给定一组整数,要求利用数组把这组数保存起来,然后实现对数组的循环移动 一道关于数的循环移动的编程题目

C\u8bed\u8a00 \u6570\u7ec4\u7684\u5faa\u73af\u79fb\u52a8

\u8981\u6c42\u6ee1\u8db3\u9519\u8bef\uff1a
\u8981\u6c42\u53ea\u7528\u4e00\u4e2a\u6570\u7ec4\u7684\u65b9\u5f0f\u5b9e\u73b0\uff0c\u4e00\u5b9a\u8981\u4fdd\u8bc1\u5728\u8f93\u51fa\u7ed3\u679c\u65f6\uff0c\u8f93\u51fa\u7684\u987a\u5e8f\u548c\u6570\u7ec4\u4e2d\u6570\u7684\u987a\u5e8f\u662f\u4e00\u81f4\u7684\u3002
#includeint main(){int array[100];int m, n, i,j, tmp, distance;scanf("%d%d", &n, &m);for (i = 0; i i - distance; --j){array[j] = array[j - 1];}array[i - distance + 1] = tmp;}for (i = 0; i < n; ++i){ //\u8f93\u51faprintf("%d", array[i]);if (i != n - 1)printf(" ");}printf("\n");return 0;}

\u4f60\u662f\u600e\u6837\u5199\u7684\u554a\uff1f

#include<stdio.h>
void main()
{
int a[100],b,c,i,j,temp;
scanf("%d%d",&b,&c);
for(i=0;i<b;i++)
scanf("%d",&a[i]);
for(i=0;i<11-c;i++)
{
temp=a[0];
for(j=0;j<b-1;j++)
a[j]=a[j+1];
a[j]=temp;
}
for(i=0;i<b;i++)
printf("%d ",a[i]);
printf("\n");
}

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