求y'要过程，准确。y=sin（1-x的平方）
y=sin(1-x^2)令u=1-x^2,原式变为y=sinu,y关于u求导得cosu,u关于x求导又得u'=-2x,根据复合函数求导法则得，y关于x的导数为y'=cos(-2x)
绛旓細A=2x²+3xy-5x+1锛 B=-x²+xy+2 (1)銆丄+2B=2x²+3xy-5x+1-2x²+2xy+4=5xy-5x+5 (2)銆5xy-5x=0锛 5x(y-1)=0锛 y=1
绛旓細姹倅=澶氬皯锛熻瑙ｉ姝ラ锛熻阿璋綖鐢卞師鏂圭▼锛1000锛1+y)^2=70(1+y)+1070 锛1锛1000锛1+y^2+2y)=70+70y+1070 1000+1000y^2+2000y=70+70y+1070 1000y^2+2000y=140+70y 100y^2+200y=14+7y 100y^2+193y-14=0 螖 = 193²+4x100x14= 42849 y1 = ( -193+鈭42849 ) / (...
绛旓細3/2=锛-4锛/x x=2 2*3+(-4)y=0 y=3/2 鎵浠=(2,2) c=(2,3/2)鎵浠鐨勮帿涓2琚牴鍙2 c鐨勮帿涓5/2 鐩稿姞涓猴紙2琚牴鍙+25/2锛
绛旓細r^2=x^2+y^2锛屼唬鍏鍜寈锛屾眰鍑簓^2锛屽啀鏍规嵁瑙掔殑璞￠檺纭畾y鐨勬璐熴
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绛旓細姹倅绛変簬澶氬皯 鎴戞潵绛 4涓洖绛 #鐑# 鍦ㄤ綘韬竟,浣犳渶娆ｈ祻鍝鎬ф牸鐨勪汉? 鍖垮悕鐢ㄦ埛 2014-12-28 灞曞紑鍏ㄩ儴 鏈洖绛旂敱鎻愰棶鑰呮帹鑽 宸茶禐杩 宸茶俯杩< 浣犲杩欎釜鍥炵瓟鐨勮瘎浠锋槸? 璇勮 鏀惰捣 鍖垮悕鐢ㄦ埛 2014-12-28 灞曞紑鍏ㄩ儴 宸茶禐杩 宸茶俯杩< 浣犲杩欎釜鍥炵瓟鐨勮瘎浠锋槸? 璇勮 鏀惰捣 鍖垮悕鐢ㄦ埛 2014-12-28 ...
绛旓細杩欏簲璇ユ槸涓涓煩褰㈠拰鐩磋涓夎褰㈢粍鎴愮殑鍥炬锛岀煩褰㈠搴旂洿瑙掕竟鐨勮竟闀挎槸6锛屾墍浠ョ煭鐩磋杈规槸6锛屽洜涓洪暱鐩磋杈规槸8锛屾牴鎹嬀鑲″畾鐞嗙畻鍑y=10銆
绛旓細鎴戜滑鍙互浣跨敤闅愬嚱鏁版眰瀵兼硶鏉ユ眰瑙ｈ繖涓棶棰樸傞鍏堬紝瀵规柟绋 x = cos(xy) 涓よ竟鍚屾椂瀵 x 姹傚锛屽埄鐢ㄩ摼寮忔硶鍒欙紝寰楀埌锛1 = (-sin(xy))(y + xy') + cos(xy)(y'x + y)鎺ヤ笅鏉ワ紝灏 y' 绉婚」锛屾暣鐞嗗緱鍒 y' 鐨勮〃杈惧紡锛歽' = (1 - cos(xy)y) / (x + sin(xy)y)杩欏氨鏄 y 瀵兼暟鐨勮〃杈惧紡锛...
绛旓細搴旂敤閰嶆柟娉曡В鏂圭▼锛屽彲寰椾袱涓В锛岃鍥剧墖鍚с
绛旓細y=1/2杩囩▼濡傚浘 璇烽噰
