用SQL命令查询数据库这门课排名前5的同学的学号和成绩若成绩相同按学号升序排列 SQL向每个学生的总成绩,输出学号和总成绩,按总成绩排序(降...

SQL\u6570\u636e\u5e93\uff1a\u67e5\u8be2\u8bfe\u7a0b\u53f7\u4e3a\u201c203402\u201d\u7684\u6210\u7ee9\u6700\u9ad8\u7684\u524d5\u540d\u5b66\u751f\u7684\u5b66\u53f7\u53ca\u6210\u7ee9\uff0c\u7ed3\u679c\u6309\u6210\u7ee9\u964d\u5e8f

--\u4e0d\u660e\u767d\u968f\u65f6\u95ee\u6211
select SNO,\u6210\u7ee9 from (
select SNO,\u6210\u7ee9,row_number() over (order by \u6210\u7ee9 desc)*1 bz from tbname where CNO='203402') aa where aa.bz<=5
order by \u6210\u7ee9 desc

select xuehao as \u5b66\u53f7,score as \u603b\u6210\u7ee9 from CJB
where xuehao in(select xuehao from XSB)
group by xuehao,score
order by score desc,xuehao

sql server:
select top 5 学号,成绩
from 成绩表
where 课程名=‘数据库’
order by 成绩 desc,学号

oracle :
select 学号,成绩
from 成绩表
where 课程名=‘数据库’and rownum<=5
order by 成绩 desc,学号

select top 5 学号,学生,成绩
from 成绩表
where 课程名
order by 成绩 desc,学号

select 学号,成绩, from 学科成绩表 order by 成绩 desc,by 学号

select top 5 *
from student
order by score desc,no asc
no asc的asc可以省略,因为默认是asc的

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