填运算符号的题目,谁来?
\u586b\u8fd0\u7b97\u7b26\u53f7\u7684\u9898\u76ee,\u8c01\u6765?\u4e00\u30013333=1 \uff0c14\u4e2a\uff1a
33/33=1\uff0c(3+3-3)/3=1\uff0c(3+3)/(3+3)=1\uff0c3+3/3-3=1\uff0c3-3+3/3=1\uff0c(3-3+3)/3=1\uff0c3-(3+3)/3=1
3*3/3/3=1\uff0c3/3+3-3=1\uff0c3/(3+3-3)=1\uff0c3/3-3+3=1\uff0c3/(3-3+3)=1\uff0c3/3*3/3=1\uff0c3/3/3*3=1
\u4e8c\u30016666=22 \uff0c\u65e0\u89e3
\u4e09\u30019999=333 \uff0c\u65e0\u89e3
\u4e00\u3001\u4e0d\u4f7f\u7528\u62ec\u53f7\uff0c\u8fd0\u7b97\u7b26\u53f7\u4f7f\u7528\u52a0\u51cf\u4e58\u9664\uff1a
1\u300112345=1 \uff0c3\u4e2a\uff1a
1+2-3-4+5=1\uff0c1-2+3+4-5=1\uff0c1/2*3*4-5=1
2\u300112345=11 \uff0c3\u4e2a\uff1a
12/3*4-5=11\uff0c1-2+3+4+5=11\uff0c1/2*3*4+5=11
3\u300112345=111 \uff0c\u65e0\u89e3
\u4e8c\u3001\u4f7f\u7528\u62ec\u53f7\uff0c\u8fd0\u7b97\u7b26\u53f7\u4f7f\u7528\u52a0\u51cf\u4e58\u9664\uff1a
1\u300112345=1 \uff0c25\u4e2a\uff1a
(1+23)/4-5=1\uff0c(12-3-4)/5=1\uff0c(12-3)/(4+5)=1\uff0c12/(3+4+5)=1
1+2-3-4+5=1\uff0c((1+2)*3-4)/5=1\uff0c(1+2)*3/(4+5)=1\uff0c((1+2)/3+4)/5=1
1-2+3+4-5=1\uff0c(1-(2-3)*4)/5=1\uff0c(1*2-3)*4+5=1\uff0c1*(2-3)*4+5=1
1*((2-3)*4+5)=1\uff0c(1*2-3)*(4-5)=1\uff0c1*(2-3)*(4-5)=1\uff0c(1*2-3)/(4-5)=1
1*(2-3)/(4-5)=1\uff0c1*2/(3+4-5)=1\uff0c1/(2+3)+4/5=1\uff0c1/(2-3)*4+5=1
1/((2-3)*4+5)=1\uff0c1/(2-3)*(4-5)=1\uff0c1/(2-3)/(4-5)=1\uff0c1/2*(3+4-5)=1
1/2*3*4-5=1
2\u300112345=11 \uff0c7\u4e2a\uff1a
(1+23)/4+5=11\uff0c12/3*4-5=11\uff0c1+(2*3-4)*5=11\uff0c1-2+3+4+5=11
1-2*(3-4)*5=11\uff0c1-2/(3-4)*5=11\uff0c1/2*3*4+5=11
3\u300112345=111 \uff0c\u65e0\u89e3
(9-√9)!/((√9)!/√9)+9 =(9-3)!/(3!/3)+9 = 6!/2+9 =720/2+9=369
33333=369
(3+3)!/(3!/3)+3^ =6!/(6/3)+9 = 720/2+9 =360+9=369
(3^(3!)+3^)/(3!/3) =(3^6 + 9)/(6/3)= (729+9)/3 =738/2=369
6不知如何填，如果允许取整运算的话，就可以。
全部没有解
333333倒是有1个：3+33+333=369
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