求实数计算带答案100道 求初二实数计算题100道
\u6570\u5b66\u521d\u4e8c\u5b9e\u6570\u8ba1\u7b97\u9898\u53ca\u7b54\u6848\uff08\u4e00\u767e\u9053\uff09(1)99²\uff0d2.99² (2)80\u00d73.5²\uff0b160\u00d73.5\u00d71.5\uff0b80\u00d71.5² (3)181²\uff0d61²\u00f7301²\uff0d181²
(4)5x\uff0d5y\uff0b5z (5)-5a²+25a-5a (6)2a(b+c)-3(b+c) (7)(ab+a)+(b+1)
(8)-4m³+16m³-28m (9)16x-25x³y² (10)36m²a-9m²a²-36m²
\u221a32-3\u221a1/2+\u221a2
\u221a12+\u221a27/\u221a3-\u221a1/3\u00d7\u221a12
\u221a50+\u221a30/\u221a8-4
\uff08\u221a6-2\u221a15\uff09\u00d7\u221a3-6\u221a1/2
\u221a2/3-4\u221a216+43\u221a1/6
\u221a8+\u221a30-\u221a2
\u221a40-5\u221a1/10+\u221a10
\u221a2+\u221a8/\u221a2
\u221a2/9+\u221a50+\u221a32
\uff081-\u221a3\uff09\uff08\u221a3+2\uff09
\uff08\u221a8+3\u221a6\uff09\u00f7\u221a2-\u221a3\u00d7\u221a0.7
\uff08-3+\u221a6\uff09\uff08-3-\u221a6\uff09-\uff08\u221a3-1/\u221a3\uff09²
³\u221a0.125-\u221a3 1/16+³\u221a\uff081-7/8\uff09²
\u221a2/3-\u221a216+42\u221a1/6
\u89e3\u65b9\u7a0b\u221a3 X-1=\u221a2 X
\u6c42X
{\u221a5 X-3\u221a Y=1}
{\u221a3 X-\u221a5 Y=2}
\u6ce8\uff1aX\u5168\u90e8\u4e0d\u5728\u6839\u53f7\u5185
\u221a\uff081/2x\uff09^2\uff0b10/9x^2
=\u221a[1/(4x^2)+10/(9x^2)]
=\u221a49/36x^2
\u82e5x>0,=7/(6x)
\u82e5x<0,=-7/(6x)
\u221aa^4mb^2n\uff0b1
=\u221a(a^2mb^n)^2\uff0b1
=a^2mb^n\uff0b1
\u221a\uff084a^5\uff0b8a^4\uff09\uff08a^2\uff0b3a\uff0b2\uff09
=\u221a[4a^4(a+2)][(a+2)(a+1)]
=\u221a[4a^4(a+2)^2(a+1)]
=2a^2(a+2)\u221a(a+1)
. 3\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09
\u7b54\u68483\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09
= 3\u00d7\u221a6/6-4\u00d75\u221a2+30\u00d7\u221a6/3
\uff1d\u221a6/2-20\u221a2+10\u221a6
2. \uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2
\u9898\u662f\u8fd9\u6837\u7684\u4e8c\u5206\u4e4b\u4e00\u51cf\u6839\u53f72\u4e58\u4ee5\u4e8c\u5206\u4e4b\u4e00\u52a0\u6839\u53f72
\u7b54\u6848\uff1a\uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2
=\uff081-\u221a2\uff09*\uff081-\u221a2\uff09\uff0f4
\uff1d\uff081\uff0d2\uff09\uff0f4
\uff1d\uff0d1\uff0f4
1.3\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09 \u7b54\u68483\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09 = 3\u00d7\u221a6/6-4\u00d75\u221a2+30\u00d7\u221a6/3 \uff1d\u221a6/2-20\u221a2+10\u221a6 2. \uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2 \u9898\u662f\u8fd9\u6837\u7684\u4e8c\u5206\u4e4b\u4e00\u51cf\u6839\u53f72\u4e58\u4ee5\u4e8c\u5206\u4e4b\u4e00\u52a0\u6839\u53f72 \u7b54\u6848\uff1a\uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2 =\uff081-\u221a2\uff09*\uff081-\u221a2\uff09\uff0f4 \uff1d\uff081\uff0d2\uff09\uff0f4 \uff1d\uff0d1\uff0f4 3.\u221a\uff081/2x\uff09^2\uff0b10/9x^2 \u221a[\uff081/2x\uff09^2\uff0b10/9x^2] =\u221a(x^2/4+10x^2/9) =\u221a(9x^2/36+40x^2/36) =\u221a(49x^2/36) =7x/6; 4.\u221aa^4mb^2n\uff0b1\uff08a\u3001b\u4e3a\u6b63\u6570\uff09 [\u221a(a^4mb^2n)]\uff0b1\uff08a\u3001b\u4e3a\u6b63\u6570\uff09 =a^2mb^n+1; 5.\u221a\uff084a^5\uff0b8a^4\uff09\uff08a^2\uff0b3a\uff0b2\uff09\uff08a>=0\uff09 \u221a[\uff084a^5\uff0b8a^4\uff09\uff08a^2\uff0b3a\uff0b2\uff09]\uff08a>=0\uff09 =\u221a[4a^4(a+2)(a+2)(a+1)] =\u221a[(2a^2)^2(a+2)^2(a+1)] =2a^2(a+2)\u221a(a+1). \u592a\u591a\u4e86\u5440\uff0c\u53ea\u80fd\u8fd9\u6837\u4e86\uff0c\u6211\u8fd8\u6709\u4e8b \u60a8\u597d\uff01 \u24605\u221a8-2\u221a32+\u221a50 =5*3\u221a2-2*4\u221a2+5\u221a2 =\u221a2(15-8+5) =12\u221a2 \u2461\u221a6-\u221a3/2-\u221a2/3 =\u221a6-\u221a6/2-\u221a6/3 =\u221a6/6 \u2462(\u221a45+\u221a27)-(\u221a4/3+\u221a125) =(3\u221a5+3\u221a3)-(2\u221a3/3+5\u221a5) =-2\u221a5+7\u221a5/3 \u2463(\u221a4a-\u221a50b)-2(\u221ab/2+\u221a9a) =(2\u221aa-5\u221a2b)-2(\u221a2b/2+3\u221aa) =-4\u221aa-6\u221a2b \u2464\u221a4x*(\u221a3x/2-\u221ax/6) =2\u221ax(\u221a6x/2-\u221a6x/6) =2\u221ax*(\u221a6x/3) =2/3*x*\u221a6 \u2465(x\u221ay-y\u221ax)\u00f7\u221axy =x\u221ay\u00f7\u221axy-y\u221ax\u00f7\u221axy =\u221ax-\u221ay \u2466(3\u221a7+2\u221a3)(2\u221a3-3\u221a7) =(2\u221a3)^2-(3\u221a7)^2 =12-63 =-51 \u2467(\u221a32-3\u221a3)(4\u221a2+\u221a27) =(4\u221a2-3\u221a3)(4\u221a2+3\u221a3) =(4\u221a2)^2-(3\u221a3)^2 =32-27 =5 \u2468(3\u221a6-\u221a4)² =(3\u221a6)^2-2*3\u221a6*\u221a4+(\u221a4)^2 =54-12\u221a6+4 =58-12\u221a6 \u2469\uff081+\u221a2-\u221a3\uff09\uff081-\u221a2+\u221a3\uff09 =[1+(\u221a2-\u221a3)][1-(\u221a2-\u221a3)] =1-(\u221a2-\u221a3)^2 =1-(2+3+2\u221a6) =-4-2\u221a6 1. =5\u221a5 - 1/25\u221a5 - 4/5\u221a5 =\u221a5*(5-1/25-4/5) =24/5\u221a5 2.=\u221a144+576 =\u221a720 =12\u221a5 3.)\u221a(8/13)^2-(2/13)^2 = \u221a(8/13+2/13)(8/13-2/13) =(2/13)\u221a15
\u5c31\u8fd9\u4e9b\u4e86\uff01\uff01\u989d\uff01\uff01\u597d\u7d2f\u554a\uff01\uff01
\u82e5\u65b9\u7a0bx^2+px+q=0(p,q\u4e3a\u5e38\u6570\uff0cp^2-4q>0)\u7684\u4e24\u6839\u4e3ax1\uff0cx2\uff0c\u5219x1+x2=_______,x1*x2=_______.
2.\u5df2\u77e5\u65b9\u7a0bx^2-5x+3=0\u7684\u4e24\u4e2a\u6839\u4e3ax1,x2\uff0c\u8ba1\u7b97\u4e0b\u5217\u5404\u5f0f\u7684\u503c\uff08\u4e0d\u89e3\u65b9\u7a0b\uff09
(1)x1+x2;
(2)x1*x2;
(3)1/x1+1/x2;
(4)x1^2+x2^2.
\u968f\u5802\u4f5c\u4e1a\u2014\u57fa\u7840\u8fbe\u6807
1.\u5982\u679c\u65b9\u7a0bax^2+bx+c=0(a=/0)\u7684\u4e24\u6839\u662fx1\uff0cx2\uff0c\u90a3\u4e48x1+x2=________,x1*x2=________.
2.\u5df2\u77e5x1\uff0cx2\u662f\u65b9\u7a0b2x^2+3x-4=0\u7684\u4e24\u4e2a\u6839\uff0c\u90a3\u4e48x1+x2=________;x1*x2=_______;1/x1+1/x2=________;x1^2+x2^2=________;(x1+1)(x2+1)=___________.
3.\u5df2\u77e5\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b2x^2-3x-1=0\u7684\u4e24\u6839\u4e3ax1\uff0cx2\uff0c\u5219x1+x2=________.
4.\u82e5\u65b9\u7a0bx^2+x-1=0\u7684\u4e24\u6839\u5206\u522b\u4e3ax1\uff0cx2\uff0c\u5219x1^2+x2^2=________.
5.\u5df2\u77e5x1\uff0cx2\u662f\u5173\u4e8ex\u7684\u65b9\u7a0bx^2+mx+m=0\u7684\u4e24\u4e2a\u5b9e\u6570\u6839\uff0c\u4e14x1+x2=1/3\uff0c\u5219x1*x2=___________.
6.\u4ee53\uff0c-1\u4e3a\u6839\uff0c\u4e14\u4e8c\u6b21\u9879\u7cfb\u6570\u4e3a3\u7684\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u5f0f\uff08 \uff09
A.3x^2-2x+3=0
B.3x^2+2x-3=0
C.3x^2-6x-9=0
D.3x^2+6x-9=0
7.\u8bbex1\uff0cx2\u662f\u65b9\u7a0b2x^2-2x-1=0\u7684\u4e24\u4e2a\u6839\uff0c\u5229\u7528\u6839\u4e0e\u7cfb\u6570\u7684\u5173\u7cfb\uff0c\u6c42\u4e0b\u5217\u5404\u5f0f\u7684\u503c\uff1a
(1) (2x1+1)(2x2+1);
(2) (x1^2+2)(x2^2+2);
(3) x1-x2.
\u8bfe\u540e\u4f5c\u4e1a\u2014\u57fa\u7840\u62d3\u5c55
1.\uff08\u5de7\u89e3\u9898\uff09\u5df2\u77e5 \u03b1^2+\u03b1-1=0\uff0c\u03b2^2+\u03b2-1=0\uff0c\u4e14\u03b1\u4e0d\u7b49\u4e8e\u03b2\uff0c\u5219\u03b1\u03b2+\u03b1+\u03b2\u7684\u503c\u4e3a\uff08 \uff09
A.2
B.-2
C.-1
D.0
2.\uff08\u6613\u9519\u9898\uff09\u5df2\u77e5\u4e09\u89d2\u5f62\u4e24\u8fb9\u957f\u5206\u522b\u4e3a2\u548c9\uff0c\u7b2c\u4e09\u8fb9\u7684\u957f\u4e3a\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u5f0fx^2-14x+48=0\u7684\u4e00\u4e2a\u6839\uff0c\u5219\u8fd9\u4e2a\u4e09\u89d2\u5f62\u7684\u5468\u957f\u4e3a\uff08 \uff09
A.11
B.17
C.17\u621619
D.19
3.\u82e5\u5173\u4e8ex\u7684\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0bx^2+kx+4k^2-3=0\u7684\u4e24\u4e2a\u5b9e\u6570\u6839\u5206\u522b\u662fx1\uff0cx2\uff0c\u4e14\u6ee1\u8db3x1+x2=x1*x2,\u5219k\u7684\u503c\u4e3a\uff08 \uff09
A.-1\u62163/4
B.-1
C.3/4
D.\u4e0d\u5b58\u5728
4.\uff08\u4e00\u9898\u591a\u89e3\uff09\u5df2\u77e5\u65b9\u7a0b2x^2+mx-4=0\u7684\u4e00\u6839\u4e3a-2\uff0c\u6c42\u5b83\u7684\u53e6\u4e00\u6761\u6839\u7684\u503c.\uff08\u7528\u4e24\u79cd\u65b9\u6cd5\u6c42\u89e3\uff09
\u7b54\u6848\uff1a1.-P Q
2. 5 3 \u7b2c\u4e09\u4e2a\u5f0f\u5b50\u5408\u5e76(X1+X2)/X1*X2=5/3 \u7b2c\u56db\u4e2a\u5f0f\u5b50=(X1+X2)^2-2X1*X2 =19
\u968f\u5802\u4f5c\u4e1a\u2014\u57fa\u7840\u8fbe\u6807
1.-B/A C/A
2.-3/2 -2 3/4 25/4
3. 3/2
4. 3
5. -1/3
6. C
7.\u8bbex1\uff0cx2\u662f\u65b9\u7a0b2x^2-2x-1=0\u7684\u4e24\u4e2a\u6839\uff0c\u5229\u7528\u6839\u4e0e\u7cfb\u6570\u7684\u5173\u7cfb\uff0c\u6c42\u4e0b\u5217\u5404\u5f0f\u7684\u503c\uff1a
(1) (2x1+1)(2x2+1); \u5c55\u5f00=2
\u56e0\u4e3aX1+X2=1 X1X2=-1/2
(2) (x1^2+2)(x2^2+2); \u5c55\u5f00=29/4
(3) x1-x2.=(X1-X2)^2\u5f00\u5e73\u65b9=X1^2+X2^2-2X1X2=
=(X1+X2)^2-4X1X2 =3\u5f00\u5e73\u65b9
\u8bfe\u540e\u4f5c\u4e1a\u2014\u57fa\u7840\u62d3\u5c55
1.\uff08\u5de7\u89e3\u9898\uff09\u5df2\u77e5 \u03b1^2+\u03b1-1=0\uff0c\u03b2^2+\u03b2-1=0\uff0c\u4e14\u03b1\u4e0d\u7b49\u4e8e\u03b2\uff0c\u5219\u03b1\u03b2+\u03b1+\u03b2\u7684\u503c\u4e3a\uff08B \uff09
A.2
B.-2
C.-1
D.0
2.\uff08\u6613\u9519\u9898\uff09\u5df2\u77e5\u4e09\u89d2\u5f62\u4e24\u8fb9\u957f\u5206\u522b\u4e3a2\u548c9\uff0c\u7b2c\u4e09\u8fb9\u7684\u957f\u4e3a\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u5f0fx^2-14x+48=0\u7684\u4e00\u4e2a\u6839\uff0c\u5219\u8fd9\u4e2a\u4e09\u89d2\u5f62\u7684\u5468\u957f\u4e3a\uff08 D\uff09\u6ce8\u610f\u4e24\u8fb9\u4e4b\u548c\u5927\u4e8e\u7b2c\u4e09\u8fb9 \u4e4b\u5dee\u5c0f\u4e8e\u7b2c\u4e09\u8fb9 \u6240\u4ee5\u53ea\u80fd\u662f8
A.11
B.17
C.17\u621619
D.19
3.\u82e5\u5173\u4e8ex\u7684\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0bx^2+kx+4k^2-3=0\u7684\u4e24\u4e2a\u5b9e\u6570\u6839\u5206\u522b\u662fx1\uff0cx2\uff0c\u4e14\u6ee1\u8db3x1+x2=x1*x2,\u5219k\u7684\u503c\u4e3a\uff08c \uff09 \u6ce8\u610f\uff1a\u5f53k\u4e3a-1\u65f6\u5019 \u539f\u65b9\u7a0b\u7684b^2-4ac\u5c0f\u4e8e0
A.-1\u62163/4
B.-1
C.3/4
D.\u4e0d\u5b58\u5728
4.\uff08\u4e00\u9898\u591a\u89e3\uff09\u5df2\u77e5\u65b9\u7a0b2x^2+mx-4=0\u7684\u4e00\u6839\u4e3a-2\uff0c\u6c42\u5b83\u7684\u53e6\u4e00\u6761\u6839\u7684\u503c.\uff08\u7528\u4e24\u79cd\u65b9\u6cd5\u6c42\u89e3\uff09
1.\u4e24\u6839\u4e4b\u548c=-M/2=-2+X2 \u4e24\u6839\u4e4b\u79ef=-2
\u6240\u4ee5X2=1 M=2
2.\uff08-b+\u6216\u8005-\u6839\u53f7\u4e0bb^2-4ac\uff09/2a=-2
\u89e3\u4e0b\u5217\u65b9\u7a0b
1. (2x-1)^2-1=0
1
2. \u2014\uff08x+3)^2=2
2
3. x^2+2x-8=0
4. 3x^2=4x-1
5. x(3x-2)-6x^2=0
6. (2x-3)^2=x^2
\u4e00.\u914d\u5b8c\u5168\u5e73\u65b9\u5f0f\uff08\u76f4\u63a5\u5199\u7b54\u6848\uff09
1. x^2-4x+___________=\uff08x-___________\uff09^2
2. x^2+mx+9\u662f\u4e00\u4e2a\u5b8c\u5168\u5e73\u65b9\u5f0f\uff0c\u5219m=_____
\u4e8c.\u914d\u65b9\u6cd5\u89e3\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\uff08\u9700\u8981\u8fc7\u7a0b\uff09
3.\u7528\u914d\u65b9\u7a0b\u89e3\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b
x^2-8x-9=0
\u57fa\u7840\u8fbe\u6807
1\u7528\u914d\u65b9\u6cd5\u89e3\u65b9\u7a0bx^2-6x-5=0,\u914d\u65b9\u5f97\uff08 \uff09
A.\uff08x-6)^2=14
B.(x-3)^=8
C.(x-3)^=14
D.(x-6)^2=41
2.\u5c06\u4e8c\u6b21\u4e09\u9879\u5f0f2x^-3x+5\u914d\u65b9\uff0c\u6b63\u786e\u7684\u662f\uff08 \uff09
3 31
A.\uff08x- \u2014)^2+ \u2014
4 16
3 34
B.\uff08x- \u2014)^2- \u2014
4 16
3 31
C.2(x- \u2014\uff09^2+ \u2014
4 16
3 31
D.2\uff08x- \u2014)^2+ \u2014
4 8
3.\u586b\u7a7a\uff1a
1. x^2+8x+______=\uff08x+______)^2
2.2x^2-12x+______=2\uff08x-______\uff09^2
4.\u7528\u914d\u65b9\u6cd5\u89e3\u4e0b\u5217\u65b9\u7a0b\uff08\u8981\u8fc7\u7a0b\uff09
1. x^+5x+3=0
2. 2x^2-x-3=0
\u57fa\u7840\u6269\u5c55
1.\u5df2\u77e5(x^2+y^2)(x^2+y^2+2)-8=0,\u5219x^2+y^2\u7684\u503c\u662f\uff08 \uff09
A.-4
B. 2
C.-1\u62164
D.2\u62164
2.\uff08\u7efc\u5408\u4f53\uff09\u7528\u914d\u65b9\u6cd5\u89e3\u5173\u65bcx^2+2mx-n^2=0\uff08\u8981\u6c42\u5199\u51fa\u8fc7\u7a0b\uff09
3.\uff08\u521b\u65b0\u9898\uff09\u5c0f\u4e3d\u548c\u5c0f\u6674\u662f\u4e00\u5bf9\u597d\u670b\u53cb\uff0c\u4f46\u5c0f\u4e3d\u8fd1\u671f\u6c89\u8ff7\u4e0e\u7f51\u7edc\uff0c\u4e0d\u6c42\u4e0a\u8fdb\uff0c\u5c0f\u6674\u51b3\u5b9a\u4e0d\u4ea4\u8fd9\u4e2a\u670b\u53cb\uff0c\u5c31\u7ed9\u4e86\u5979\u4e00\u4e2a\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u8bf4\uff1a\u201c\u89e3\u8fd9\u4e2a\u65b9\u7a0b\u5427\uff0c\u8fd9\u5c31\u662f\u6211\u4eec\u7684\u7ed3\u679c\uff01\u201d\u5c0f\u4e3d\u89e3\u5b8c\u8fd9\u4e2a\u65b9\u7a0b\u5927\u5403\u4e00\u60ca\uff0c\u539f\u6765\u628a\u8fd9\u4e24\u4e2a\u8ddf\u653e\u5728\u4e00\u8d77\u662f\u201c886\u201d\uff08\u7f51\u7edc\u8bed\u201c\u62dc\u62dc\u4e86\u201d\uff09\u3002\u540c\u5b66\u4f60\u80fd\u8bbe\u8ba1\u4e00\u4e2a\u8fd9\u6837\u7684\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u9ebc\uff1f
4.\uff08\u5f00\u653e\u63a2\u7a76\u9898\uff09\u8bbe\u4ee3\u6570\u5f0f2x^2+4x-3=M\uff0c\u7528\u914d\u65b9\u6cd5\u8bf4\u660e\uff1a\u65e0\u8bbax\u53d6\u4f55\u503c\uff0cM\u603b\u4e0d\u5c0f\u65bc\u4e00\u5b9a\u503c\uff0c\u5e76\u6c42\u51fa\u8be5\u503c\uff08\u8981\u6c42\u5168\u8fc7\u7a0b\uff09
-5x+x<-35
X^2+5X-6
--------- \uff08\u7ea6\u5206\uff09
X^2-3X+2
A^2-1 2A-A^2
-------- + ---------
A^2-2A+A A^2-A-2
X^2-Y^2 X
\uff08---------)^2 \u9664\u4ee5 \uff08X+Y) * (-----)^3 \u5176\u4e2dX=-1/2\uff0cY=-1
XY X-Y
)(0.5x-1/2)(1/2x+0.5)=?(\u8981\u5199\u51fa\u8ba1\u7b97\u8fc7\u7a0b)
a(x+y)-b(x+y)-x-y
(x-1/y)\u00f7(y-1/x)
[(x+1)/(x^2-x)+4/(1-x^2)]\u00f7[(x^2-2x-3)/(x^2+3x)](1+x)^2
(\u221a6+\u221a5)\u76842006\u6b21\u65b9 X (\u221a6-\u221a5)\u76842006\u6b21\u65b9
\u7b54\u6848\uff1a\u3010\u89e3\u4e0b\u5217\u65b9\u7a0b\u3011
1\u3001(2X)^2-1=0
\u79fb\u9879\uff0c\u5f97\uff1a(2X)^2=1
\u5f00\u5e73\u65b9\uff0c\u5f97\uff1a2X=+-1
\u65b9\u7a0b\u4e24\u8fb9\u90fd\u9664\u4ee52\uff0c\u5f97\uff1aX=+-1/2
2\u30011/2(X+3)^2=2
\u65b9\u7a0b\u4e24\u8fb9\u90fd\u4e58\u4ee52\uff0c\u5f97\uff1a(X+3)^2=4
\u5f00\u5e73\u65b9\uff0c\u5f97\uff1aX+3=+-2
\u65b9\u7a0b\u4e24\u8fb9\u90fd\u51cf\u53bb3\uff0c\u5f97\uff1aX=-1\u6216-5
3\u3001X^2+2X-8=0
\u5de6\u8fb9\u8fdb\u884c\u56e0\u5f0f\u5206\u89e3\uff0c\u5f97\uff1a(X+2)(X-4)=0
X+2=0\u6216X-4=0
X=-2\u6216X=4
4\u30013X^2=4X-1
\u79fb\u9879\uff0c\u5f97\uff1a3X^2-4X+1=0
\u5de6\u8fb9\u8fdb\u884c\u56e0\u5f0f\u5206\u89e3\uff0c\u5f97\uff1a(3X-1)(X-1)=0
3X-1=0\u6216X-1=0
X=1/3\u6216X=1
5\u3001X(3X-2)-6X^2=0
3X^2-2X-6X^2=0
\u6574\u7406\uff0c\u5f97\uff1a-3X^2-2X=0
\u65b9\u7a0b\u4e24\u8fb9\u90fd\u9664\u4ee5-1\uff0c\u5f97\uff1a3X^2+2X=0
\u5de6\u8fb9\u8fdb\u884c\u56e0\u5f0f\u5206\u89e3\uff0c\u5f97\uff1aX(3X+2)=0
X=0\u62163X+2=0
X=0\u6216X=-2/3
6\u3001(2X-3)^2=X^2
4X^2-12X+9=X^2
\u65b9\u7a0b\u4e24\u8fb9\u90fd\u51cf\u53bbX^2\uff0c\u5f97\uff1a3X^2-12X+9=0
\u65b9\u7a0b\u4e24\u8fb9\u90fd\u9664\u4ee53\uff0c\u5f97\uff1aX^2-4X+3=0
\u5de6\u8fb9\u8fdb\u884c\u56e0\u5f0f\u5206\u89e3\uff0c\u5f97\uff1a(X-1)(X-3)=0
X-1=0\u6216X-3=0
X=1\u6216X=3
\u3010\u4e00\u3001\u914d\u5b8c\u5168\u5e73\u65b9\u5f0f\u3011
1\u3001 x^2-4x+4=\uff08x-2\uff09^2
2\u3001 x^2+mx+9\u662f\u4e00\u4e2a\u5b8c\u5168\u5e73\u65b9\u5f0f\uff0c\u5219m=6
\u3010\u4e8c\u3001\u914d\u65b9\u6cd5\u89e3\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u3011
X^2-8X-9=0
X^2-8X=9
X^2-8X+16=9+16
(X-4)^2=25
(X-4)^2=5^2
X-4=+-5
X=9\u6216-1
\u3010\u57fa\u7840\u8fbe\u6807\u3011
1\u3001C
2\u3001D
3\u3001\u586b\u7a7a
\u2460 x^2+8x+16=\uff08x+4)^2
\u24612x^2-12x+18=2\uff08x-3\uff09^2
4.\u7528\u914d\u65b9\u6cd5\u89e3\u4e0b\u5217\u65b9\u7a0b\uff08\u8981\u8fc7\u7a0b\uff09
\u2460X^+5X+3=0
X^+5X=-3
x^+5X+(5/2)^2=(5/2)^2-3
(X+5/2)^2=13/4
X+5/2=+-\u221a13/2
X=(\u221a13-5)/2\u6216-(\u221a13+5)/2
\u24612X^2-X-3=0
X^2-1/2X=3/2
X^2-1/2X+(1/4)^2=3/2+(1/4)^2
(X-1/4)^2=25/16
X-1/4=+-5/4
X=3/2\u6216X=-1
\u3010\u57fa\u7840\u6269\u5c55\u3011
1\u3001B
2\u3001X^2+2mX-n^2=0
X^2+2mX=n^2
X^2+2mX+m^2=n^2+m^2
(X+m)^2=n^2+m^2
X+m=+-\u221a(n^2+m^2)
X=-m+-\u221a(n^2+m^2)
3\u3001\u4e0d\u662f\u5f88\u6e05\u695a\u9898\u610f\uff0c\u4e24\u4e2a\u6839\u653e\u5728\u4e00\u8d77\u662f886\u4e09\u4e2a\u6570\uff0c\u662f\u52a0\u8d77\u6765\u8fd8\u662f\u600e\u4e48\u7ec4\u5408\u5462\uff0c\u5982\u679c\u662f8\u548c6\u7684\u8bdd\uff0c\u5f88\u7b80\u5355\uff0c(X-8)(X-6)=0\u5c31\u53ef\u4ee5\u4e86\uff0c\u5c55\u5f00\u5c31\u662fX^2-14X+48=0
\u5982\u679c\u4e24\u4e2a\u6839\u662f88\u548c6\uff0c(X-88)(X-6)=0\uff0c\u5c55\u5f00\u5c31\u662fX^2-94X+528=0
4\u30012X^2+4X-3=M
M=2X^2+4X-3
=2(X^2+2X)-3
=2(X^2+2X+1-1)-3
=2(X^2+2X+1)-5
=2(X+1)^2-5
\u65e0\u8bbaX\u53d6\u4f55\u503c\uff0c2(X+1)^2\u6052\u5927\u4e8e0\uff0c\u5219M\u6052\u5927\u4e8e-5\u3002
(4)5x－5y＋5z (5)-5a²+25a-5a (6)2a(b+c)-3(b+c) (7)(ab+a)+(b+1)
(8)-4m³+16m³-28m (9)16x-25x³y² (10)36m²a-9m²a²-36m²
√32-3√1/2+√2
√12+√27/√3-√1/3×√12
√50+√30/√8-4
（√6-2√15）×√3-6√1/2
√2/3-4√216+43√1/6
√8+√30-√2
√40-5√1/10+√10
√2+√8/√2
√2/9+√50+√32
（1-√3）（√3+2）
（√8+3√6）÷√2-√3×√0.7
（-3+√6）（-3-√6）-（√3-1/√3）²
³√0.125-√3 1/16+³√（1-7/8）²
√2/3-√216+42√1/6
解方程√3 X-1=√2 X
求X
{√5 X-3√ Y=1}
{√3 X-√5 Y=2}
注：X全部不在根号内
√（1/2x）^2＋10/9x^2
=√[1/(4x^2)+10/(9x^2)]
=√49/36x^2
若x>0,=7/(6x)
若x<0,=-7/(6x)
√a^4mb^2n＋1
=√(a^2mb^n)^2＋1
=a^2mb^n＋1
√（4a^5＋8a^4）（a^2＋3a＋2）
=√[4a^4(a+2)][(a+2)(a+1)]
=√[4a^4(a+2)^2(a+1)]
=2a^2(a+2)√(a+1)
. 3√（1/6）-4√（50）+30√（2/3）
答案3√（1/6）-4√（50）+30√（2/3）
= 3×√6/6-4×5√2+30×√6/3
＝√6/2-20√2+10√6
2. （1-根号2）/2乘以（1＋根号2）／2
题是这样的二分之一减根号2乘以二分之一加根号2
答案：（1-根号2）/2乘以（1＋根号2）／2
=（1-√2）*（1-√2）／4
＝（1－2）／4
＝－1／4
1.3√（1/6）-4√（50）+30√（2/3） 答案3√（1/6）-4√（50）+30√（2/3） = 3×√6/6-4×5√2+30×√6/3 ＝√6/2-20√2+10√6 2. （1-根号2）/2乘以（1＋根号2）／2 题是这样的二分之一减根号2乘以二分之一加根号2 答案：（1-根号2）/2乘以（1＋根号2）／2 =（1-√2）*（1-√2）／4 ＝（1－2）／4 ＝－1／4 3.√（1/2x）^2＋10/9x^2 √[（1/2x）^2＋10/9x^2] =√(x^2/4+10x^2/9) =√(9x^2/36+40x^2/36) =√(49x^2/36) =7x/6; 4.√a^4mb^2n＋1（a、b为正数） [√(a^4mb^2n)]＋1（a、b为正数） =a^2mb^n+1; 5.√（4a^5＋8a^4）（a^2＋3a＋2）（a>=0） √[（4a^5＋8a^4）（a^2＋3a＋2）]（a>=0） =√[4a^4(a+2)(a+2)(a+1)] =√[(2a^2)^2(a+2)^2(a+1)] =2a^2(a+2)√(a+1).
①5√8-2√32+√50 =5*3√2-2*4√2+5√2 =√2(15-8+5) =12√2 ②√6-√3/2-√2/3 =√6-√6/2-√6/3 =√6/6 ③(√45+√27)-(√4/3+√125) =(3√5+3√3)-(2√3/3+5√5) =-2√5+7√5/3 ④(√4a-√50b)-2(√b/2+√9a) =(2√a-5√2b)-2(√2b/2+3√a) =-4√a-6√2b ⑤√4x*(√3x/2-√x/6) =2√x(√6x/2-√6x/6) =2√x*(√6x/3) =2/3*x*√6 ⑥(x√y-y√x)÷√xy =x√y÷√xy-y√x÷√xy =√x-√y ⑦(3√7+2√3)(2√3-3√7) =(2√3)^2-(3√7)^2 =12-63 =-51 ⑧(√32-3√3)(4√2+√27) =(4√2-3√3)(4√2+3√3) =(4√2)^2-(3√3)^2 =32-27 =5 ⑨(3√6-√4)² =(3√6)^2-2*3√6*√4+(√4)^2 =54-12√6+4 =58-12√6 ⑩（1+√2-√3）（1-√2+√3） =[1+(√2-√3)][1-(√2-√3)] =1-(√2-√3)^2 =1-(2+3+2√6) =-4-2√6 1. =5√5 - 1/25√5 - 4/5√5 =√5*(5-1/25-4/5) =24/5√5 2.=√144+576 =√720 =12√5 3.)√(8/13)^2-(2/13)^2 = √(8/13+2/13)(8/13-2/13) =(2/13)√15
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绛旓細绛旀:f (x)=2x 7. 缁冧範4:宸茬煡f (x)鏄簩娆″嚱鏁,婊¤冻f(0)=1涓攆 (x 1) - f (x)=2x,姹俧 (x) 绛旀:f (x) = x2- x 1 渚3.璁緁(x)鏄疪涓婄殑鍑芥暟,涓旀弧瓒砯(0)=1,骞朵笖瀵逛换鎰瀹炴暟x,y 鏈塮(x-y)=f(x)-y(2x-y 1),姹俧(x) 绛旀:f (x) =x2 x 1 缁冧範5:鍑芥暟f(x)瀵逛换浣晉鈭...
绛旓細6,a^2-ab+2b^2=3 姹2ab-2a^2-4b^2-7鐨勫 2ab-2a^2-4b^2-7 =2(ab-a^2-2b^2)-7 =-2(a^2-ab+2b^2)-7 =(-2)*3-7 =-6-7 =-13 7,鑻=2x^2+3xy-2x-3,B=-x^2+xy+2,涓3A+6B鐨勫间笌x鏃犲叧,姹倅鐨勫 3A+6B=6x^2+9xy-6x-9-6x^2+6xy+12 =15xy-6x+...
绛旓細姹100閬鍒濅簩涓嬪鏈熸暟瀛璁＄畻棰1.鍥犲紡鍒嗚В(4a+5b)² - (5a-4b)²2.鍥犲紡鍒嗚В x² - y² + 10x + 253.鍖栫畝鍚庢眰鍊(1/2x+1/3y)² - (1/3x+1/2y)² - (5/6x+5/6y)(1/6
绛旓細6.鍏充簬x鐨勪笉绛夊紡缁剓 3x+2/4>x+a 鏈夊洓涓暣鏁拌В,姹俛鐨勫彇鍊艰寖鍥 7.濡傛灉涓嶇瓑寮忕粍{ 4b-3x<3a ...10.宸茬煡a銆乥銆乧銆乨鏄瀹炴暟,涓 ,缁欏嚭涓嬪垪4涓笉绛夊紡:鈶;鈶;鈶;鈶 ,鍏朵腑姝ｇ‘鐨勬槸 .11.鑻,...2012-02-23 璋佽兘缁欐垜100閬涓鍏冧竴娆′笉绛夊紡棰?? 2 2012-11-23 100閬撳垵涓涓嶇瓑寮璁＄畻棰绛旀,璋㈣阿...
