vb字符串截取前四位放在一个变量里 后面放在一个变量里 vb里面一个变量里的字符怎么拆分成几个变量,A变量里德字符都...

vb \u4e2dstring \u7c7b\u578b\u7684\u53d8\u91cf\u5982\u4f55\u628a\u5b57\u7b26\u4e32\u7684\u7b2c\u4e00\u4e2a\u5b57\u7b26\u5355\u72ec\u53d6\u51fa

a="ABCDE"
b=left(a,1)
print b

\u8fd0\u884c\u540e\uff0c\u6253\u5370\u51fab\u7684\u503c\uff0c\u5373"A"\u3002

\u4e3b\u8981\u5c31\u662f\u7528split\u62c6\u6210\u6570\u7ec4\uff0c\u6bd4\u5982
dim arr
str="[01][\u5927\u5f3a][\u8bed\u658785][\u6570\u5b6690][\u82f1\u8bed80][\u7269\u740679][\u4f53\u80b2B][\u64cd\u884c\u8bc4\u52067][0]"
str=replace(str,"][",",") \u5c06][\u66ff\u6362\u4e3a,
str=replace(str,"]","") \u6e05\u6389]
str=replace(str,"[","")\u6e05\u6389[
arr=split(str,",")
\u8fd9\u6837arr\u6570\u7ec4\u4e2d\u5c31\u4fdd\u5b58\u4e86\u5404\u9879\u503c\uff0c\u6bd4\u5982arr(0)\u5c31\u662f01\uff0carr(2)\u662f\u5927\u5f3a

' 获取前四位字符.
a1 = Left$(S, 4)

' 获取剩下的字符.
a2 = Right$(S, Len(S) - 4)


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