C语言用while写出1-2+3-4+5-6...+N的合 1-2+3-4+5-6+...-100用c语言的中while...

\u5173\u4e8e\u4e00\u4e2ac\u8bed\u8a00\u7684\u95ee\u9898\uff0c\u7528while\u5faa\u73af\u8ba1\u7b971-2+3-4+5-6+7-8...n

a\u6ca1\u6709\u5b9a\u4e49\uff0c\u5e76\u4e14\u4f60\u8ba1\u7b97\u7684\u662f1+2+3+....
\u4e0d\u9700\u8981\u7528\u5230a\uff0c\u4fee\u6539\u5982\u4e0b\uff1a
while (b < n)
{
b++;
//\u4f7f\u7528\u4e09\u5143\u8fd0\u7b97\u7b26\uff0c\u5982\u679cb\u662f\u5076\u6570\uff0c\u5219-b\uff1b\u5426\u5219+b
sum += b % 2 == 0 ? -b : b;
}

#include #include main(){ int i = 1; sum = 0; while (i <= 100) { sum += i * pow(-1, i - 1); i++; } printf("%d", sum);}

#include <stdio.h>


int main(void) /* 1-2+3-4+5-6...+N */

{

int this = 1; /* 运算起始 */

int n;

scanf("%d", &n); /* 输入N的值 */

int sum = 0;

while (this <= n) {

if (this%2 == 0) /* 是合数 */

sum -= this;

else /* 是基数 */

sum += this;

this ++; /* this递增 */

}

printf("%d
", sum);

return 0;

}

给分吧!



int func(int n) {  // n 为传进来的计算上限
    int plus = 1;  // 标记+还是-,第一个用+, 即式子视为:+1-2+3-4+5-6...+n
    int count = 1; // 从1开始循环
    int sum = 0;
    while(count <= n) {
        if (plus == 1) {
            sum += count;
        } else {
            sum -= count;
        }
        plus = plus == 1 ? 0 : 1; // 切换+-
        ++count;
    }
    return sum; // 返回结果
}


int i = 1;
int n = 20000;
int sum = 0;
int flag = 0;
while( i < n )
{
flag = !flag;
if ( flag )
sum = sum + i;
else
sum = sum - i;

i++;
}

get_sum(int N)
{
int i = 1,x=1,sum=0;
while(i <= N)
{
sum += (x?i:-i);
x = x?0:1; //每次运算,x取反,控制运算符号
i++;
}
return (sum);
}

int i = 0;
int sum = 0;
while (++i)
{
sum += (i%2==0?-1*i:i);
}

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