怎么编写:输入一个字符串,并将字符串反转,如“abcd”反转成“dcba” 定义将一个字符串反转的函数,例如将字符abcd反转为dcba

\u5b9a\u4e49\u4e00\u4e2a\u5b57\u7b26\u4e32\u53cd\u8f6c\u51fd\u6570\uff0c\u4f8b\u5982\u5c06\u5b57\u7b26\u4e32\u201cabcd\u201d\u53cd\u8f6c\u4e3a\u201cdcba\u201d\u3002

#include
#include

// \u5b66\u7f16\u7a0b \u6b22\u8fce\u5230 \u777f\u817e\u7f16\u7a0b.\u7f51

void reverse(char* str)
{
int len = strlen(str);
int times = len / 2;
char temp;
int i;
for (i=0; i<times; i++)
{
temp = str[i];
str[i] = str[len-i-1];
str[len-i-1] = temp;
}
}


int main()
{
char num[] = "abcd";

reverse(num);
puts(num);

return 0;
}

char * mystrrev ( char * string )
{
char *start = string;
char *left = string;
char ch;

while (*string++) /* find end of string */
;
string -= 2;

while (left < string)
{
ch = *left;
*left++ = *string;
*string-- = ch;
}

return(start);
}

/////////////////cabs. vc\u5b57\u7b26\u4e32\u9006\u8f6c

#include

char* rstr(char* a)
{
char* p1, *p2, t;
p1 = p2 = a;
while(*p2) ++p2;
while(p1 < p2) {
t = *p1;
*p1++ = *--p2;
*p2 = t;
}
return a;
}


int main()
{
char a[] = "abcd";
puts(rstr(a));
}

java的话,new个String Buffer,直接调函数。
自己写的话,可以重新new个String,for 循环加--length的字符就行。不过内存耗费大,用char数组来处理,用首尾俩个游标,low<high,low++,high--,互换

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