c语言高手来帮忙
C\u8bed\u8a00\u9ad8\u624b\u6765~~~1\u3001#include
#define N 10
main()
{
int i,j,a[N]={1,3,4,6,7,9,10,14,18};
int number;
scanf("%d",&number);
for(i=0;i<N-1;i++)
if(number<a[i])
break;
for(j=N-2;j>=i;j--)
a[j+1]=a[j];
a[i]=number;
for(i=0;i<N;i++)
printf("%5d",a[i]);
printf("\n");
}
2\u3001#include
#define N 5
main()
{
int i,j,a[N]={8,6,5,4,1};
for(i=0;i<N;i++)
printf("%5d",a[i]);
printf("\n");
for(i=0;i<=(N-1)/2;i++)
{
int temp;
temp=a[i];
a[i]=a[N-1-i];
a[N-1-i]=temp;
}
for(i=0;i<N;i++)
printf("%5d",a[i]);
printf("\n");
}
3\u3001#include
#define N 15
main()
{
int i; //\u5faa\u73af\u53d8\u91cf
int a[N]={30,29,28,26,25,24,20,19,18,15,14,12,10,8,5};
int low=0,up=N-1,middle; //\u6bcf\u6b21\u67e5\u627e\u7684\u533a\u95f4\u4e0a\u4e0b\u9650\u53ca\u533a\u95f4\u7684\u4e2d\u95f4\u5143\u7d20\u4e0b\u6807
int number;
int flag=0;
scanf("%d",&number);
while(low<=up)
{
middle=(up+low)/2;
if(number<a[middle])
low=middle+1;
else
{
if(number==a[middle])
{
flag=1;
break;
}
else
up=middle-1;
}
}
if(flag==1)
printf("the number is found.It's location is a[%d] \n",middle);
else
printf("the number is not found.\n");
}
4\u3001#include
#include
main()
{
int i,j;
char string1[80],string2[20];
gets(string1);
gets(string2);
i=0;
while(string1[i]!='\0')
i++;
j=0;
while(string2[j]!='\0')
string1[i++]=string2[j++];
string1[i]='\0';
puts(string1);
}
5\u3001#include
#define N 10
main()
{
int i,j,a[N][N];
for(i=0;i<N;i++)
{
a[i][0]=1;
a[i][i]=1;
}
for(i=2;i<N;i++)
for(j=1;j<i;j++)
a[i][j]=a[i-1][j-1]+a[i-1][j];
for(i=0;i<N;i++)
{
for(j=0;j<=i;j++)
printf("%5d",a[i][j]);
printf("\n");
}
}
\u8fd0\u884c\u7ed3\u679c\u90fd\u662f\u5bf9\u7684\uff0c\u6211\u8bd5\u8fc7\u4e86
\u5173\u952e\u662f\u627e\u5230\u77e9\u9635\u6392\u5e03\u7684\u89c4\u5f8b
\u4e5f\u5c31\u662f\u533a\u5206\u5947\u6570\u884c\u548c\u5076\u6570\u884c
#includeint main(){int row = 1,col = 1;while(row != 9){while(col != 9){printf("%2d,", (row - (row % 2 == 1 ? 1 : 0)) * 8 + (col + (row % 2 == 1 ? 0 : -1)) * (row % 2 == 1 ? 1 : -1));//\u8fd9\u91cc\u662f\u5173\u952e\uff01col++;}printf("\n");col = 1;row++;}return 0;}
以上程序代码的功能是：
检查一片文档中“回车”的数目，也就是讲，求的是文档中段落的数目。
把EOF改成 "\0"就可以了啊
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