用c语言如何输入100个学生的成绩并且求平均值和最低分及格率? 急求!c语言输入100个学生的成绩,统计不及格的学生的人数

\u7528c\u8bed\u8a00\u8f93\u5165100\u4e2a\u5b66\u751f\u7684\u6210\u7ee9\u6c42\u5e73\u5747\u503c \u6700\u4f4e\u5206\u53ca\u683c\u7387

\u628a100\u5206\u5b9a\u4e3a\u6700\u9ad8\u5206\uff0c60\u5206\u4e3a\u53ca\u683c\u5206\u6570\u7ebf\u3002\u7528C\u8bed\u8a00\u5b9e\u73b0\u5982\u4e0b\uff1a
#include
#define N 100
void main()
{
int i;
float grade,sum=0,min=100,pass=0;
for(i=0;i{
scanf("%f",&grade);//\u8f93\u5165\u5b66\u751f\u5206\u6570\u3002
sum+=grade;//\u8ba1\u7b97\u5b66\u751f\u7684\u6210\u7ee9\u7684\u603b\u548c\u3002
if (gradeif (grade>=60) pass++; //\u6c42\u53ca\u683c\u4eba\u6570\u3002
}
printf("%0.2f\n",sum/N);
//\u4fdd\u7559\u4e24\u4f4d\u5c0f\u6570\u8f93\u51fa100\u4e2a\u5b66\u751f\u7684\u6210\u7ee9\u7684\u5e73\u5747\u503c\u3002
printf("%0.2f\n",min);//\u4fdd\u7559\u4e24\u4f4d\u5c0f\u6570\u8f93\u51fa\u6700\u4f4e\u5206\u3002
printf("%0.2f%%\n",pass/N*100);//\u4fdd\u7559\u4e24\u4f4d\u5c0f\u6570\u8f93\u51fa\u53ca\u683c\u7387\u3002
}

#include "stdio.h"
#define N 100
void main()
{
int a[N],unpass=0;
for(int i=0;i<N;i++)
{
scanf("%d",&a[i]);
}
for(int i=0;i<N;i++)
{
if(a[i]<60)
unpass++;
}
printf("\u4e0d\u53ca\u683c\u4eba\u6570%d\n",unpass);
}

把100分定为最高分,60分为及格分数线。用C语言实现如下:



#include<stdio.h>
int main()
{
int sum=0,min=1000,jg=0,i,a[100];
for(i=0;i<100;i++)
{
printf("第%d个学生的成绩:",i); //若不需要提示可将此行删除
scanf("%d",&a[i]);
sum+=a[i];
if(a[i]<min)min=a[i];
if(a[i]>=60)jg++;
}
printf("平均分=%.2f\n最低分=%d\n及格率=%d%%\n",sum/100.0,min,jg);
system("pause");
return 0;
}

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