氯气（C12）和氧气一样，都是活泼的非金属单质．在一定条件下，甲烷和充足的氯气反应，推测其产物是（
1.\u6c2f\u6c14\u548c\u6c27\u6c14\u4e00\u6837,\u90fd\u662f\u6d3b\u6cfc\u7684\u975e\u91d1\u5c5e\u5355\u8d28.\u5728\u4e00\u5b9a\u6761\u4ef6\u4e0b\uff0c\u7532\u70f7\u548c\u5145\u8db3\u7684\u6c2f\u6c14\u53cd\u5e94\uff0c\u5176\u4ea7\u7269\u662f\u6c2f\u6c14\u4e0e\u7532\u70f7\u5728\u5149\u7167\u7684\u6761\u4ef6\u4e0b\u53d1\u751f\u662f\u53d6\u4ee3\u53cd\u5e94\u3002\u4e5f\u5c31\u662f\u8bf4\u53d6\u4ee3\u4e00\u4e2a\u6c22\u539f\u5b50\uff0c\u7ed3\u5408\u4e00\u4e2a\u6c2f\u539f\u5b50\uff0c\u76f8\u5f53\u4e8e\u521d\u4e2d\u7684\u7f6e\u6362\u53cd\u5e94\uff0c\u4e00\u8fdb\u4e00\u51fa\u3002\u53cd\u5e94\u7684\u5316\u5b66\u65b9\u7a0b\u5f0f\u5206\u522b\u4e3a\uff1a
CH4+Cl2\u2192\u5149\u7167\u2192CH3Cl+HCl
CH3Cl+Cl2\u2192\u5149\u7167\u2192CH2Cl2+HCl
CH2Cl2+Cl2\u2192\u5149\u7167\u2192CHCl3+HCl
CHCl3+Cl2\u2192\u5149\u7167\u2192CCl4+HCl
\u5145\u8db3\u7684\u6c2f\u6c14\uff0c\u5b8c\u5168\u53d6\u4ee3\uff0c\u53cd\u5e94\u7684\u5316\u5b66\u65b9\u7a0b\u5f0f\u4e3a\uff1a
CH4+2Cl2\u2192\u5149\u7167\u2192CCl4+4HCl
\u6240\u4ee5\u662fB\uff0c\u4e0d\u662fC\u3002C\u6ca1\u6709\u53d6\u4ee3\u5b8c\u5168
\u5e0c\u671b\u5bf9\u4f60\u6709\u5e2e\u52a9
CH 4 \u5728Cl 2 \u4e2d\u5145\u5206\u53cd\u5e94\u751f\u6210CCl 4 \u548cHCl\uff0c\u628aCO 2 \u548cH 2 O\u7684O\u5143\u7d20\u7528Cl\u5143\u7d20\u66ff\u6362\u5c31\u53ef\u4ee5\u4e86\uff0cO\u662f-2\u4ef7\uff0cCl\u662f-1\u4ef7\uff0c\u6545\u751f\u6210\u7269CCl 4 \u548cHCl\uff0e\u6545\u9009B\uff0e
CH4在Cl2中充分反应生成CCl4和HCl，把CO2和H2O的O元素用Cl元素替换就可以了，O是-2价，Cl是-1价，故生成物CCl4和HCl．故选A．
绛旓細鏁呭～锛2Cl2 +2Ca锛圤H锛2鈺怌aCl2 +Ca锛圕lO锛2 +2H2O锛涒憽涓嶈兘杈惧埌瀹為獙鐨勭洰鐨勶紝闇瑕佽璁′竴涓鐓у疄楠屾墠鑳借揪鍒板疄楠岀殑鐩殑锛屽嵆鍦ㄤ竴涓孩鑹插竷鏉′笂婊村姞鐩愰吀锛屽竷鏉℃棤鍙樺寲锛屽氨璇佹槑璧锋紓鐧戒綔鐢ㄧ殑鐗╄川鏄姘吀锛庢晠绛旀涓猴細鍦ㄤ竴涓孩鑹插竷鏉′笂婊村姞鐩愰吀锛屽竷鏉℃棤鍙樺寲锛屽氨璇佹槑璧锋紓鐧戒綔鐢ㄧ殑鐗╄川鏄姘吀锛涳紙4锛夎В锛氳...
绛旓細A,C,C,B,D,D,D,C,A,A,?,B,C,C
绛旓細2銆佹隘閰搁挔姘у寲娉曪細灏嗘隘閰搁挔涓庡寲骞虫贩瀹㈠湪鐨勬潯浠跺崄鍙嶇敓纰抽吀閽惧拰姘寲閽犮傚弽搴旀柟绋嬪紡涓篘aC103+KC1鈫扠C103+NaC1.3銆姘皵姘у寲娉曪細灏嗘隘姘旈氳繃鍚姘ф皵鐨勭┖姘斾腑锛屼娇鍏舵哀鍖栦负姘吀銆備箣鍚庡皢姘吀鍜屾隘鍖栭捑娣峰悎锛屽弽搴旂敓鎴愭隘閰搁捑鍜屾隘鍖栭挔銆傚弽搴旀柟绋嬪紡涓C12+302+2KC1鈫2KC103.浠ヤ笂涓夌鏂规硶涓紝鐢佃В娉曟槸鏈甯哥敤鐨勬柟娉曪紝...
绛旓細閿兘鏄弿杩板寲瀛﹂敭寮哄害鐨勭墿鐞嗛噺锛屽畠琛ㄧず鏂紑涓涓寲瀛﹂敭鎵闇鐨勮兘閲忋傚浜嶧₂锛堟盁姘旓級鍜孋l₂锛堟隘姘锛夎繖鏍风殑鍙屽師瀛愬垎瀛愶紝鍏堕敭鑳藉垎鍒寚鐨勬槸鏂紑涓涓盁-姘熼敭鍜屼竴涓隘-姘敭鎵闇鐨勮兘閲忋備竴鑸潵璇达紝姘-姘熼敭鐨勯敭鑳借楂樹簬姘-姘敭锛岃繖鏄洜涓烘盁鍘熷瓙鐨勭數璐熸ф洿寮猴紝浣垮緱姘-姘熼敭鏇村姞绋冲畾锛岄渶瑕佹洿澶...
绛旓細绗竷涓绘棌: (鍗曡川姘у寲)F2>C12>Br2>I2; (鍏冪礌闈為噾灞)F>C1>Br>I 鍙﹀娉ㄦ剰锛屾哀鍏冪礌鐨勯潪閲戝睘瑕佺◢寮轰簬姘厓绱;浣嗘槸鍗曡川姘у寲鍗寸浉鍙嶏紝姘у寲(C12>02)鍗:姘皵姣姘ф皵姘у寲绋嶅己浜;浣嗘槸濂ユ哀03瑕佽繙姣擟12姘у寲寮恒傛哀鍖栫墿璐锛屾槸鎸囨湰韬湭蹇呯噧鐑э紝浣嗗彲閲婃斁鍑烘哀锛屽彲鑳藉紩璧锋垨淇冧娇鍏朵粬鐗╄川鐕冪儳鐨勪竴绉嶅寲瀛﹁川姣旇緝娲绘臣鐨...
绛旓細3Cl2+6KOH(鐑,娴)===5KCl+KClO3+3H2O 3S+6NaOH===2Na2S+Na2SO3+3H2O 4P+3KOH(娴)+3H2O===PH3+3KH2PO2 11P+15CuSO4+24H2O===5Cu3P+6H3PO4+15H2SO4 3C+CaO===CaC2+CO 3C+SiO2===SiC+2CO 浜,閲戝睘鍗曡川(Na,Mg,Al,Fe)鐨勮繕鍘熸 2Na+H2===2NaH 4Na+O2===2Na2O 2Na2O+O2===2...
绛旓細锛1锛夋隘姘鐨勭墿鐞嗘ц川鏈夛細鍦ㄥ父娓╀笅锛宭浣撶Н姘寸害婧惰В2浣撶Н鐨姘皵锛姣旂┖姘斿瘑搴﹀ぇ锛庢晠绛旀涓猴細姣旂┖姘斿瘑搴﹀ぇ锛屽彲婧朵簬姘达紱锛2锛夋牴鎹璐熷寲鍚堜环鐨勪唬鏁板拰涓洪浂锛+1+x+锛-2锛=0锛寈=+1锛鏁呯瓟妗堜负锛+1锛
绛旓細10銆佷竴姘у寲纰冲湪姘ф皵涓噧鐑:2CO + O2 鐐圭噧 2CO2 11銆佷簩姘у寲纰冲拰姘村弽搴(浜屾哀鍖栫⒊閫氬叆绱壊鐭宠晩璇曟恫):CO2 + H2O === H2CO3 12銆佺敓鐭崇伆婧朵簬姘:CaO + H2O === Ca(OH)2 13銆佹棤姘寸～閰搁摐浣滃共鐕ュ墏:CuSO4 + 5H2O === CuSO4?5H2O 14銆侀挔鍦姘皵涓噧鐑:2Na + Cl2鐐圭噧 2NaCl 鍒嗚В鍙嶅簲鍒嗚В鍙嶅簲鍒嗚В鍙嶅簲鍒嗚В...
绛旓細O+Mn2锛嬨1銆佸寲瀛︽柟绋嬪紡:4HC1(娴)+Mn0z=鍔犵儹=MnC12+C12鈫+2H20鎴栬16HC1+2KMn04=2KC1+2MnC12+8H20+5C12鈫戙傚疄楠屽閫氬父鐢ㄦ哀鍖栨祿鐩愰吀鐨勬柟娉曟潵鍒跺彇姘皵銆傚埗澶囨隘姘斿父瑙佺殑姘у寲鍓傛湁:Mn0z銆並Mn04銆丆ca(C10)2銆丆o203锛屽埗澶囨隘姘斾腑鐨勪袱涓弽搴旂敤鐨勭洂閰告瘮杈冪█鐨勮瘽锛屽弽搴斿皢涓嶅啀杩涜锛屾病鏈夌洂閰稿彲鐢...
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