C++：键盘输入n，然后输入n个整数存入数组a，将奇数移到a的前端，要求见下。咋编？ c++.用一维数组输入n个整数,将这n个整数逆序存放
c++\u9898\u30021\u3001\u4ece\u952e\u76d8\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570n\uff0c\u5efa\u7acb\u4e00\u4e2a\u52a8\u6001\u6570\u7ec4a[n]\u3002\u4f9d\u6b21\u8f93\u5165\u8fd9n\u4e2a\u6570\u7684\u503c\uff0c\u5c06\u5176\u6392\u5e8f\u540e\u518d\u8f93\u51fa\u7ed3\u679c\u30021.
#include "iostream"
using namespace std;
int main()
{
int n,i,j,tmp;
int *p=NULL;
cin>>n;
p=new int[n];
for(i=0;i<n;i++)
cin>>p[i];
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
if(p[i]>p[j])
{
tmp=p[i];
p[i]=p[j];
p[j]=tmp;
}
cout<<"\u8f93\u5165\u6570\u636e\u4ece\u5c0f\u5230\u5927\u6392\u5e8f\u540e\u8f93\u51fa:";
for(i=0;i<n;i++)
cout<<p[i]<<" ";
cout<<endl;
delete [] p;
p=NULL;
}
\u7ed3\u679c\uff1a
2.
#include "iostream"
#include "cstring"
using namespace std;
int main()
{
char *p1="Southeast ";
char *p2="University";
char *p3=NULL;
int len=0;
len=strlen(p1)+strlen(p2)+1;
p3=new char[len];
memset(p3,0,len);
strncpy(p3,p1,strlen(p1));
strncat(p3,p2,strlen(p2));
cout<<p3<<endl;
delete [] p3;
}
\u7ed3\u679c\uff1a
#includeusing namespace std;int main(){ int i,a[10]; cout>a[i]; } cout= 0;i--) { cout<<a[i]<<" "; } cout<<endl;}
代码文本：
//#include "stdafx.h"//vc++ 6.0? Maybe should add this line.
#include <iostream>
#include "time.h"
using namespace std;
int main(int argc,char *argv[]){
int a[100],i,j,t,n;
cout << "Enter n...
";
if(cin >> n,n>100 || n<1)
n=100;
if(n>10){//n>10时自动随机输入并显示
srand((unsigned)time(NULL));
for(i=0;i<n;){
cout.width(6);//输出格式占宽6列右对齐
cout << (a[i++]=rand());
if(i%10==0 || i==n)//输出10个数或最后一行末回车
cout << endl;
}
}
else{//n<=10时手工输入显示
cout << "Please enter " << n << " integer(s)(SEP by ' ')...
";
for(i=0;i<n;cin >> a[i++]);
cout << endl;
}
for(i=0;i<n;i++){//把奇数移到a前端算法
if((a[i]&1)==0){
for(j=i+1;j<n;j++)
if(a[j]&1){//在i后找到奇数则保存至t
for(t=a[j];j>i;a[j--]=a[j-1]);//a[i]~a[j]顺序向后移一位
a[i]=t;//把a[j]拷贝到a[i];这样奇偶数的相对顺序不变
break;
}
if(j==n)//若i后无奇数了就中止外for操作
break;
}
}
cout << "OUT:
";
for(i=0;i<n;){//输出
cout.width(6);//输出格式占宽6列右对齐
cout << a[i++];
if(i%10==0 || i==n)//输出10个数或最后一行末回车
cout << endl;
}
return 0;
}
要完成把一个数组中所有的奇数移到前端的操作，实质上还是一个排序的操作。只是判断大小的情况是，如果前面的数是偶数，而后面的数是奇数，那么就交换这一对数。按这个原则进行排序，就可以了。
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