一道化学选择题，在线等。
\u4e00\u9053\u5316\u5b66\u7684\u9009\u62e9\u9898A 22.4nb/mNA
m\u514b\u542b\u6709b\u4e2a\u5206\u5b50,\u6240\u4ee5\u6bcf\u514b\u542b\u6709b/m\u4e2a\u5206\u5b50,
n\u514b\u542b\u6709nb/m\u4e2a\u5206\u5b50
n\u514b\u8be5\u6df7\u5408\u6c14\u4f53\u7269\u8d28\u7684\u91cf\u4e3a(nb/m)/NA
\u56e0\u4e3a\u5728\u6807\u51c6\u72b6\u51b5\u4e0b,1mol\u4f53\u79ef\u4e3a22.4L
\u6240\u4ee5n\u514b\u8be5\u6df7\u5408\u6c14\u4f53\u5728\u76f8\u540c\u72b6\u51b5\u4e0b\u6240\u5360\u7684\u4f53\u79ef\u5e94\u662f
22.4*(nb/m)/NA=22.4nb/mNA
\u7b54\u6848D
A \u539f\u5b50\u80fd \u5c31\u662f\u88c2\u53d8\u554a \u5267\u53d8\u4ec0\u4e48\u7684 \u8fd9\u4e2a\u4e0d\u662f\u5316\u5b66\u53d8\u5316
B \u6f6e\u6c50 \u5c31\u662f\u6d77\u6c34\u6da8\u6f6e\u7684\u65f6\u5019\u91cd\u529b\u52bf\u80fd\u53d8\u4e3a\u7535\u80fd
C \u98ce\u80fd\u5e94\u8be5\u61c2\u554a
D \u751f\u7269\u80fd\u5c31\u662f \u592a\u9633\u80fd\u901a\u8fc7\u7eff\u8272\u690d\u7269\u7684\u5149\u5408\u4f5c\u7528\u8f6c\u6362\u6210\u5316\u5b66\u80fd\uff0c\u50a8\u5b58\u5728\u751f\u7269\u4f53\u5185\u90e8\u7684\u80fd\u91cf\u3002
反应还可以水解产生H+.强酸跟弱碱反应后溶液呈碱性，氨水要水解
强酸弱碱呈碱性，强碱弱酸呈酸性。越弱越水解 选D
B PH=3 的盐酸跟PH=11的氨水
B中，实际不是恰好反应的，氨水远远过量。因为电离出OH-浓度为0。001mol/L实际NH3.H20远大于0。001mol/L
绛旓細鏌愯剛鑲吀CmHnCOOH 0.1mol涓庣瀹屽叏鍙嶅簲锛岄渶纰0.2mol锛岋紞锛嶇儍鍩哄彧鑳藉鐨勪笉楗卞拰搴︿负2锛宯=2m-3 0.1mol璇ヨ剛鑲吀瀹屽叏鐕冪儳鏃朵骇鐢熶簩姘у寲纰冲拰姘寸殑鐗╄川鐨勯噺涔嬪拰涓3.4mol锛嶏紞m+1+(n+1)/2=34 瑙ｄ笂闈㈢殑鏂圭▼寮忥紝寰楀埌 B 瀹為檯涓婏紝浠呮牴鎹涓涓叧绯伙紝宸茬粡鍙互鍒ゆ柇鎺掗櫎A鍜孋浜 ...
绛旓細绗涓閬撻夋嫨D銆傘傚洜涓篈閫夐」涓哄己閰告憾娑诧紝鍙舰鎴愮閰告哀鍖栦簩浠烽搧锛孊閫夐」鏄⒈鎬ф憾娑诧紝鑳戒笌閾垫牴鍙嶅簲鐢熸垚姘斾綋锛孋閫夐」鑳戒笌閾濈敓鎴愭阿姘旂殑鍙互鏄吀鎬т篃鍙互鏄⒈鎬э紝閰告х殑鎯呭喌涓嬬敓鎴愮閰革紝浼氭哀鍖栨隘绂诲瓙銆侱閫夐」鏈夊ぇ閲忕⒊閰告牴鐨勬憾娑叉槸纰辨э紝姝ゆ潯浠朵笅閮借兘瀛樺湪 绗簩閬 A姝ｇ‘锛屾隘姘斿湪纰辨ф憾娑茬敓鎴愯礋涓浠风殑姘瀛愶紝杞Щ...
绛旓細閫堿銆侰O2鑻ヤ笉鑳藉強鏃舵帓鍑,PH灏嗗噺灏,鏄鹃吀鎬.鍥犱负CO2涓庝綋鍐匟2O缁撳悎鐢熸垚H2CO3
绛旓細鍥犱负鐢熸垚娌夋穩0.01mol锛屾墍浠 0.01mol:1mol=d:1mol 鎵浠=0.01mol 鎵浠 NaOH=(d+0.02+c)mol/0.5mol/L=(0.06+0.02+0.01)mol/0.5mol/L=0.18L=180mL 鎵浠閫夋嫨AC 绗笁閬擄細2Cu2S + 14HNO3 --- 2Cu(NO3)2 + 2CuSO4 + 5NO2 + 5NO + 7H2O 鍓╀笅鐨勭敤鎴戞暀涔= =|| ...
绛旓細鍏堟妸mg,ml鎵╁ぇ1000鍊嶄负g,L锛38.4g閾滐紝鍗0.6mol,鐢熸垚鐨勭閰搁摐Cu(NO3)2涓0.6mol锛22.4L姘斾綋锛屽嵆1mol锛屽彲鑳戒负锛圢O2锛夋垨锛圢O2+NO锛,涓嶇鎬庢牱锛屼竴涓狽O2鍜孨O鍒嗗瓙涓彧鍚竴涓狽鍘熷瓙锛屾墍浠ユ牴鎹甆鍘熷瓙瀹堟亽锛屽緱鍒拌杩樺師鐨勭閰哥殑鐗╄川鐨勯噺涓1mol锛屾墍浠ュ弬鍔犲弽搴旂殑纭濋吀鐨勭墿璐ㄧ殑閲=1+0.6脳2=2.2mol ...
绛旓細1)婧舵恫涓璠H+]=9.4*10^-3鎽╁皵/鍗囷紱[OH藟]=1*10^-12鎽╁皵/鍗囷紱绂昏В搴=9.4*10^-3/0.5=1.88%锛汸H=2.03 2锛変笂杩版憾娑蹭腑鍔犲叆绛変綋绉0.2mol路L-1姘㈡哀鍖栭挔NaOH婧舵恫锛岀敓鎴(0.5-0.2)/2=0.15mol路L-1鐢查吀鍜 0.2/2=0.1mol路L-1鐢查吀閽犳憾娑茬殑娣峰悎鐗┿侶COOH=HCOO-+H+ 0.15-X...
绛旓細鐢变簬鍏冪礌鐨勭绫荤洿鎺ュ喅瀹氫簬鍏冪礌鐨勮川瀛愭暟锛屾墍浠ュ師瀛愭斁灏勪簡璐ㄥ瓙銆傜瓟妗圓 绌烘皵锛岀敱浜庡彟澶栦笁鑰呴兘鏄函鍑鐗┿傜敱浜庝箼鐩稿浜庣⒊鍘熷瓙鐨勮川閲忎负c/d,鎵浠ヤ箼鐨勭浉瀵瑰師瀛愯川閲忔槸c/d,鑰屼竴涓崟浣嶇殑鐩稿鍘熷瓙璐ㄩ噺涓虹⒊鍘熷瓙鐨勫崄浜屽垎涔嬩竴銆備篃灏辨槸璇达紝璁句箼鐨勭浉瀵瑰師瀛愯川閲忎负m ,鍙緱12c=md,寰楀埌涔欑殑鐩稿鍘熷瓙璐ㄩ噺鏄12c/d,鍚岀悊...
绛旓細2Al + 6HCl == 2AlCl3 + 3H2鈫 2Al+2NaOH+2H2O=2NaAlO2+3H2鈫 nHCl=0.3mol瀹屽叏鍙嶅簲鐢熸垚姘斾綋0.15mol锛岃梟Al=0.1mol nNaOH=0.3mol瀹屽叏鍙嶅簲鐢熸垚姘斾綋0.45mol锛岃梟Al=0.3mol 鐜扮敓鎴愭皵浣撶殑浣撶Н涔嬫瘮涓3锛4鍒欒鏄庯紝鍙嶅簲杩囩▼涓紝閾濆湪涓涓弽搴斾腑杩囬噺锛堝洜涓洪兘瀹屽叏鍙嶅簲鐨勮瘽锛岀瓑閲忕殑閾濈敓鎴愮殑...
绛旓細閫堿锛欰閫夐」锛屾姄浣忛挔瀹堟亽锛屽嵆姘㈡哀鍖栭挔婧舵恫涓殑閽犵瀛愰兘鏄敱姘寲閽犺屾潵鐨勶紝鍙堝洜涓轰簩鑰呯殑涓涓垎瀛愰兘鍚湁涓涓挔绂诲瓙锛屽彲绠楀嚭姘寲閽犵殑鐗╄川鐨勯噺锛屽簲绛変簬姘㈡哀鍖栭挔鐗╄川鐨勯噺銆侭瀵圭殑锛岀敤浜庢憾瑙ｅ拰閲忓彇 C瀵圭殑锛岃棰樼殑閲忕瓛淇浼氫娇寰楁憾娑插亸绋 D锛屾牴鎹乏鐗╁彸鐮佸師鍒欏彲鐭 鏈涢噰绾筹紝璋㈣阿锛侊紒锛
绛旓細銆愯В鏋愩戞牴鎹鎰忥紝C4H8O2搴斾唬琛ㄧ晶閰稿拰閰紝鍏朵腑缇ч吀锛堝嵆C3H7COOH锛夌殑绉嶇被绛変簬鈥擟3H7鐨勭绫伙紝鏁呮湁 CH3-CH2-CH2-COOH CH3-CH(CH3)COOH 閰繀椤绘弧瓒砇COOR鈥诧紙R鈥插彧鑳戒负鐑冨熀锛屼笉鑳戒负姘㈠師瀛愶級锛孯涓嶳鈥插簲鍏卞惈3涓⒊鍘熷瓙锛屽彲鑳戒负锛欳2鈥擟OO鈥擟锛 CH3CH2COOCH3 C鈥擟OO鈥擟2锛 CH3COOCH2CH3 H鈥擟OO鈥...
