\u8fc7\u5982\u679c\u4e0d\u662f\u5fc5\u8981\u7684\u8bdd\uff0c\u975e\u5e38\u4e0d\u5efa\u8bae\u5728\u666e\u901a\u7a0b\u5e8f\u4e2d\u4f7f\u7528\u592a\u591a\u7684\u5faa\u73af\u5d4c\u5957\uff08\u6700\u597d\u4e0d\u8981\u8d85\u8fc7 3 \u4e2a\uff09\u3002
#include
void main()
{
int in[15],ins,i,k=14,j=0;
printf("\u8bf7\u6309\u7167\u4ece\u5c0f\u5230\u5927\u7684\u987a\u5e8f\u8f93\u516515\u4e2a\u6570\n");
for(i=0;i<15;i++) scanf("%d",&in[i]);
printf("\u8bf7\u8f93\u5165\u8981\u67e5\u627e\u7684\u6570:");
scanf("%d",&ins);
i=(j+k)/2;
while(j<=k)
{
if(in[i]>ins)
k=i-1;
else
if(in[i]<ins)
j=i+1;
else break;
i=(j+k)/2;
}
printf("\u4f60\u67e5\u627e\u7684\u662f\u5176\u4e2d\u7684\u7b2c%d\u4e2a\u6570\u3002",i+1);/*i\u662f\u4ed6\u7684\u5b58\u50a8\u7684\u987a\u5e8f\u6570\uff0ci+1\u624d\u662f\u4ed6\u5728\u8f93\u5165\u6570\u7ec4\u4e2d\u7684\u4f4d\u7f6e\u6570*/
}
就是说有可能在线程序只运行一次你的程序，然后连续输入两个数据，看输出是否正确，而你的程序只判断一个数字，所以第一个数字正确，而当在线程序输入第二个数字时你的程序已经结束退出，所以无法通过测试样例。
你可以试试让程序循环输入判断，看是否可以通过
没啥问题
for(i=2;i<=sqrt(m);i++)
{
if(m%i == 0 )
{
flag=0;
printf("No!");
break;//最好有
}
}
#include<stdio.h>
#include<math.h>
int main()
{
int i,m,flag=1;
scanf("%d",&m);
for(i=2;i<=SQRT（M）;i++)
{
if(m%i == 0 )
{
flag=0;
printf("No!");BREAK；
}
}
if(flag==1)
printf("The number is:%d",m);
return 0;
}
最后那个IF没有定条件
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