(2x-1)^2=(3-x)^2用因式分解法解 (2x-1)^2=(3-x)^2
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\u5f00\u5e73\u65b9\uff1a
2x\uff0d1\uff1d�\uff083\uff0dx\uff09
\u4f9d\u6b21\u53d6\u201c\uff0b\u201d\u3001\u201c\uff0d\u201d\u5404\u5f97\u4e00\u4e2a\u4e00\u5143\u4e00\u6b21\u65b9\u7a0b\uff0c\u63a5\u7740\u518d\u89e3\u8fd9\u4e24\u4e2a\u65b9\u7a0b\u5c31\u884c\u4e86\u3002
(2x-1)^2=(3-x)^2
(2x-1)^2-(3-x)^2=0
(2x-1+3-x)(2x-1-3+x)=0
(x+2)(3x-4)=0
x1=-2
x2=4/3
扩展资料：
因式分解法解一元二次方程的一般步骤如下：
1、移项，使方程的右边化为零；
2、将方程的左边转化为两个一元一次方程的乘积；
3、令每个因式分别为零
4、括号中x，它们的解就都是原方程的解。
(2x-1)²=(3-x)²
4x² -2x -2x +1 = 9 -3x -3x +x²
3x² +2x -8 = 0
x² +2/3x -8/3 = 0
x² +2/3x +1/9 = 8/3 +19
x² +2/3x +1/9 = 25/9
(x + 1/3)(x + 1/3) = 25/9
x + 1/3 = ±5/3
x = ±5/3 - 1/3
x₁= 43
x₂ = -2
(2x-1)²=(3-x)²
(2x-1)²=(x-3)²
(2x-1)²-(x-3)²=0
(2x-1+x-3)(2x-1-x+3)=0
(3x-4)(x+2)=0
x1=-2
x2=4/3
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