C语言编程：输入一串字母,统计每个字母出现的次数
\u7f16\u7a0b\u7279\u60e0\u6765\u88ad,\u4ef7\u4f4e\u8d28\u4f18\u8d2d\u5f97\u5b89,\u670d\u52a1\u5b8c\u5584\u5fc3\u66f4\u751c #include<stdio.h>void
main()
{
char
ch;
//ch用来每次接收一个字符
int
i,s[26]={0};
//数组s[]用来统计每个小写字母的个数
printf("please
input
a
string:\n");
scanf("%c",&ch);
while(ch!='\n')
//输入一行字符，以回车键结束
{
if(ch>'A'&&ch<'Z')
//遇到大写字母时，转换成小写来处理
ch+=32;
s[ch-'a']++;
//0~25对应a~z
scanf("%c",&ch);
}
printf("\n");
for(i=0;i<26;i++)
if(s[i])
//只输出输入过的字母统计
printf("%c:%d\n",(char)(i+'a'),s[i]);
//(char)(i+'a')用强制类型转换，输出对应字母
}
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绛旓細1銆佽鍏ュ瓧绗︼紝鐩村埌閬囧埌鎹㈣缁撴潫銆2銆佸浜庢瘡涓瓧绗︼紝鍒ゆ柇鏄瀛楁瘝杩樻槸鏁板瓧锛屾垨鑰呮槸鍏跺畠瀛楃銆3銆佸浜庢瘡涓瓧绗﹀垽鏂悗锛屽搴旂被鍒鏁板櫒鑷姞銆4銆佹渶缁堣緭鍑虹粨鏋溿備笁銆佸弬鑰冧唬鐮侊細include <stdio.h>int main(){ int a,b,c,ch; a=b=c=0;//璁℃暟鍣ㄥ垵濮嬪寲涓0. while((ch=getchar())!='\n')...
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