求大神帮忙解答~~
\u5404\u4f4d\u5927\u795e\u5e2e\u5fd9\u89e3\u7b54\uff01\uff0195-5=90
100\u00f790=10/9
32*10/9=35\u53c85/9
\u539f\u5f0f=[1+\u221a(1-4a)/2]^2 *[1+\u221a(1-4a)/2 - 1] +a[1+\u221a(1-4a)/2] +2006
=[1+\u221a(1-4a)/2]^2 *[-1+\u221a(1-4a)/2 ] +a[1+\u221a(1-4a)/2] +2006
=[1+\u221a(1-4a)/2] *[1+\u221a(1-4a)/2]*[-1+\u221a(1-4a)/2 ] +a[1+\u221a(1-4a)/2] +2006
=[1+\u221a(1-4a)/2] *[((1-4a)-1) /4] +a[1+\u221a(1-4a)/2] +2006
=[1+\u221a(1-4a)/2] *(-a) +a[1+\u221a(1-4a)/2] +2006
=2006
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