八年级下册数学二次根式的计算题，有悬赏!!! 求八年级数学200道二次根式的计算题~
\u521d\u4e8c\u6570\u5b66\u4e8c\u6b21\u6839\u5f0f\u8ba1\u7b97\u9898\u3002\u6362\u4e00\u4e0b\u5404\u90e8\u5206\u7684\u987a\u5e8f\uff0c\u4ee5\u6b64\u51d1\u6210\u5e73\u65b9\u5dee\u516c\u5f0f\uff0c\u770b\u5f97\u51fa\u9898\u4e3b\u7684\u601d\u8def\u662f\u5bf9\u7684\u4f46\u662f\u4e0d\u8981\u5c40\u9650\u4e8e\u9898\u76ee\u672c\u8eab\u7ed9\u7684\u5f62\u5f0f\uff0c\u8981\u7075\u6d3b\u7efc\u5408\u8fd0\u7528\u5404\u79cd\u65b9\u6cd5\u54e6\uff01
\u6269\u5c55\u5185\u5bb9\uff1a
\u4e00\u4e9b\u5316\u7b80\u6839\u5f0f\u7684\u5c0f\u65b9\u6cd5
\u4e00\uff0c \u5316\u7b80\u5e26\u6839\u53f7\u7684\u5b9e\u6570\u7684\u4e3b\u8981\u4f9d\u636e1\uff0c(\u221aa)=a(a\u22650), ( \u573a\u861f)=a.2,\u221aa=\u2223a\u2223 \u573a\u861f=a.3,\u221aab=\u221aa\u221ab(a\u22650,b\u22650)4,\u221aa/b=\u221aa/\u221ab(a\u22650,b>0)\u4e0a\u8ff0\u516c\u5f0f\u53ef\u4ece\u5de6\u5230\u53f3\uff0c\u4e5f\u53ef\u4ece\u53f3\u5230\u5de6\u8fd0\u7528\u4e8e\u5316\u7b80\uff0c\u53e6\u5916\u8fd8\u8981\u7528\u5230\u6574\u5f0f\u4e58\u6cd5\u6cd5\u5219\uff0c\u4e58\u6cd5\u516c\u5f0f\u7b49\u3002
\u4e8c\uff0c \u5316\u7b80\u5e26\u6839\u53f7\u7684\u5b9e\u6570\u7684\u7ed3\u679c\u7684\u8981\u6c42\uff1a1\uff0c\u6839\u53f7\u5185\u4e0d\u80fd\u542b\u6709\u80fd\u5f00\u65b9\u7684\u56e0\u6570\uff08\u56e0\u5f0f\uff092\uff0c \u6839\u53f7\u5185\uff08\u88ab\u5f00\u65b9\u6570\uff09\u4e0d\u542b\u5206\u6bcd3\uff0c \u5206\u6bcd\u4e0a\u4e0d\u5e26\u6839\u53f7\u3002
\u5e0c\u671b\u53ef\u4ee5\u5e2e\u5230\u4f60\u54e6
\u89e3\u65b9\u7a0b\u221a3 X-1=\u221a2 X
\u6c42X
{\u221a5 X-3\u221a Y=1}
{\u221a3 X-\u221a5 Y=2}
\u6ce8\uff1aX\u5168\u90e8\u4e0d\u5728\u6839\u53f7\u5185
\u221a\uff081/2x\uff09^2\uff0b10/9x^2
=\u221a[1/(4x^2)+10/(9x^2)]
=\u221a49/36x^2
\u82e5x>0,=7/(6x)
\u82e5x<0,=-7/(6x)
\u221aa^4mb^2n\uff0b1
=\u221a(a^2mb^n)^2\uff0b1
=a^2mb^n\uff0b1
\u221a\uff084a^5\uff0b8a^4\uff09\uff08a^2\uff0b3a\uff0b2\uff09
=\u221a[4a^4(a+2)][(a+2)(a+1)]
=\u221a[4a^4(a+2)^2(a+1)]
=2a^2(a+2)\u221a(a+1)
. 3\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09
\u7b54\u68483\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09
= 3\u00d7\u221a6/6-4\u00d75\u221a2+30\u00d7\u221a6/3
\uff1d\u221a6/2-20\u221a2+10\u221a6
2. \uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2
\u9898\u662f\u8fd9\u6837\u7684\u4e8c\u5206\u4e4b\u4e00\u51cf\u6839\u53f72\u4e58\u4ee5\u4e8c\u5206\u4e4b\u4e00\u52a0\u6839\u53f72
\u7b54\u6848\uff1a\uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2
=\uff081-\u221a2\uff09*\uff081-\u221a2\uff09\uff0f4
\uff1d\uff081\uff0d2\uff09\uff0f4
\uff1d\uff0d1\uff0f4
1.3\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09 \u7b54\u68483\u221a\uff081/6\uff09-4\u221a\uff0850\uff09+30\u221a\uff082/3\uff09 = 3\u00d7\u221a6/6-4\u00d75\u221a2+30\u00d7\u221a6/3 \uff1d\u221a6/2-20\u221a2+10\u221a6 2. \uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2 \u9898\u662f\u8fd9\u6837\u7684\u4e8c\u5206\u4e4b\u4e00\u51cf\u6839\u53f72\u4e58\u4ee5\u4e8c\u5206\u4e4b\u4e00\u52a0\u6839\u53f72 \u7b54\u6848\uff1a\uff081-\u6839\u53f72\uff09/2\u4e58\u4ee5\uff081\uff0b\u6839\u53f72\uff09\uff0f2 =\uff081-\u221a2\uff09*\uff081-\u221a2\uff09\uff0f4 \uff1d\uff081\uff0d2\uff09\uff0f4 \uff1d\uff0d1\uff0f4 3.\u221a\uff081/2x\uff09^2\uff0b10/9x^2 \u221a[\uff081/2x\uff09^2\uff0b10/9x^2] =\u221a(x^2/4+10x^2/9) =\u221a(9x^2/36+40x^2/36) =\u221a(49x^2/36) =7x/6; 4.\u221aa^4mb^2n\uff0b1\uff08a\u3001b\u4e3a\u6b63\u6570\uff09 [\u221a(a^4mb^2n)]\uff0b1\uff08a\u3001b\u4e3a\u6b63\u6570\uff09 =a^2mb^n+1; 5.\u221a\uff084a^5\uff0b8a^4\uff09\uff08a^2\uff0b3a\uff0b2\uff09\uff08a>=0\uff09 \u221a[\uff084a^5\uff0b8a^4\uff09\uff08a^2\uff0b3a\uff0b2\uff09]\uff08a>=0\uff09 =\u221a[4a^4(a+2)(a+2)(a+1)] =\u221a[(2a^2)^2(a+2)^2(a+1)] =2a^2(a+2)\u221a(a+1). \u592a\u591a\u4e86\u5440\uff0c\u53ea\u80fd\u8fd9\u6837\u4e86\uff0c\u6211\u8fd8\u6709\u4e8b \u60a8\u597d\uff01 \u24605\u221a8-2\u221a32+\u221a50 =5*3\u221a2-2*4\u221a2+5\u221a2 =\u221a2(15-8+5) =12\u221a2 \u2461\u221a6-\u221a3/2-\u221a2/3 =\u221a6-\u221a6/2-\u221a6/3 =\u221a6/6 \u2462(\u221a45+\u221a27)-(\u221a4/3+\u221a125) =(3\u221a5+3\u221a3)-(2\u221a3/3+5\u221a5) =-2\u221a5+7\u221a5/3 \u2463(\u221a4a-\u221a50b)-2(\u221ab/2+\u221a9a) =(2\u221aa-5\u221a2b)-2(\u221a2b/2+3\u221aa) =-4\u221aa-6\u221a2b \u2464\u221a4x*(\u221a3x/2-\u221ax/6) =2\u221ax(\u221a6x/2-\u221a6x/6) =2\u221ax*(\u221a6x/3) =2/3*x*\u221a6 \u2465(x\u221ay-y\u221ax)\u00f7\u221axy =x\u221ay\u00f7\u221axy-y\u221ax\u00f7\u221axy =\u221ax-\u221ay \u2466(3\u221a7+2\u221a3)(2\u221a3-3\u221a7) =(2\u221a3)^2-(3\u221a7)^2 =12-63 =-51 \u2467(\u221a32-3\u221a3)(4\u221a2+\u221a27) =(4\u221a2-3\u221a3)(4\u221a2+3\u221a3) =(4\u221a2)^2-(3\u221a3)^2 =32-27 =5 \u2468(3\u221a6-\u221a4)² =(3\u221a6)^2-2*3\u221a6*\u221a4+(\u221a4)^2 =54-12\u221a6+4 =58-12\u221a6 \u2469\uff081+\u221a2-\u221a3\uff09\uff081-\u221a2+\u221a3\uff09 =[1+(\u221a2-\u221a3)][1-(\u221a2-\u221a3)] =1-(\u221a2-\u221a3)^2 =1-(2+3+2\u221a6) =-4-2\u221a6 1. =5\u221a5 - 1/25\u221a5 - 4/5\u221a5 =\u221a5*(5-1/25-4/5) =24/5\u221a5 2.=\u221a144+576 =\u221a720 =12\u221a5 3.)\u221a(8/13)^2-(2/13)^2 = \u221a(8/13+2/13)(8/13-2/13) =(2/13)\u221a15 \u53c2\u8003\u8d44\u6599\uff1ahttp://zhidao.baidu.com/question/68013881.html \u4e5d\u5e74\u7ea7\u6570\u5b66\u6d4b\u9a8c\u5377 \u300a\u4e8c\u6b21\u6839\u5f0f\u300b \u73ed\u7ea7\uff1a \u59d3\u540d\uff1a \u5ea7\u53f7\uff1a \u6210\u7ee9\uff1a \u4e00. \u9009\u62e9\u9898\u3002\uff08\u6bcf\u98984\u5206\uff0c\u517120\u5206\uff09 1. \u82e5 \u6709\u610f\u4e49\uff0c\u5219 \u80fd\u53d6\u5f97\u6700\u5c0f\u6574\u6570\u662f\uff08 \uff09 A. 0 B. 1 C. -1 D. -4 2. \u5df2\u77e5 \uff0c\u5219 \u7684\u503c\u4e3a\uff08 \uff09 A. 1 B. -1 C. D. \u4ee5\u4e0a\u7b54\u6848\u90fd\u4e0d\u5bf9 3. \u7684\u6574\u6570\u90e8\u5206\u4e3a \uff0c \u7684\u6574\u6570\u90e8\u5206\u4e3a \uff0c\u5219 \u7684\u503c\u662f\uff08 \uff09 A. 1 B. 2 C. 4 D. 9 4. \u628a \u6839\u53f7\u5916\u7684\u56e0\u5f0f\u79fb\u5230\u6839\u53f7\u5185\uff0c\u5f97\uff08 \uff09 A. B. C. D. 5. \u82e5 \uff0c\u5219 \u7684\u503c\u662f\uff08 \uff09 A. -2 B. 0 C. 2 D. \u4e8c. \u586b\u7a7a\u9898\u3002\uff08\u6bcf\u98984\u5206\uff0c\u517120\u5206\uff09 6. \u82e5\u4e8c\u6b21\u6839\u5f0f \u6709\u610f\u4e49\uff0c\u5219 \u7684\u53d6\u503c\u8303\u56f4\u662f \u3002 7. \u5df2\u77e5 \uff0c\u5219 \u3002 8. \u6bd4\u8f83\u5927\u5c0f\uff1a \u3002 9. \u5728\u5b9e\u6570\u8303\u56f4\u5185\u56e0\u5f0f\u5206\u89e3\uff1a \u3002 10. \u82e5 \uff0c\u5219 \u3002 \u4e09. \u8ba1\u7b97\u3002\uff08\u6bcf\u98987\u5206\uff0c\u517128\u5206\uff09 11. 12. 13. 14. \u56db. \u89e3\u7b54\u9898\u3002\uff0815\u201516\u9898\u6bcf\u989810\u5206\uff0c17\u989812\u5206\uff09 15. \u5982\u56fe\uff1a\u9762\u79ef\u4e3a48 \u7684\u6b63\u65b9\u5f62\u56db\u4e2a\u89d2\u662f\u9762\u79ef\u4e3a3 \u7684\u5c0f\u6b63\u65b9\u5f62\uff0c\u73b0\u5c06\u56db\u4e2a\u89d2\u526a\u6389\uff0c\u5236\u4f5c\u4e00\u4e2a\u65e0\u76d6\u7684\u957f\u65b9\u4f53\u76d2\u5b50\uff0c\u6c42\u8fd9\u4e2a\u957f\u65b9\u4f53\u7684\u5e95\u9762\u8fb9\u957f\u548c\u9ad8\u5206\u522b\u662f\u591a\u5c11\uff1f\uff08\u7cbe\u786e\u52300.1 \uff09 16. \u5f53 \u65f6\uff0c\u5316\u7b80\uff1a 17. \u82e5\u6700\u7b80\u4e8c\u6b21\u6839\u5f0f \u662f\u540c\u7c7b\u4e8c\u6b21\u6839\u5f0f\u3002 \u2474. \u6c42 \u7684\u503c\u3002 \u2475. \u6c42 \u5e73\u65b9\u548c\u7684\u7b97\u672f\u5e73\u65b9\u6839\u3002 \u7b54\u6848\uff1a 1\u2015\u20155\uff1a ABDDD 6. \uff1b 7. 8\uff1b 8. \uff1b 9. \uff1b 10. 0\uff1b 11. \uff1b 12. \uff1b 13. \uff1b 14. \uff1b 15. \u5e95\u9762\u8fb9\u957f\u4e3a3.5cm\uff1b \u9ad8\u4e3a1.7cm\uff1b 16. \uff1b 17. \u3001
\u4e0a\u54ea\u53bb\u5f04\u90a3\u4e48\u4e9b \u81ea\u5df1\u7f16\u6216\u8005\u4e0a\u4e66\u5e97\u53bb\u627e\u51e0\u672c\u7ec3\u4e60\u518c \u81ea\u5df1\u64cd\uff01\uff01\uff01\uff01\uff01\uff01\uff01
第二道=7b²c*根号c/6a
第三道=九分之二倍根号5
第四道=二分之根号10除以三分之根号21乘以五分之7=二分之根号10乘以根号21分之3乘以五分之7=二百一十分之二十一倍根号210
第五道=2倍根号3+3倍根号3-4倍根号三=根号3
第六道=2倍根号二+5倍根号2-3倍根号2=4倍根号2
第七道=x倍的根号3x+3倍根号3x=（3+x）3x
不谢。
请在此输入您的回答，每一次专业解答都将打造您的权威形象
绛旓細(1)鈭氾紙12^2+24^2)=鈭(12^2+2^2*12^2)=鈭12^2*(1+2^2)=鈭12^2*鈭(1+4)=12鈭5 (2)鈭歔(8/13)^2-(2/13)^2]=鈭(8/13+2/13)(8/13-2/13)=鈭(10*6/13^2)=鈭(2^2*15/13^2)=鈭(2/13)^2*鈭15 =(2/13)鈭15 ...
绛旓細6銆=(1/8)脳(鈭(18梅27/2)=1/8脳鈭(4/3)=1/8脳鈭(4/9脳3锛=1/8脳2/3 鈭3=1/12 鈭3 7銆=2鈭(6x²梅x/3)=2鈭(18x)=6鈭(2x)8銆=鈭氾紙4/3脳3/7脳5/7)=鈭(4/49脳5)=2/7 鈭5 9銆亁>=0 x-3>0 鈭磝>3 10銆=1/6鈭6+2鈭6-10鈭6 =-47/6 鈭6 ...
绛旓細x²+2xy+y²=锛坸+y锛²=锛堚垰3+1+鈭3-1 锛²=锛2鈭3锛²=12
绛旓細鈭6锛堚垰3-鈭2)=3鈭2-2鈭3 涓嶆噦鍙互鍐嶉棶锛佷竴鐩村埌浣犳槑鐧戒负姝紝鏈夊府鍔╄鍙婃椂鐐瑰嚮銆愰噰绾充负婊℃剰鍥炵瓟銆戞寜閽紝鎴栧湪瀹㈡埛绔彸涓婅璇勪环鐐广愭弧鎰忋戙傝阿璋紒浣犵殑閲囩撼鏄垜鍓嶈繘鐨勫姩鍔! 浣犵殑閲囩撼涔熶細缁欎綘甯︽潵璐㈠瘜鍊笺傛垜浠浉浜掑涔狅紒鍏卞悓杩涙锛佸笇鏈涗笅娆¤兘鍐嶅府鍔╀綘锛
绛旓細绗竴棰橈細X(2-鈭2)=(鈭2-2)X(2-鈭2)=-1(2-鈭2锛墄=1绗浜岄锛氱敤浜岄櫌浜屾鏂圭▼鍏紡瑙-b卤鏍瑰彿涓媌^2-4ac/2a 绗笁棰橈細3x锛坸-1锛=2-2x 3x锛坸-1锛=-2锛坸-1锛3x锛坸-1锛+2锛坸-1锛=0 锛3x+2锛夛紙x-1锛=0 鎵浠=1鎴-3/2绗洓棰橈細锛坢+2锛夛紙2m-5锛=-10 2m^2-5m+4m...
绛旓細濡傚浘鎵绀烘湜閲囩撼
绛旓細鈭0.12 =鈭氾紙3/25锛=鈭3/5 =0.2鈭5 鈭48 =鈭氾紙16*3锛=4鈭3 鎵浠ュ彲浠ュ悎骞 鈭0.12+鈭48=4.2鈭3
绛旓細鍘熷紡=鈭16-鈭6+鈭24 =4-鈭6+2鈭6 =4+鈭6
绛旓細鍒濅簩鏁板浜屾鏍瑰紡璁＄畻棰(瑕佽缁嗚繃绋) (1)(鏍瑰彿3-2)(鏍瑰彿3+2)(2)(2鍊嶆牴鍙2=3)鐨勫钩鏂(3)2鏍瑰彿20脳4鍒嗕箣1梅4鍊嶆牴鍙5(4)鏍瑰彿6鍒嗕箣1+鏍瑰彿24-鏍瑰彿6000(5)(5-2鍊嶆牴鍙6)脳(鏍瑰彿2-鏍瑰彿3)鏀规(2)(2鍊嶆牴鍙2+3)鐨... (1)(鏍瑰彿3-2)(鏍瑰彿3+2)(2)(2鍊嶆牴鍙2=3)鐨勫钩鏂(3)2鏍瑰彿20脳4鍒嗕箣...
绛旓細a(n) = 1/[n^(1/2) + (n+1)^(1/2)]= [(n+1)^(1/2) - n^(1/2)]/{[n^(1/2) + (n+1)^(1/2)] [(n+1)^(1/2) - n^(1/2)]} = [(n+1)^(1/2) - n^(1/2)]/[(n+1) - n]= (n+1)^(1/2) - n^(1/2)a(1) + a(2) + ... + a(...
