一道线代题 一道线代题？
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绛旓細|A|=0锛屽垯3(a-1)=a^2-1锛屽嵆a=1鎴2 1 1 1 1 1 2 a d 1 4 a^2 d^2 -> 1 1 1 1 0 1 a-1 d-1 0 3 a^2-1 d^2-1 -> 1 1 1 1 0 1 a-1 d-1 0 0 0 (d-1)(d-2)鍒(d-1)(d-2)涓嶄负0 鍗砫涓嶇瓑浜1銆2 绛旀閫夋嫨C ...
绛旓細瑙ｇ瓟:鏍规嵁棰樻剰:鐩寸嚎L:y=k(x-4);鎶涚墿绾:y^2=4x; (K鈮0)鑱旂珛涓ゅ紡瀛愶紝鏁寸悊鍙緱:k^2X^2-(8k^2+4)x+16K^2=0;鏍规嵁闊﹁揪瀹氱悊:X1+X2=8+k^2/4;X1X2=16;鎵浠:y1+y2=k(x1-4)+k(x2-4)=K(X1+X2)-8K=4/k;(K鈮0)鍥犳:AP鐨勪腑鐐筼(X1/2+2;y1/2)涓哄渾蹇;鍗婂緞R=|AP|/2=...
绛旓細銆愮瓟妗堛慍 銆愯В鏋愩戠郴鏁拌鍒楀紡涓 D= |k 0 1| |2 k 1| |k -2 1| = |k 0 1| |2 k 1| |0 -2 0| =2k-4 鏍规嵁鍏嬫媺榛樻硶鍒欙紝2k-4鈮0鏃讹紝鏂圭▼缁勪粎鏈夐浂瑙ｃ傗埓绛旀鏄痥鈮2
绛旓細A鐨勫垪鍚戦噺绾挎ф棤鍏筹紝鏄剧劧A鍒楁弧绉╋紝鑰孉鏄柟闃碉紝鍥犳A灏辨槸婊＄З鐨勶紝鍙嗐傚洜姝^2涔熷彲閫嗭紝浠庤孉^2涔熸槸婊＄З鐨勶紝鍒欎篃鍒楁弧绉╋紝婊¤冻鍒楀悜閲忕嚎鎬ф棤鍏
绛旓細瑙: 鐢卞凡鐭, A(B-E)=B 鎵浠 A = B(B-E)^-1 = 1 -2 0 0 1/2 0 2 1 0 涔 -1/2 0 0 0 0 0 0 0 -1 = 1 1/2 0 -1/2 1 0 0 0 0 A= 1 4 2 0 -3 4 0 4 3 |A-位E|= 1-位 4 2 0 -3-位 ...
绛旓細涓閬绠鍗曠殑绾夸唬棰 涓诲瑙掔嚎涓婃槸0,绱т复瀵硅绾夸袱杈圭殑鏁版槸 1 ,鐒跺悗鍏朵粬鏁伴兘鏄0,姹傝鍒楀紡鐨勫,姹傝В 涓閬撶畝鍗曠殑绾夸唬棰樹富瀵硅绾夸笂鏄0,绱т复瀵硅绾夸袱杈圭殑鏁版槸1,鐒跺悗鍏朵粬鏁伴兘鏄0,姹傝鍒楀紡鐨勫,姹傝В鍟,鎴戝疄鍦ㄤ笉浼氬仛鍟... 涓閬撶畝鍗曠殑绾夸唬棰樹富瀵硅绾夸笂鏄0,绱т复瀵硅绾夸袱杈圭殑鏁版槸 1 ,鐒跺悗鍏朵粬鏁伴兘鏄0,姹傝鍒楀紡鐨...
绛旓細1 1 -1 1 2 a+2 -b-2 3 0 -3a a+2b -3 r2-2r1 ~1 1 -1 1 0 a -b 1 0 -3a a+2b -3 r3+3r2 ~1 1 -1 1 0 a -b 1 0 0 a-b 0 鏄剧劧绯绘暟琛屽垪寮=a(a-b)涓嶇瓑浜庨浂鍗砤涓嶇瓑浜0锛屼笖a涓嶇瓑浜巄 ~1 1 -1 1 0 a -b 1 0 0 1 0 r1+r3锛宺2+br3 ~1 1 ...
绛旓細鍒 P^2 = [0 0 1][0 0 0][0 0 0]P^n = O (n鈮3)A^k = (位E+P)^k = 位^kE + k位^(k-1)P + [(1/2)k(k-1)]位^(k-2)P^2 + [k(k-1)(k-2)/3!]位^(k-3)P^3 + ... = [位^k, k位^(k-1), (1/2)k(k-1)位^(k-2)][0, 位^k, k位...
绛旓細銆愬垎鏋愩戞眰瑙ｅ悜閲忕殑鏋佸ぇ绾挎ф棤鍏崇粍锛岄渶瑕佸鍚戦噺杩涜鍒濈瓑琛屽彉鎹紝姹傚嚭绉 銆愯В绛斻戝鐭╅樀锛坅1锛宎2锛宎3锛宎4锛変綔鍒濈瓑琛屽彉鎹紝寰 1 2 0 3 0 -1 1 -1 0 0 0 0 0 0 0 0 绉╀负2锛屾瀬澶х嚎鎬ф棤鍏崇粍涓篴1锛宎2 a3=2a1-a2 a4=a1+a2 newmanhero 2015...
绛旓細x=-4锛寉=5锛屽洜涓篴鐩镐技浜庡瑙掗樀锛屾墍浠ヤ袱涓殑鐗瑰緛鍊肩浉鍚岋紝鐒跺悗寰呭畾绯绘暟娉曞氨绠楀嚭鏉ヤ簡銆傚悗闈灏辨槸鐗瑰緛鍊煎搴旂殑鐗瑰緛鍚戦噺鎷煎湪涓璧峰氨鏄簡锛岃瀵瑰簲涓庡瑙掗樀鐨勭壒寰佸奸『搴忋傚鏋滄弧鎰忚鍙婃椂閲囩撼鍝︺
