设int数据占用两个字节,float数据占用四个字节,double数据占用8个字节,且已知floa 在c语言中,整型变量int为什么占4个字节?float占4个...

12 \u8bbeint\u6570\u636e\u5360\u7528\u4e24\u4e2a\u5b57\u8282\uff0cfloat\u6570\u636e\u5360\u7528\u56db\u4e2a\u5b57\u8282\uff0cdouble\u6570\u636e\u5360\u75288\u4e2a\u5b57\u8282\uff0c\u4e14\u5df2\u77e5f

\u9009A

int\u5360\u591a\u5c11\u4e2a\u5b57\u8282\u662f\u7531\u7f16\u8bd1\u5668\u51b3\u5b9a\u7684\uff0cANSI\u6807\u51c6\u5b9a\u4e49int\u662f\u53602\u4e2a\u5b57\u8282\uff0e
TC\u662f\u6309ANSI\u6807\u51c6\u7684\uff0c\u5b83\u7684int\u662f\u53602\u4e2a\u5b57\u8282\u7684\uff0e
\u4f60\u53ef\u4ee5\u5728TC\u91cc\u8bd5\uff0eprintf("%d",sizeof(int));\u7ed3\u679c\u662f2\uff1b
\u4f46\u662f\u5728VC\u91cc\uff0c\u4e00\u4e2aint\u662f\u53604\u4e2a\u5b57\u8282\u7684\uff0c\u5728VC\u91cc\u9762\uff0c
printf("%d",sizeof(int));
cout<<sizeof(int);\u7ed3\u679c\u90fd\u662f4\uff0e
\u4e0d\u540c\u7684\u7f16\u8bd1\u5668\uff0c\u89c4\u5b9a\u4e5f\u4e0d\u4e00\u6837\uff0e
float,double\u4e5f\u662f\u4e00\u6837\u7684\uff0c\u5728\u4e0d\u540c\u7684\u7f16\u8bd1\u5668\u91cc\uff0c\u5360\u7684\u5b57\u8282\u662f\u4e0d\u4e00\u6837\u7684\uff0e

sizeof(a*b) 的结果是4,因为float占用四个字节。表达式计算后应该是什么类型的,就占用相应的字节数。比如int与float相乘,结果肯定是float型的,就是4,如果a是double型,则结果是8,如果ab都是int型,则结果是2......感觉挺有意思,亲自去试了下,就是这样的~

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