4道高一的化学计算题.很急!!! 一道高一化学计算题
\u9ad8\u4e00\u5316\u5b66\u8ba1\u7b97\u9898 \u6025\u6025\u6025!!2NaHCO3=Na2CO3+H2O+CO2
\u51cf\u5c11\u7684\u8d28\u91cf\u76f8\u5f53\u4e8e\u662fH2CO3\u7684\u8d28\u91cf\uff0c\u5219\uff083.8-3.18\uff09/62=0.01mol
\u6240\u4ee5NaHCO3\u7269\u8d28\u7684\u91cf\u662f0.02mol\uff0c1.68g\u3002
\u78b3\u9178\u94a0\u7684\u8d28\u91cf\u5206\u6570\u4e3a(3.8-1.68)/3.8=55.79%
\u7528X\u4ee3\u8868\u94a0\u548c\u94be
XHCO3+HCl=XCl+H2O+CO2
\u8bbe\u78b3\u9178\u6c22\u94a0\u548c\u78b3\u9178\u6c22\u94be\u7269\u8d28\u7684\u91cf\u5206\u522b\u4e3aA\u3001B
84A+100B=9.2
A+B=2.24/22.4
A=0.05 B=0.05
\u6240\u4ee5\u5b83\u4eec\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u662f1\uff1a1
\u5148\u5199\u5316\u5b66\u65b9\u7a0b\u5f0f\uff0cAl +3HCl =AlCl3 + 1.5H2
Al + H2O +NaOH =NaAlO2 +1.5H2
\u5047\u8bbe\u94dd\u4e0d\u8db3\uff0c\u5219\u6c22\u6c14\u6bd4\u4e3a1\uff1a1\uff0c\u5047\u8bbe\u94dd\u8fc7\u91cf\uff0c\u5219\u6c22\u6c14\u6bd4\u4e3a1\uff1a3
\u800c\u9898\u76ee\u662f1\uff1a2\uff0c\u6240\u4ee5\u94dd\u5728\u9178\u4e2d\u8fc7\u91cf\uff0c\u5728\u6c22\u6c27\u5316\u94a0\u4e2d\u4e0d\u8db3\uff0c\u9009\u62e9\u7b2c\u4e8c\u4e2a\u53cd\u5e94\u5f0f\u8ba1\u7b97\u6c22\u6c14\u7684\u8d28\u91cf\u3002\u56e0\u4e3a\u9178\u662f\u5b8c\u5168\u53cd\u5e94\u7684\uff0c\u6839\u636e\u6d53\u5ea6\u53ef\u77e5\u548c\u9178\u53cd\u5e94\u653e\u51fa0.15mol \u7684\u6c22\u6c14\uff0c\u6240\u4ee5\u6839\u636e1\uff1a2\u53ef\u77e5\u5728\u6c22\u6c27\u5316\u94a0\u4e2d\u653e\u51fa0.3mol\u7684\u6c22\u6c14\u3002\u6839\u636e\u53cd\u5e94\u5f0f\u7684\u6bd4\u4f8b\u7cfb\u6570\u53ef\u77e5\u67090.2mol \u7684\u94dd\u3002\u53735.4\u514b\u3002
则NaOH溶液的物质的量浓度为： 1000（m/40）/V
2、设混合气体中氧气的物质的量为Xmol,氮气为Ymol
则 32X+28Y=10
(X+Y)*22.4=7.8
解上面的方程组可得 X=0.12，则混合气体中氧气质量为0.12*32=3.84g
3、设原混合物中MgCl2的物质的量为Xmol,NaCl为Ymol
则 95X+58.5Y=49.7
1000(2X+Y)/600=1.667
解方程组得到X MgCl2的质量为95X
4、 设盐酸浓度为X
盐酸和氢氧化钠反应的摩尔比是1：1
HCL+NaOH=NaCL+H2O
1 1
25X 20*0.8
则X=0.64mol/L
同样 盐酸和氢氧化钾反应也的摩尔比也是1：1
可得不纯的氢氧化钾溶液中含有氢氧化钾的物质的量为 0.64*0.02=0.0128mol
故混合氢氧化钾中含有氢氧化钾的质量为0.0128*56=0.7168g
则氢氧化钾纯度为 0.7168/8=89.6%
1.c=n（NaOH）/V=（m/40)/（（ρ水V+m）/ρ）
2.可以用十字交叉法
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绛旓細浠呬緵鍙傝
