x的三次方减二x^2+2+x-+1的因式分解？ x的三次方减x的二次方减1因式分解
x\u7684\u4e09\u6b21\u65b9\u51cfx\u76842\u6b21\u65b9\u51cfx\u52a01\u3002\u56e0\u5f0f\u5206\u89e3\u600e\u4e48\u505a\uff1f\u89e3\uff1a
x\u7684\u4e09\u6b21\u65b9\u51cfx\u76842\u6b21\u65b9\u51cfx\u52a01=xxx-xx-x+1=\uff08xxx+1\uff09-\uff08xx+x\uff09=\uff08x+1\uff09\uff08xx-x+1\uff09-x(x+1)=(x+1)(xx-x+1-x)=(x+1)(xx-2x+1)=(x+1)(x-1)(x-1)
\u4eb2\uff0c\u8bf7\u60a8\u91c7\u7eb3\uff0c\u60a8\u7684\u91c7\u7eb3\u662f\u6211\u7684\u52a8\u529b\uff0c\u8c22\u8c22\u3002
x³-x²+X-1
=x²(x-1)+(x-1)
=(x-1)(x²+1)
=(x-1)(x²+x+1)-2x(x-1)
=(x-1)(x²+x+1-2x)
=(x-1)(x²-x+1)
X^3-X^2+X-1
=X^2*（X-1）+X-1
=（X^2+1）*（X-1）
绛旓細x^3-2x^2-3x=0 x(x^2-2x-3)=0 x(x-3)(x+1)=0 x=0 x=-1 x=3
绛旓細=x²-1-4/(x-2)
绛旓細(2x+3)(x²-7x+12)=0 (2x+3)(x-3)(x-4)=0 x1=-3/2,x2=3,x3=4
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绛旓細x^3-x^2-x-2=0,x^4+2x^3-2x^2+x-1=(x^3-x^2-x-2)(x+3)+2x^2+6x+5=2x^2+6x+5,姹傝繎浼煎硷紝鍙互鍚楋紵
绛旓細x鐨勪笁娆℃柟鍑2X鐨浜屾鏂鍐嶅姞1=x鐨勪笁娆℃柟-X鐨勪簩娆℃柟-X鐨勪簩娆℃柟+1 锛漻鐨勪笁娆℃柟-X鐨勪簩娆℃柟-锛圶鐨勪簩娆℃柟锛1锛夛紳X鐨勪簩娆℃柟锛圶锛1锛夛紞锛圶+1锛夛紙X锛1锛夛紳锛圶锛1锛夛紙X鐨勪簩娆℃柟锛峏锛1锛
绛旓細鐨勪笁娆℃柟鍑忓幓浜鍊x =x(x²-2)=x(x+鈭2)(x-鈭2)鏍瑰彿4.9 =鈭(49/10)=鈭(49*7)/鈭70 =(鈭7)^3/(鈭70)宸茬煡a=鏍瑰彿7,b=鏍瑰彿70 鎵浠ュ師寮=a^3/b
绛旓細x^3-x^2=x^2*(x-1)
绛旓細x^3-2x^2+3<0 x^3+x^2+3-3x^2<0 [x^2+3(1-x)](x+1)<0 x^2-3x+3=(x-3/2)^2+3/4>0 =>x+1<0 =>x<-1
